Integrand size = 46, antiderivative size = 21 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=3 e^{-e^{x-\frac {x^2}{3}}}-2 x \]
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\[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=\int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \int \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx \\ & = -2 x+\int e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x) \, dx \\ & = -2 x+\int e^{-e^{x-\frac {x^2}{3}}+x-\frac {x^2}{3}} (-3+2 x) \, dx \\ & = -2 x+\int \left (-3 e^{-e^{x-\frac {x^2}{3}}+x-\frac {x^2}{3}}+2 e^{-e^{x-\frac {x^2}{3}}+x-\frac {x^2}{3}} x\right ) \, dx \\ & = -2 x+2 \int e^{-e^{x-\frac {x^2}{3}}+x-\frac {x^2}{3}} x \, dx-3 \int e^{-e^{x-\frac {x^2}{3}}+x-\frac {x^2}{3}} \, dx \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=3 e^{-e^{x-\frac {x^2}{3}}}-2 x \]
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Time = 0.03 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81
method | result | size |
risch | \(3 \,{\mathrm e}^{-{\mathrm e}^{-\frac {x \left (-3+x \right )}{3}}}-2 x\) | \(17\) |
default | \({\mathrm e}^{-{\mathrm e}^{-\frac {1}{3} x^{2}+x}+\ln \left (3\right )}-2 x\) | \(19\) |
norman | \({\mathrm e}^{-{\mathrm e}^{-\frac {1}{3} x^{2}+x}+\ln \left (3\right )}-2 x\) | \(19\) |
parallelrisch | \({\mathrm e}^{-{\mathrm e}^{-\frac {1}{3} x^{2}+x}+\ln \left (3\right )}-2 x\) | \(19\) |
parts | \({\mathrm e}^{-{\mathrm e}^{-\frac {1}{3} x^{2}+x}+\ln \left (3\right )}-2 x\) | \(19\) |
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (18) = 36\).
Time = 0.24 (sec) , antiderivative size = 46, normalized size of antiderivative = 2.19 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=-{\left (2 \, x e^{\left (-\frac {1}{3} \, x^{2} + x\right )} - e^{\left (-\frac {1}{3} \, x^{2} + x - e^{\left (-\frac {1}{3} \, x^{2} + x\right )} + \log \left (3\right )\right )}\right )} e^{\left (\frac {1}{3} \, x^{2} - x\right )} \]
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Time = 0.08 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.67 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=- 2 x + 3 e^{- e^{- \frac {x^{2}}{3} + x}} \]
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Time = 0.29 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=-2 \, x + 3 \, e^{\left (-e^{\left (-\frac {1}{3} \, x^{2} + x\right )}\right )} \]
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Time = 0.31 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=-2 \, x + 3 \, e^{\left (-e^{\left (-\frac {1}{3} \, x^{2} + x\right )}\right )} \]
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Time = 0.13 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {1}{3} \left (-6+3 e^{-e^{\frac {1}{3} \left (3 x-x^2\right )}+\frac {1}{3} \left (3 x-x^2\right )} (-3+2 x)\right ) \, dx=3\,{\mathrm {e}}^{-{\mathrm {e}}^{-\frac {x^2}{3}}\,{\mathrm {e}}^x}-2\,x \]
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