\(\int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx\) [6935]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 14, antiderivative size = 21 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=\frac {5 \left (-e+x+\frac {x (7-\log (x))}{4294967296}\right )}{x} \]

[Out]

5*(1/4294967296*x*(7-ln(x))+x-exp(1))/x

Rubi [A] (verified)

Time = 0.00 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.62, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {12, 45} \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5 e}{x}-\frac {5 \log (x)}{4294967296} \]

[In]

Int[(21474836480*E - 5*x)/(4294967296*x^2),x]

[Out]

(-5*E)/x - (5*Log[x])/4294967296

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {21474836480 e-5 x}{x^2} \, dx}{4294967296} \\ & = \frac {\int \left (\frac {21474836480 e}{x^2}-\frac {5}{x}\right ) \, dx}{4294967296} \\ & = -\frac {5 e}{x}-\frac {5 \log (x)}{4294967296} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.62 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5 e}{x}-\frac {5 \log (x)}{4294967296} \]

[In]

Integrate[(21474836480*E - 5*x)/(4294967296*x^2),x]

[Out]

(-5*E)/x - (5*Log[x])/4294967296

Maple [A] (verified)

Time = 0.05 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.62

method result size
default \(-\frac {5 \,{\mathrm e}}{x}-\frac {5 \ln \left (x \right )}{4294967296}\) \(13\)
norman \(-\frac {5 \,{\mathrm e}}{x}-\frac {5 \ln \left (x \right )}{4294967296}\) \(13\)
risch \(-\frac {5 \,{\mathrm e}}{x}-\frac {5 \ln \left (x \right )}{4294967296}\) \(13\)
parallelrisch \(-\frac {5 x \ln \left (x \right )+21474836480 \,{\mathrm e}}{4294967296 x}\) \(16\)

[In]

int(1/4294967296*(21474836480*exp(1)-5*x)/x^2,x,method=_RETURNVERBOSE)

[Out]

-5*exp(1)/x-5/4294967296*ln(x)

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.67 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5 \, {\left (x \log \left (x\right ) + 4294967296 \, e\right )}}{4294967296 \, x} \]

[In]

integrate(1/4294967296*(21474836480*exp(1)-5*x)/x^2,x, algorithm="fricas")

[Out]

-5/4294967296*(x*log(x) + 4294967296*e)/x

Sympy [A] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.67 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=- \frac {5 \log {\left (x \right )}}{4294967296} - \frac {5 e}{x} \]

[In]

integrate(1/4294967296*(21474836480*exp(1)-5*x)/x**2,x)

[Out]

-5*log(x)/4294967296 - 5*E/x

Maxima [A] (verification not implemented)

none

Time = 0.18 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.57 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5 \, e}{x} - \frac {5}{4294967296} \, \log \left (x\right ) \]

[In]

integrate(1/4294967296*(21474836480*exp(1)-5*x)/x^2,x, algorithm="maxima")

[Out]

-5*e/x - 5/4294967296*log(x)

Giac [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.62 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5 \, e}{x} - \frac {5}{4294967296} \, \log \left ({\left | x \right |}\right ) \]

[In]

integrate(1/4294967296*(21474836480*exp(1)-5*x)/x^2,x, algorithm="giac")

[Out]

-5*e/x - 5/4294967296*log(abs(x))

Mupad [B] (verification not implemented)

Time = 12.48 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.57 \[ \int \frac {21474836480 e-5 x}{4294967296 x^2} \, dx=-\frac {5\,\ln \left (x\right )}{4294967296}-\frac {5\,\mathrm {e}}{x} \]

[In]

int(-((5*x)/4294967296 - 5*exp(1))/x^2,x)

[Out]

- (5*log(x))/4294967296 - (5*exp(1))/x