Integrand size = 5, antiderivative size = 16 \[ \int (-9+10 x) \, dx=x+5 \left (4-2 x+x^2+\log ^2(3)\right ) \]
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Time = 0.00 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.56, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int (-9+10 x) \, dx=5 x^2-9 x \]
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Rubi steps \begin{align*} \text {integral}& = -9 x+5 x^2 \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.56 \[ \int (-9+10 x) \, dx=-9 x+5 x^2 \]
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Time = 0.01 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.62
method | result | size |
gosper | \(5 x^{2}-9 x\) | \(10\) |
default | \(5 x^{2}-9 x\) | \(10\) |
norman | \(5 x^{2}-9 x\) | \(10\) |
risch | \(5 x^{2}-9 x\) | \(10\) |
parallelrisch | \(5 x^{2}-9 x\) | \(10\) |
parts | \(5 x^{2}-9 x\) | \(10\) |
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none
Time = 0.23 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.56 \[ \int (-9+10 x) \, dx=5 \, x^{2} - 9 \, x \]
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Time = 0.02 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.44 \[ \int (-9+10 x) \, dx=5 x^{2} - 9 x \]
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none
Time = 0.21 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.56 \[ \int (-9+10 x) \, dx=5 \, x^{2} - 9 \, x \]
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none
Time = 0.27 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.56 \[ \int (-9+10 x) \, dx=5 \, x^{2} - 9 \, x \]
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Time = 0.03 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.44 \[ \int (-9+10 x) \, dx=x\,\left (5\,x-9\right ) \]
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