Integrand size = 56, antiderivative size = 28 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=e^{-\frac {e^5}{-5-e}-8 e^{-x} x+4 x^2} \]
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\[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=\int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \left (-8+8 x+8 e^x x\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int 8 \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \left (-1+x+e^x x\right ) \, dx \\ & = 8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \left (-1+x+e^x x\right ) \, dx \\ & = 8 \int \left (-\exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right )+\exp \left (\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x+\exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x\right ) \, dx \\ & = -\left (8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \, dx\right )+8 \int \exp \left (\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x \, dx+8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x \, dx \\ & = -\left (8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \, dx\right )+8 \int \exp \left (\frac {e^{-x} \left (-40 \left (1+\frac {e}{5}\right ) x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x \, dx+8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x \, dx \\ & = -\left (8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) \, dx\right )+8 \int e^{-8 e^{-x} x+\frac {e^5+20 x^2+4 e x^2}{5+e}} x \, dx+8 \int \exp \left (-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}\right ) x \, dx \\ \end{align*}
Time = 0.98 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=e^{\frac {e^5}{5+e}-8 e^{-x} x+4 x^2} \]
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Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.43
method | result | size |
default | \({\mathrm e}^{\frac {\left (\left ({\mathrm e}^{5}+4 x^{2} {\mathrm e}+20 x^{2}\right ) {\mathrm e}^{x}-8 x \,{\mathrm e}-40 x \right ) {\mathrm e}^{-x}}{{\mathrm e}+5}}\) | \(40\) |
norman | \({\mathrm e}^{\frac {\left (\left ({\mathrm e}^{5}+4 x^{2} {\mathrm e}+20 x^{2}\right ) {\mathrm e}^{x}-8 x \,{\mathrm e}-40 x \right ) {\mathrm e}^{-x}}{{\mathrm e}+5}}\) | \(40\) |
parallelrisch | \({\mathrm e}^{\frac {\left (\left ({\mathrm e}^{5}+4 x^{2} {\mathrm e}+20 x^{2}\right ) {\mathrm e}^{x}-8 x \,{\mathrm e}-40 x \right ) {\mathrm e}^{-x}}{{\mathrm e}+5}}\) | \(40\) |
risch | \({\mathrm e}^{-\frac {\left (-20 \,{\mathrm e}^{x} x^{2}-4 x^{2} {\mathrm e}^{1+x}+8 x \,{\mathrm e}-{\mathrm e}^{5+x}+40 x \right ) {\mathrm e}^{-x}}{{\mathrm e}+5}}\) | \(45\) |
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Leaf count of result is larger than twice the leaf count of optimal. 51 vs. \(2 (23) = 46\).
Time = 0.24 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.82 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=e^{\left (x - \frac {{\left (8 \, x e - {\left (20 \, x^{2} + {\left (4 \, x^{2} - x\right )} e - 5 \, x + e^{5}\right )} e^{x} + 40 \, x\right )} e^{\left (-x\right )}}{e + 5}\right )} \]
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Time = 0.13 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.39 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=e^{\frac {\left (- 40 x - 8 e x + \left (4 e x^{2} + 20 x^{2} + e^{5}\right ) e^{x}\right ) e^{- x}}{e + 5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (23) = 46\).
Time = 0.42 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.25 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=e^{\left (\frac {4 \, x^{2} e}{e + 5} + \frac {20 \, x^{2}}{e + 5} - \frac {40 \, x e^{\left (-x\right )}}{e + 5} - \frac {8 \, x e^{\left (-x + 1\right )}}{e + 5} + \frac {e^{5}}{e + 5}\right )} \]
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\[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx=\int { 8 \, {\left (x e^{x} + x - 1\right )} e^{\left (-x - \frac {{\left (8 \, x e - {\left (4 \, x^{2} e + 20 \, x^{2} + e^{5}\right )} e^{x} + 40 \, x\right )} e^{\left (-x\right )}}{e + 5}\right )} \,d x } \]
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Time = 12.76 (sec) , antiderivative size = 67, normalized size of antiderivative = 2.39 \[ \int e^{-x+\frac {e^{-x} \left (-40 x-8 e x+e^x \left (e^5+20 x^2+4 e x^2\right )\right )}{5+e}} \left (-8+8 x+8 e^x x\right ) \, dx={\mathrm {e}}^{-\frac {8\,x\,{\mathrm {e}}^{-x}\,\mathrm {e}}{\mathrm {e}+5}}\,{\mathrm {e}}^{\frac {4\,x^2\,\mathrm {e}}{\mathrm {e}+5}}\,{\mathrm {e}}^{\frac {{\mathrm {e}}^5}{\mathrm {e}+5}}\,{\mathrm {e}}^{-\frac {40\,x\,{\mathrm {e}}^{-x}}{\mathrm {e}+5}}\,{\mathrm {e}}^{\frac {20\,x^2}{\mathrm {e}+5}} \]
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