Integrand size = 52, antiderivative size = 22 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=e^{-2 x-\frac {2 x}{5-\frac {55 x}{4}}} x^2 \]
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\[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=\int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{5 (-4+11 x)^2} \, dx \\ & = \frac {1}{5} \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{(-4+11 x)^2} \, dx \\ & = \frac {1}{5} \int \frac {e^{-\frac {2 x (-24+55 x)}{-20+55 x}} x \left (160-1072 x+2090 x^2-1210 x^3\right )}{(4-11 x)^2} \, dx \\ & = \frac {1}{5} \int \left (-\frac {32}{121} e^{-\frac {2 x (-24+55 x)}{-20+55 x}}+10 e^{-\frac {2 x (-24+55 x)}{-20+55 x}} x-10 e^{-\frac {2 x (-24+55 x)}{-20+55 x}} x^2-\frac {512 e^{-\frac {2 x (-24+55 x)}{-20+55 x}}}{121 (-4+11 x)^2}-\frac {256 e^{-\frac {2 x (-24+55 x)}{-20+55 x}}}{121 (-4+11 x)}\right ) \, dx \\ & = -\left (\frac {32}{605} \int e^{-\frac {2 x (-24+55 x)}{-20+55 x}} \, dx\right )-\frac {256}{605} \int \frac {e^{-\frac {2 x (-24+55 x)}{-20+55 x}}}{-4+11 x} \, dx-\frac {512}{605} \int \frac {e^{-\frac {2 x (-24+55 x)}{-20+55 x}}}{(-4+11 x)^2} \, dx+2 \int e^{-\frac {2 x (-24+55 x)}{-20+55 x}} x \, dx-2 \int e^{-\frac {2 x (-24+55 x)}{-20+55 x}} x^2 \, dx \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=e^{\frac {2 (24-55 x) x}{-20+55 x}} x^2 \]
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Time = 0.55 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95
method | result | size |
risch | \(x^{2} {\mathrm e}^{-\frac {2 x \left (55 x -24\right )}{5 \left (11 x -4\right )}}\) | \(21\) |
gosper | \(x^{2} {\mathrm e}^{-\frac {2 x \left (55 x -24\right )}{5 \left (11 x -4\right )}}\) | \(23\) |
norman | \(\frac {\left (11 x^{3}-4 x^{2}\right ) {\mathrm e}^{-\frac {2 \left (55 x^{2}-24 x \right )}{55 x -20}}}{11 x -4}\) | \(40\) |
parallelrisch | \(\frac {\left (805255 x^{3}-292820 x^{2}\right ) {\mathrm e}^{-\frac {2 \left (55 x^{2}-24 x \right )}{5 \left (11 x -4\right )}}}{805255 x -292820}\) | \(42\) |
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Time = 0.26 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=x^{2} e^{\left (-\frac {2 \, {\left (55 \, x^{2} - 24 \, x\right )}}{5 \, {\left (11 \, x - 4\right )}}\right )} \]
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Time = 0.09 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.77 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=x^{2} e^{- \frac {2 \cdot \left (55 x^{2} - 24 x\right )}{55 x - 20}} \]
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Time = 0.28 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=x^{2} e^{\left (-2 \, x + \frac {32}{55 \, {\left (11 \, x - 4\right )}} + \frac {8}{55}\right )} \]
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Time = 0.31 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=x^{2} e^{\left (-\frac {2 \, {\left (55 \, x^{2} - 24 \, x\right )}}{5 \, {\left (11 \, x - 4\right )}}\right )} \]
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Time = 13.65 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.27 \[ \int \frac {e^{-\frac {2 \left (-24 x+55 x^2\right )}{-20+55 x}} \left (160 x-1072 x^2+2090 x^3-1210 x^4\right )}{80-440 x+605 x^2} \, dx=x^2\,{\mathrm {e}}^{-\frac {22\,x^2}{11\,x-4}}\,{\mathrm {e}}^{\frac {48\,x}{55\,x-20}} \]
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