Integrand size = 49, antiderivative size = 22 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=\frac {5 \left (1-x-(1+8 x)^4\right )}{x+\log (x)} \]
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\[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=\int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{(x+\log (x))^2} \, dx \\ & = \int \left (\frac {5 \left (33+417 x+2432 x^2+6144 x^3+4096 x^4\right )}{(x+\log (x))^2}-\frac {5 \left (33+768 x+6144 x^2+16384 x^3\right )}{x+\log (x)}\right ) \, dx \\ & = 5 \int \frac {33+417 x+2432 x^2+6144 x^3+4096 x^4}{(x+\log (x))^2} \, dx-5 \int \frac {33+768 x+6144 x^2+16384 x^3}{x+\log (x)} \, dx \\ & = 5 \int \left (\frac {33}{(x+\log (x))^2}+\frac {417 x}{(x+\log (x))^2}+\frac {2432 x^2}{(x+\log (x))^2}+\frac {6144 x^3}{(x+\log (x))^2}+\frac {4096 x^4}{(x+\log (x))^2}\right ) \, dx-5 \int \left (\frac {33}{x+\log (x)}+\frac {768 x}{x+\log (x)}+\frac {6144 x^2}{x+\log (x)}+\frac {16384 x^3}{x+\log (x)}\right ) \, dx \\ & = 165 \int \frac {1}{(x+\log (x))^2} \, dx-165 \int \frac {1}{x+\log (x)} \, dx+2085 \int \frac {x}{(x+\log (x))^2} \, dx-3840 \int \frac {x}{x+\log (x)} \, dx+12160 \int \frac {x^2}{(x+\log (x))^2} \, dx+20480 \int \frac {x^4}{(x+\log (x))^2} \, dx+30720 \int \frac {x^3}{(x+\log (x))^2} \, dx-30720 \int \frac {x^2}{x+\log (x)} \, dx-81920 \int \frac {x^3}{x+\log (x)} \, dx \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=-\frac {5 x \left (33+384 x+2048 x^2+4096 x^3\right )}{x+\log (x)} \]
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Time = 0.80 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.14
method | result | size |
risch | \(-\frac {5 \left (4096 x^{3}+2048 x^{2}+384 x +33\right ) x}{x +\ln \left (x \right )}\) | \(25\) |
parallelrisch | \(\frac {-20480 x^{4}-10240 x^{3}-1920 x^{2}-165 x}{x +\ln \left (x \right )}\) | \(27\) |
default | \(-\frac {5 \left (4096 x^{4}+2048 x^{3}+384 x^{2}+33 x \right )}{x +\ln \left (x \right )}\) | \(28\) |
norman | \(\frac {165 \ln \left (x \right )-1920 x^{2}-10240 x^{3}-20480 x^{4}}{x +\ln \left (x \right )}\) | \(28\) |
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Time = 0.24 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=-\frac {5 \, {\left (4096 \, x^{4} + 2048 \, x^{3} + 384 \, x^{2} + 33 \, x\right )}}{x + \log \left (x\right )} \]
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Time = 0.05 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=\frac {- 20480 x^{4} - 10240 x^{3} - 1920 x^{2} - 165 x}{x + \log {\left (x \right )}} \]
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Time = 0.23 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=-\frac {5 \, {\left (4096 \, x^{4} + 2048 \, x^{3} + 384 \, x^{2} + 33 \, x\right )}}{x + \log \left (x\right )} \]
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Time = 0.29 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=-\frac {5 \, {\left (4096 \, x^{4} + 2048 \, x^{3} + 384 \, x^{2} + 33 \, x\right )}}{x + \log \left (x\right )} \]
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Time = 12.39 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {165+1920 x+8320 x^2-61440 x^4+\left (-165-3840 x-30720 x^2-81920 x^3\right ) \log (x)}{x^2+2 x \log (x)+\log ^2(x)} \, dx=-\frac {5\,x\,\left (4096\,x^3+2048\,x^2+384\,x+33\right )}{x+\ln \left (x\right )} \]
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