Integrand size = 191, antiderivative size = 29 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=1+\frac {\left (-1+e^{5 x}\right ) x}{\log \left (\frac {x}{-2-\log (-x+\log (x))}\right )} \]
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\[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1+x-e^{5 x} (1+x)+2 \left (-1+e^{5 x}\right ) \log (x)-\left (-1+e^{5 x}\right ) (x-\log (x)) \log (-x+\log (x))+\left (-1+e^{5 x} (1+5 x)\right ) (x-\log (x)) (2+\log (-x+\log (x))) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx \\ & = \int \left (\frac {1}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}+\frac {x}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}-\frac {2 \log (x)}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}+\frac {\log (-x+\log (x))}{(2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}-\frac {1}{\log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}+\frac {e^{5 x} \left (-1-x+2 \log (x)-x \log (-x+\log (x))+\log (x) \log (-x+\log (x))+2 x \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+10 x^2 \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-2 \log (x) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-10 x \log (x) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+x \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+5 x^2 \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-\log (x) \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-5 x \log (x) \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )\right )}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}\right ) \, dx \\ & = -\left (2 \int \frac {\log (x)}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx\right )+\int \frac {1}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {x}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {\log (-x+\log (x))}{(2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx-\int \frac {1}{\log \left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {e^{5 x} \left (-1-x+2 \log (x)-x \log (-x+\log (x))+\log (x) \log (-x+\log (x))+2 x \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+10 x^2 \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-2 \log (x) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-10 x \log (x) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+x \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+5 x^2 \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-\log (x) \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-5 x \log (x) \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )\right )}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx \\ & = \frac {e^{5 x} \left (2 x^2 \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-2 x \log (x) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )+x^2 \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )-x \log (x) \log (-x+\log (x)) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )\right )}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )}-2 \int \frac {\log (x)}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {1}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {x}{(x-\log (x)) (2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx+\int \frac {\log (-x+\log (x))}{(2+\log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx-\int \frac {1}{\log \left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.90 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\frac {\left (-1+e^{5 x}\right ) x}{\log \left (-\frac {x}{2+\log (-x+\log (x))}\right )} \]
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Time = 281.93 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07
method | result | size |
parallelrisch | \(-\frac {-8 x \,{\mathrm e}^{5 x}+8 x}{8 \ln \left (-\frac {x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )}\) | \(31\) |
risch | \(-\frac {2 i x \left ({\mathrm e}^{5 x}-1\right )}{-2 \pi \operatorname {csgn}\left (\frac {i x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )^{2}-\pi \,\operatorname {csgn}\left (\frac {i}{\ln \left (\ln \left (x \right )-x \right )+2}\right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )+\pi \,\operatorname {csgn}\left (\frac {i}{\ln \left (\ln \left (x \right )-x \right )+2}\right ) \operatorname {csgn}\left (\frac {i x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )^{2}+\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (\frac {i x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )^{2}+\pi \operatorname {csgn}\left (\frac {i x}{\ln \left (\ln \left (x \right )-x \right )+2}\right )^{3}+2 \pi +2 i \ln \left (\ln \left (\ln \left (x \right )-x \right )+2\right )-2 i \ln \left (x \right )}\) | \(175\) |
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\frac {x e^{\left (5 \, x\right )} - x}{\log \left (-\frac {x}{\log \left (-x + \log \left (x\right )\right ) + 2}\right )} \]
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Time = 4.21 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.17 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\frac {x e^{5 x}}{\log {\left (- \frac {x}{\log {\left (- x + \log {\left (x \right )} \right )} + 2} \right )}} - \frac {x}{\log {\left (- \frac {x}{\log {\left (- x + \log {\left (x \right )} \right )} + 2} \right )}} \]
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Time = 0.26 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.03 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\frac {x e^{\left (5 \, x\right )} - x}{\log \left (x\right ) - \log \left (-\log \left (-x + \log \left (x\right )\right ) - 2\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1672 vs. \(2 (27) = 54\).
Time = 1.35 (sec) , antiderivative size = 1672, normalized size of antiderivative = 57.66 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx=\text {Too large to display} \]
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Time = 13.92 (sec) , antiderivative size = 266, normalized size of antiderivative = 9.17 \[ \int \frac {-1-x+e^{5 x} (1+x)+\left (2-2 e^{5 x}\right ) \log (x)+\left (-x+e^{5 x} x+\left (1-e^{5 x}\right ) \log (x)\right ) \log (-x+\log (x))+\left (2 x+e^{5 x} \left (-2 x-10 x^2\right )+\left (-2+e^{5 x} (2+10 x)\right ) \log (x)+\left (x+e^{5 x} \left (-x-5 x^2\right )+\left (-1+e^{5 x} (1+5 x)\right ) \log (x)\right ) \log (-x+\log (x))\right ) \log \left (-\frac {x}{2+\log (-x+\log (x))}\right )}{(-2 x+2 \log (x)+(-x+\log (x)) \log (-x+\log (x))) \log ^2\left (-\frac {x}{2+\log (-x+\log (x))}\right )} \, dx={\mathrm {e}}^{5\,x}\,\left (5\,x^2+x\right )-x+\frac {x\,\left ({\mathrm {e}}^{5\,x}-1\right )-\frac {x\,\ln \left (-\frac {x}{\ln \left (\ln \left (x\right )-x\right )+2}\right )\,\left (x-\ln \left (x\right )\right )\,\left (\ln \left (\ln \left (x\right )-x\right )+2\right )\,\left ({\mathrm {e}}^{5\,x}+5\,x\,{\mathrm {e}}^{5\,x}-1\right )}{x-2\,\ln \left (x\right )+x\,\ln \left (\ln \left (x\right )-x\right )-\ln \left (\ln \left (x\right )-x\right )\,\ln \left (x\right )+1}}{\ln \left (-\frac {x}{\ln \left (\ln \left (x\right )-x\right )+2}\right )}-\frac {x^3\,\ln \left (x\right )-x^2\,\ln \left (x\right )+x^2\,{\mathrm {e}}^{5\,x}+x^3\,{\mathrm {e}}^{5\,x}-16\,x^4\,{\mathrm {e}}^{5\,x}+19\,x^5\,{\mathrm {e}}^{5\,x}-5\,x^6\,{\mathrm {e}}^{5\,x}-x^2+4\,x^3-4\,x^4+x^5+x^2\,{\mathrm {e}}^{5\,x}\,\ln \left (x\right )+4\,x^3\,{\mathrm {e}}^{5\,x}\,\ln \left (x\right )-5\,x^4\,{\mathrm {e}}^{5\,x}\,\ln \left (x\right )}{\left (x-2\,\ln \left (x\right )+\ln \left (\ln \left (x\right )-x\right )\,\left (x-\ln \left (x\right )\right )+1\right )\,\left (x+x\,\ln \left (x\right )-3\,x^2+x^3\right )} \]
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