Integrand size = 43, antiderivative size = 26 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=4 e^{2 x}-\frac {16 x^2}{\left (\frac {25-x}{3}+x\right )^2} \]
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Time = 0.09 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.116, Rules used = {6820, 12, 6874, 2225, 37} \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=4 e^{2 x}-\frac {144 x^2}{(2 x+25)^2} \]
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Rule 12
Rule 37
Rule 2225
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {8 \left (-900 x+e^{2 x} (25+2 x)^3\right )}{(25+2 x)^3} \, dx \\ & = 8 \int \frac {-900 x+e^{2 x} (25+2 x)^3}{(25+2 x)^3} \, dx \\ & = 8 \int \left (e^{2 x}-\frac {900 x}{(25+2 x)^3}\right ) \, dx \\ & = 8 \int e^{2 x} \, dx-7200 \int \frac {x}{(25+2 x)^3} \, dx \\ & = 4 e^{2 x}-\frac {144 x^2}{(25+2 x)^2} \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=8 \left (\frac {e^{2 x}}{2}-\frac {18 x^2}{(25+2 x)^2}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92
method | result | size |
risch | \(\frac {900 x +5625}{x^{2}+25 x +\frac {625}{4}}+4 \,{\mathrm e}^{2 x}\) | \(24\) |
default | \(\frac {1800}{2 x +25}-\frac {22500}{\left (2 x +25\right )^{2}}+4 \,{\mathrm e}^{2 x}\) | \(26\) |
parts | \(\frac {1800}{2 x +25}-\frac {22500}{\left (2 x +25\right )^{2}}+4 \,{\mathrm e}^{2 x}\) | \(26\) |
norman | \(\frac {3600 x +2500 \,{\mathrm e}^{2 x}+400 x \,{\mathrm e}^{2 x}+16 \,{\mathrm e}^{2 x} x^{2}+22500}{\left (2 x +25\right )^{2}}\) | \(36\) |
parallelrisch | \(\frac {64 \,{\mathrm e}^{2 x} x^{2}+90000+1600 x \,{\mathrm e}^{2 x}+10000 \,{\mathrm e}^{2 x}+14400 x}{16 x^{2}+400 x +2500}\) | \(42\) |
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none
Time = 0.23 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=\frac {4 \, {\left ({\left (4 \, x^{2} + 100 \, x + 625\right )} e^{\left (2 \, x\right )} + 900 \, x + 5625\right )}}{4 \, x^{2} + 100 \, x + 625} \]
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Time = 0.07 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.85 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=- \frac {7200 \left (- 4 x - 25\right )}{32 x^{2} + 800 x + 5000} + 4 e^{2 x} \]
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\[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=\int { \frac {8 \, {\left ({\left (8 \, x^{3} + 300 \, x^{2} + 3750 \, x + 15625\right )} e^{\left (2 \, x\right )} - 900 \, x\right )}}{8 \, x^{3} + 300 \, x^{2} + 3750 \, x + 15625} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 41 vs. \(2 (19) = 38\).
Time = 0.27 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.58 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=\frac {4 \, {\left (4 \, x^{2} e^{\left (2 \, x\right )} + 100 \, x e^{\left (2 \, x\right )} + 900 \, x + 625 \, e^{\left (2 \, x\right )} + 5625\right )}}{4 \, x^{2} + 100 \, x + 625} \]
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Time = 12.57 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-7200 x+e^{2 x} \left (125000+30000 x+2400 x^2+64 x^3\right )}{15625+3750 x+300 x^2+8 x^3} \, dx=4\,{\mathrm {e}}^{2\,x}+\frac {3600\,x+22500}{{\left (2\,x+25\right )}^2} \]
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