Integrand size = 202, antiderivative size = 30 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=x-\frac {6-\log \left (\frac {3}{-5-e^x+x}\right )}{x^2+x^x} \]
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\[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )^2} \, dx \\ & = \int \left (1+\frac {x \left (-6+\log \left (-\frac {3}{5+e^x-x}\right )\right ) (-2+x+x \log (x))}{\left (x^2+x^x\right )^2}-\frac {-31-5 e^x+6 x+5 \log \left (-\frac {3}{5+e^x-x}\right )+e^x \log \left (-\frac {3}{5+e^x-x}\right )-x \log \left (-\frac {3}{5+e^x-x}\right )-30 \log (x)-6 e^x \log (x)+6 x \log (x)+5 \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)+e^x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)-x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}\right ) \, dx \\ & = x+\int \frac {x \left (-6+\log \left (-\frac {3}{5+e^x-x}\right )\right ) (-2+x+x \log (x))}{\left (x^2+x^x\right )^2} \, dx-\int \frac {-31-5 e^x+6 x+5 \log \left (-\frac {3}{5+e^x-x}\right )+e^x \log \left (-\frac {3}{5+e^x-x}\right )-x \log \left (-\frac {3}{5+e^x-x}\right )-30 \log (x)-6 e^x \log (x)+6 x \log (x)+5 \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)+e^x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)-x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx \\ & = x+\int \left (\frac {12 x}{\left (x^2+x^x\right )^2}-\frac {6 x^2}{\left (x^2+x^x\right )^2}-\frac {2 x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (x^2+x^x\right )^2}+\frac {x^2 \log \left (-\frac {3}{5+e^x-x}\right )}{\left (x^2+x^x\right )^2}-\frac {6 x^2 \log (x)}{\left (x^2+x^x\right )^2}+\frac {x^2 \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (x^2+x^x\right )^2}\right ) \, dx-\int \frac {-31-5 e^x+6 x-6 \left (5+e^x-x\right ) \log (x)+\left (5+e^x-x\right ) \log \left (-\frac {3}{5+e^x-x}\right ) (1+\log (x))}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx \\ & = x-2 \int \frac {x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (x^2+x^x\right )^2} \, dx-6 \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx-6 \int \frac {x^2 \log (x)}{\left (x^2+x^x\right )^2} \, dx+12 \int \frac {x}{\left (x^2+x^x\right )^2} \, dx+\int \frac {x^2 \log \left (-\frac {3}{5+e^x-x}\right )}{\left (x^2+x^x\right )^2} \, dx+\int \frac {x^2 \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (x^2+x^x\right )^2} \, dx-\int \left (-\frac {31}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}-\frac {5 e^x}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {6 x}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {5 \log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {e^x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}-\frac {x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}-\frac {30 \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}-\frac {6 e^x \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {6 x \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {5 \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}+\frac {e^x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}-\frac {x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )}\right ) \, dx \\ & = x+2 \int \frac {\left (-1+e^x\right ) \left (-5-e^x+x\right ) \int \frac {x}{\left (x^2+x^x\right )^2} \, dx}{\left (5+e^x-x\right )^2} \, dx+5 \int \frac {e^x}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-5 \int \frac {\log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-5 \int \frac {\log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-6 \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx-6 \int \frac {x}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+6 \int \frac {e^x \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-6 \int \frac {x \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+6 \int \frac {\int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx}{x} \, dx+12 \int \frac {x}{\left (x^2+x^x\right )^2} \, dx+30 \int \frac {\log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+31 \int \frac {1}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+\log \left (-\frac {3}{5+e^x-x}\right ) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx-\left (2 \log \left (-\frac {3}{5+e^x-x}\right )\right ) \int \frac {x}{\left (x^2+x^x\right )^2} \, dx-(6 \log (x)) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx+\left (\log \left (-\frac {3}{5+e^x-x}\right ) \log (x)\right ) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx-\int \frac {e^x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+\int \frac {x \log \left (-\frac {3}{5+e^x-x}\right )}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-\int \frac {e^x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx+\int \frac {x \log \left (-\frac {3}{5+e^x-x}\right ) \log (x)}{\left (5+e^x-x\right ) \left (x^2+x^x\right )} \, dx-\int \frac {\left (-1+e^x\right ) \left (-5-e^x+x\right ) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx}{\left (5+e^x-x\right )^2} \, dx-\int \frac {\log \left (-\frac {3}{5+e^x-x}\right ) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx}{x} \, dx-\int \frac {\left (-1+e^x\right ) \left (-5-e^x+x\right ) \log (x) \int \frac {x^2}{\left (x^2+x^x\right )^2} \, dx}{\left (5+e^x-x\right )^2} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.10 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\frac {-6+x^3+x^{1+x}+\log \left (-\frac {3}{5+e^x-x}\right )}{x^2+x^x} \]
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Time = 32.08 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.63
method | result | size |
risch | \(-\frac {\ln \left (-{\mathrm e}^{x}+x -5\right )}{x^{2}+x^{x}}+\frac {-12+2 x^{3}+2 x^{x} x +2 \ln \left (3\right )}{2 x^{2}+2 x^{x}}\) | \(49\) |
parallelrisch | \(\frac {-12+2 x^{3}+10 x^{2}+2 \,{\mathrm e}^{x \ln \left (x \right )} x +10 \,{\mathrm e}^{x \ln \left (x \right )}+2 \ln \left (-\frac {3}{{\mathrm e}^{x}+5-x}\right )}{2 x^{2}+2 \,{\mathrm e}^{x \ln \left (x \right )}}\) | \(55\) |
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Time = 0.26 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\frac {x^{3} + x x^{x} + \log \left (\frac {3}{x - e^{x} - 5}\right ) - 6}{x^{2} + x^{x}} \]
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Time = 0.71 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.13 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=x + \frac {\log {\left (- \frac {3}{- x + e^{x} + 5} \right )}}{x^{2} + e^{x \log {\left (x \right )}}} - \frac {6}{x^{2} + e^{x \log {\left (x \right )}}} \]
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Time = 0.33 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\frac {x^{3} + x x^{x} + \log \left (3\right ) - \log \left (x - e^{x} - 5\right ) - 6}{x^{2} + x^{x}} \]
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Timed out. \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\text {Timed out} \]
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Time = 13.33 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07 \[ \int \frac {60 x-11 x^2+5 x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+e^x \left (12 x-x^2+x^4\right )+x^x \left (31-6 x+10 x^2-2 x^3+e^x \left (5+2 x^2\right )+\left (30+6 e^x-6 x\right ) \log (x)\right )+\log \left (-\frac {3}{5+e^x-x}\right ) \left (-10 x-2 e^x x+2 x^2+x^x \left (-5-e^x+x+\left (-5-e^x+x\right ) \log (x)\right )\right )}{5 x^4+e^x x^4-x^5+\left (5+e^x-x\right ) x^{2 x}+x^x \left (10 x^2+2 e^x x^2-2 x^3\right )} \, dx=\frac {\ln \left (-\frac {3}{{\mathrm {e}}^x-x+5}\right )+x\,x^x+x^3-6}{x^x+x^2} \]
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