Integrand size = 107, antiderivative size = 24 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\frac {e}{3+e^{2 x}+x}+\log \left (\frac {3 x}{3+82 x}\right ) \]
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\[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {3 e^{4 x}+6 e^{2 x} (3+x)+3 (3+x)^2-e x (3+82 x)-2 e^{1+2 x} x (3+82 x)}{x \left (3+e^{2 x}+x\right )^2 (3+82 x)} \, dx \\ & = \int \left (-\frac {2 e}{3+e^{2 x}+x}+\frac {e (5+2 x)}{\left (3+e^{2 x}+x\right )^2}+\frac {3}{x (3+82 x)}\right ) \, dx \\ & = 3 \int \frac {1}{x (3+82 x)} \, dx+e \int \frac {5+2 x}{\left (3+e^{2 x}+x\right )^2} \, dx-(2 e) \int \frac {1}{3+e^{2 x}+x} \, dx \\ & = -\left (82 \int \frac {1}{3+82 x} \, dx\right )+e \int \left (\frac {5}{\left (3+e^{2 x}+x\right )^2}+\frac {2 x}{\left (3+e^{2 x}+x\right )^2}\right ) \, dx-(2 e) \int \frac {1}{3+e^{2 x}+x} \, dx+\int \frac {1}{x} \, dx \\ & = \log (x)-\log (3+82 x)+(2 e) \int \frac {x}{\left (3+e^{2 x}+x\right )^2} \, dx-(2 e) \int \frac {1}{3+e^{2 x}+x} \, dx+(5 e) \int \frac {1}{\left (3+e^{2 x}+x\right )^2} \, dx \\ \end{align*}
Time = 1.15 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.96 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\frac {e}{3+e^{2 x}+x}+\log (x)-\log (3+82 x) \]
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00
method | result | size |
norman | \(\frac {{\mathrm e}}{{\mathrm e}^{2 x}+3+x}-\ln \left (82 x +3\right )+\ln \left (x \right )\) | \(24\) |
risch | \(\frac {{\mathrm e}}{{\mathrm e}^{2 x}+3+x}-\ln \left (82 x +3\right )+\ln \left (x \right )\) | \(24\) |
parallelrisch | \(\frac {{\mathrm e}^{2 x} \ln \left (x \right )-\ln \left (x +\frac {3}{82}\right ) {\mathrm e}^{2 x}+x \ln \left (x \right )-\ln \left (x +\frac {3}{82}\right ) x +{\mathrm e}+3 \ln \left (x \right )-3 \ln \left (x +\frac {3}{82}\right )}{{\mathrm e}^{2 x}+3+x}\) | \(52\) |
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Time = 0.26 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.71 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=-\frac {{\left (x + e^{\left (2 \, x\right )} + 3\right )} \log \left (82 \, x + 3\right ) - {\left (x + e^{\left (2 \, x\right )} + 3\right )} \log \left (x\right ) - e}{x + e^{\left (2 \, x\right )} + 3} \]
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Time = 0.10 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.83 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\log {\left (x \right )} - \log {\left (x + \frac {3}{82} \right )} + \frac {e}{x + e^{2 x} + 3} \]
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Time = 0.25 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.96 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\frac {e}{x + e^{\left (2 \, x\right )} + 3} - \log \left (82 \, x + 3\right ) + \log \left (x\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (24) = 48\).
Time = 0.29 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.62 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\frac {x \log \left (2 \, x\right ) + e^{\left (2 \, x\right )} \log \left (2 \, x\right ) - x \log \left (82 \, x + 3\right ) - e^{\left (2 \, x\right )} \log \left (82 \, x + 3\right ) + e + 3 \, \log \left (2 \, x\right ) - 3 \, \log \left (82 \, x + 3\right )}{x + e^{\left (2 \, x\right )} + 3} \]
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Time = 13.89 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.42 \[ \int \frac {27+3 e^{4 x}+18 x+3 x^2+e \left (-3 x-82 x^2\right )+e^{2 x} \left (18+6 x+e \left (-6 x-164 x^2\right )\right )}{27 x+756 x^2+495 x^3+82 x^4+e^{4 x} \left (3 x+82 x^2\right )+e^{2 x} \left (18 x+498 x^2+164 x^3\right )} \, dx=\ln \left (x\right )-\ln \left (x+\frac {3}{82}\right )-\frac {\frac {{\mathrm {e}}^{2\,x+1}}{3}+\frac {x\,\mathrm {e}}{3}}{x+{\mathrm {e}}^{2\,x}+3} \]
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