Integrand size = 192, antiderivative size = 33 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2}{x \left (4+e^x+e^{\left (-e^x+x\right ) \left (6-x-x^2\right )}+x\right )} \]
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Timed out. \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\text {\$Aborted} \]
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Rubi steps Aborted
Time = 0.38 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.70 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2 e^{x^2+x^3}}{x \left (e^{x+x^2+x^3}+e^{6 x+e^x \left (-6+x+x^2\right )}+e^{x^2+x^3} (4+x)\right )} \]
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Time = 0.23 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82
method | result | size |
risch | \(\frac {2}{x \left (x +{\mathrm e}^{x}+{\mathrm e}^{\left (3+x \right ) \left (-2+x \right ) \left ({\mathrm e}^{x}-x \right )}+4\right )}\) | \(27\) |
parallelrisch | \(\frac {2}{x \left (x +{\mathrm e}^{x}+{\mathrm e}^{\left (x^{2}+x -6\right ) {\mathrm e}^{x}-x^{3}-x^{2}+6 x}+4\right )}\) | \(37\) |
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Time = 0.27 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.24 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2}{x^{2} + x e^{\left (-x^{3} - x^{2} + {\left (x^{2} + x - 6\right )} e^{x} + 6 \, x\right )} + x e^{x} + 4 \, x} \]
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Time = 0.19 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.09 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2}{x^{2} + x e^{x} + x e^{- x^{3} - x^{2} + 6 x + \left (x^{2} + x - 6\right ) e^{x}} + 4 x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 58 vs. \(2 (27) = 54\).
Time = 0.38 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.76 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2 \, e^{\left (x^{3} + x^{2} + 6 \, e^{x}\right )}}{{\left (x^{2} + x e^{x} + 4 \, x\right )} e^{\left (x^{3} + x^{2} + 6 \, e^{x}\right )} + x e^{\left (x^{2} e^{x} + x e^{x} + 6 \, x\right )}} \]
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Time = 0.65 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.39 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {2}{x^{2} + x e^{\left (-x^{3} + x^{2} e^{x} - x^{2} + x e^{x} + 6 \, x - 6 \, e^{x}\right )} + x e^{x} + 4 \, x} \]
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Time = 16.08 (sec) , antiderivative size = 163, normalized size of antiderivative = 4.94 \[ \int \frac {-8+e^x (-2-2 x)-4 x+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (-2-12 x+4 x^2+6 x^3+e^x \left (10 x-6 x^2-2 x^3\right )\right )}{16 x^2+e^{2 x} x^2+e^{12 x-2 x^2-2 x^3+2 e^x \left (-6+x+x^2\right )} x^2+8 x^3+x^4+e^x \left (8 x^2+2 x^3\right )+e^{6 x-x^2-x^3+e^x \left (-6+x+x^2\right )} \left (8 x^2+2 e^x x^2+2 x^3\right )} \, dx=\frac {{\mathrm {e}}^x\,\left (2\,x^4+8\,x^3+10\,x^2-30\,x\right )+x^2\,\left (6\,{\mathrm {e}}^{2\,x}-4\right )+x^3\,\left (2\,{\mathrm {e}}^{2\,x}-28\right )-x\,\left (10\,{\mathrm {e}}^{2\,x}-46\right )-6\,x^4}{x^2\,\left (x+{\mathrm {e}}^{6\,x-6\,{\mathrm {e}}^x+x^2\,{\mathrm {e}}^x+x\,{\mathrm {e}}^x-x^2-x^3}+{\mathrm {e}}^x+4\right )\,\left (3\,x\,{\mathrm {e}}^{2\,x}-5\,{\mathrm {e}}^{2\,x}-15\,{\mathrm {e}}^x-2\,x+4\,x^2\,{\mathrm {e}}^x+x^3\,{\mathrm {e}}^x+x^2\,{\mathrm {e}}^{2\,x}+5\,x\,{\mathrm {e}}^x-14\,x^2-3\,x^3+23\right )} \]
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