Integrand size = 40, antiderivative size = 18 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=e^{2-\frac {x \log \left (\frac {9}{4}\right )}{3+4 x}} \]
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Time = 0.07 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.50, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.075, Rules used = {12, 27, 6838} \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=e^2 3^{-\frac {2 x}{4 x+3}} 4^{\frac {x}{4 x+3}} \]
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Rule 12
Rule 27
Rule 6838
Rubi steps \begin{align*} \text {integral}& = -\left (\left (3 \log \left (\frac {9}{4}\right )\right ) \int \frac {e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}}}{9+24 x+16 x^2} \, dx\right ) \\ & = -\left (\left (3 \log \left (\frac {9}{4}\right )\right ) \int \frac {e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}}}{(3+4 x)^2} \, dx\right ) \\ & = 3^{-\frac {2 x}{3+4 x}} 4^{\frac {x}{3+4 x}} e^2 \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(42\) vs. \(2(18)=36\).
Time = 0.15 (sec) , antiderivative size = 42, normalized size of antiderivative = 2.33 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=\frac {2^{-\frac {3+2 x}{3+4 x}} 9^{-\frac {x}{3+4 x}} e^2 \log \left (\frac {9}{4}\right )}{\log \left (\frac {3}{2}\right )} \]
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Time = 0.86 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.06
method | result | size |
gosper | \({\mathrm e}^{\frac {x \ln \left (\frac {4}{9}\right )+8 x +6}{3+4 x}}\) | \(19\) |
parallelrisch | \({\mathrm e}^{\frac {x \ln \left (\frac {4}{9}\right )+8 x +6}{3+4 x}}\) | \(19\) |
derivativedivides | \(\frac {\ln \left (\frac {4}{9}\right )^{2} {\mathrm e}^{\frac {\ln \left (\frac {4}{9}\right )}{4}+2-\frac {3 \ln \left (\frac {4}{9}\right )}{4 \left (3+4 x \right )}}}{4 \ln \left (2\right )^{2}-8 \ln \left (2\right ) \ln \left (3\right )+4 \ln \left (3\right )^{2}}\) | \(42\) |
default | \(\frac {\ln \left (\frac {4}{9}\right )^{2} {\mathrm e}^{\frac {\ln \left (\frac {4}{9}\right )}{4}+2-\frac {3 \ln \left (\frac {4}{9}\right )}{4 \left (3+4 x \right )}}}{4 \ln \left (2\right )^{2}-8 \ln \left (2\right ) \ln \left (3\right )+4 \ln \left (3\right )^{2}}\) | \(42\) |
risch | \(4^{\frac {x}{3+4 x}} \left (\frac {1}{9}\right )^{\frac {x}{3+4 x}} {\mathrm e}^{2}\) | \(45\) |
norman | \(\frac {4 x \,{\mathrm e}^{\frac {x \ln \left (\frac {4}{9}\right )+8 x +6}{3+4 x}}+3 \,{\mathrm e}^{\frac {x \ln \left (\frac {4}{9}\right )+8 x +6}{3+4 x}}}{3+4 x}\) | \(51\) |
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none
Time = 0.25 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=e^{\left (\frac {x \log \left (\frac {4}{9}\right ) + 8 \, x + 6}{4 \, x + 3}\right )} \]
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Time = 0.11 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.94 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=e^{\frac {x \log {\left (\frac {4}{9} \right )} + 8 x + 6}{4 x + 3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 44 vs. \(2 (14) = 28\).
Time = 0.30 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.44 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=-\frac {\sqrt {3} \sqrt {2} e^{\left (\frac {3 \, \log \left (3\right )}{2 \, {\left (4 \, x + 3\right )}} - \frac {3 \, \log \left (2\right )}{2 \, {\left (4 \, x + 3\right )}} + 2\right )} \log \left (\frac {4}{9}\right )}{6 \, {\left (\log \left (3\right ) - \log \left (2\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 32 vs. \(2 (14) = 28\).
Time = 0.29 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.78 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx=e^{\left (\frac {x \log \left (\frac {4}{9}\right )}{4 \, x + 3} + \frac {8 \, x}{4 \, x + 3} + \frac {6}{4 \, x + 3}\right )} \]
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Time = 0.78 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.83 \[ \int -\frac {3 e^{\frac {6+8 x-x \log \left (\frac {9}{4}\right )}{3+4 x}} \log \left (\frac {9}{4}\right )}{9+24 x+16 x^2} \, dx={\left (\frac {4}{9}\right )}^{\frac {x}{4\,x+3}}\,{\mathrm {e}}^{\frac {6}{4\,x+3}}\,{\mathrm {e}}^{\frac {8\,x}{4\,x+3}} \]
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