Integrand size = 182, antiderivative size = 28 \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\log \left (-1+\frac {x-\log (x)}{e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )}\right ) \]
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Time = 2.50 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.50, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.027, Rules used = {6820, 6857, 6816, 6828, 209} \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\log \left (\log ^2\left (12 \left (9 x^2+4\right )\right )-x+\log (x)+e^4\right )-\log \left (\log ^2\left (12 \left (9 x^2+4\right )\right )+e^4\right ) \]
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Rule 209
Rule 6816
Rule 6820
Rule 6828
Rule 6857
Rubi steps \begin{align*} \text {integral}& = \int \frac {-e^4 \left (-4+4 x-9 x^2+9 x^3\right )+36 x^2 (x-\log (x)) \log \left (12 \left (4+9 x^2\right )\right )-\left (-4+4 x-9 x^2+9 x^3\right ) \log ^2\left (12 \left (4+9 x^2\right )\right )}{x \left (4+9 x^2\right ) \left (e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )\right ) \left (e^4-x+\log (x)+\log ^2\left (12 \left (4+9 x^2\right )\right )\right )} \, dx \\ & = \int \left (\frac {-4+4 x-9 x^2+9 x^3-36 x^2 \log \left (12 \left (4+9 x^2\right )\right )}{x \left (4+9 x^2\right ) \left (-e^4+x-\log (x)-\log ^2\left (12 \left (4+9 x^2\right )\right )\right )}+\frac {36 x \log \left (48+108 x^2\right )}{\left (-4-9 x^2\right ) \left (e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )\right )}\right ) \, dx \\ & = 36 \int \frac {x \log \left (48+108 x^2\right )}{\left (-4-9 x^2\right ) \left (e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )\right )} \, dx+\int \frac {-4+4 x-9 x^2+9 x^3-36 x^2 \log \left (12 \left (4+9 x^2\right )\right )}{x \left (4+9 x^2\right ) \left (-e^4+x-\log (x)-\log ^2\left (12 \left (4+9 x^2\right )\right )\right )} \, dx \\ & = -\log \left (e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )\right )+\log \left (e^4-x+\log (x)+\log ^2\left (12 \left (4+9 x^2\right )\right )\right ) \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.50 \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=-\log \left (e^4+\log ^2\left (12 \left (4+9 x^2\right )\right )\right )+\log \left (e^4-x+\log (x)+\log ^2\left (12 \left (4+9 x^2\right )\right )\right ) \]
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Time = 30.79 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.32
method | result | size |
risch | \(\ln \left (\ln \left (108 x^{2}+48\right )^{2}+{\mathrm e}^{4}-x +\ln \left (x \right )\right )-\ln \left (\ln \left (108 x^{2}+48\right )^{2}+{\mathrm e}^{4}\right )\) | \(37\) |
parallelrisch | \(-\ln \left (\ln \left (108 x^{2}+48\right )^{2}+{\mathrm e}^{4}\right )+\ln \left (-\ln \left (108 x^{2}+48\right )^{2}-{\mathrm e}^{4}+x -\ln \left (x \right )\right )\) | \(41\) |
default | \(-\ln \left (\ln \left (9 x^{2}+4\right )^{2}+\left (2 \ln \left (3\right )+4 \ln \left (2\right )\right ) \ln \left (9 x^{2}+4\right )+\ln \left (3\right )^{2}+4 \ln \left (2\right ) \ln \left (3\right )+4 \ln \left (2\right )^{2}+{\mathrm e}^{4}\right )+\ln \left (\ln \left (9 x^{2}+4\right )^{2}+\left (2 \ln \left (3\right )+4 \ln \left (2\right )\right ) \ln \left (9 x^{2}+4\right )+\ln \left (3\right )^{2}+4 \ln \left (2\right ) \ln \left (3\right )+4 \ln \left (2\right )^{2}+{\mathrm e}^{4}+\ln \left (x \right )-x \right )\) | \(105\) |
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Time = 0.37 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.29 \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\log \left (\log \left (108 \, x^{2} + 48\right )^{2} - x + e^{4} + \log \left (x\right )\right ) - \log \left (\log \left (108 \, x^{2} + 48\right )^{2} + e^{4}\right ) \]
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Exception generated. \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\text {Exception raised: PolynomialError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 102 vs. \(2 (25) = 50\).
Time = 0.34 (sec) , antiderivative size = 102, normalized size of antiderivative = 3.64 \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\log \left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2} + 2 \, {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (9 \, x^{2} + 4\right ) + \log \left (9 \, x^{2} + 4\right )^{2} - x + e^{4} + \log \left (x\right )\right ) - \log \left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2} + 2 \, {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (9 \, x^{2} + 4\right ) + \log \left (9 \, x^{2} + 4\right )^{2} + e^{4}\right ) \]
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Time = 0.97 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.29 \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=\log \left (\log \left (108 \, x^{2} + 48\right )^{2} - x + e^{4} + \log \left (x\right )\right ) - \log \left (\log \left (108 \, x^{2} + 48\right )^{2} + e^{4}\right ) \]
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Timed out. \[ \int \frac {e^4 \left (4-4 x+9 x^2-9 x^3\right )+\left (36 x^3-36 x^2 \log (x)\right ) \log \left (48+108 x^2\right )+\left (4-4 x+9 x^2-9 x^3\right ) \log ^2\left (48+108 x^2\right )}{e^8 \left (4 x+9 x^3\right )+e^4 \left (-4 x^2-9 x^4\right )+e^4 \left (4 x+9 x^3\right ) \log (x)+\left (-4 x^2-9 x^4+e^4 \left (8 x+18 x^3\right )+\left (4 x+9 x^3\right ) \log (x)\right ) \log ^2\left (48+108 x^2\right )+\left (4 x+9 x^3\right ) \log ^4\left (48+108 x^2\right )} \, dx=-\int \frac {\left (9\,x^3-9\,x^2+4\,x-4\right )\,{\ln \left (108\,x^2+48\right )}^2+\left (36\,x^2\,\ln \left (x\right )-36\,x^3\right )\,\ln \left (108\,x^2+48\right )+{\mathrm {e}}^4\,\left (9\,x^3-9\,x^2+4\,x-4\right )}{\left (9\,x^3+4\,x\right )\,{\ln \left (108\,x^2+48\right )}^4+\left ({\mathrm {e}}^4\,\left (18\,x^3+8\,x\right )+\ln \left (x\right )\,\left (9\,x^3+4\,x\right )-4\,x^2-9\,x^4\right )\,{\ln \left (108\,x^2+48\right )}^2+{\mathrm {e}}^8\,\left (9\,x^3+4\,x\right )-{\mathrm {e}}^4\,\left (9\,x^4+4\,x^2\right )+{\mathrm {e}}^4\,\ln \left (x\right )\,\left (9\,x^3+4\,x\right )} \,d x \]
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