Integrand size = 63, antiderivative size = 26 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {1}{5} x^2 \left (-2+2 x^3+\frac {-1+x^2}{\log (5)}\right )^2 \]
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Leaf count is larger than twice the leaf count of optimal. \(99\) vs. \(2(26)=52\).
Time = 0.02 (sec) , antiderivative size = 99, normalized size of antiderivative = 3.81, number of steps used = 4, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.016, Rules used = {12} \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {4 x^8}{5}+\frac {4 x^7}{5 \log (5)}+\frac {x^6}{5 \log ^2(5)}-\frac {8 x^5}{5}-\frac {4 x^5}{5 \log (5)}-\frac {2 x^4}{5 \log ^2(5)}-\frac {4 x^4}{5 \log (5)}+\frac {4 x^2}{5}+\frac {x^2}{5 \log ^2(5)}+\frac {4 x^2}{5 \log (5)} \]
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Rule 12
Rubi steps \begin{align*} \text {integral}& = \frac {\int \left (2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)\right ) \, dx}{5 \log ^2(5)} \\ & = \frac {x^2}{5 \log ^2(5)}-\frac {2 x^4}{5 \log ^2(5)}+\frac {x^6}{5 \log ^2(5)}+\frac {1}{5} \int \left (8 x-40 x^4+32 x^7\right ) \, dx+\frac {\int \left (8 x-16 x^3-20 x^4+28 x^6\right ) \, dx}{5 \log (5)} \\ & = \frac {4 x^2}{5}-\frac {8 x^5}{5}+\frac {4 x^8}{5}+\frac {x^2}{5 \log ^2(5)}-\frac {2 x^4}{5 \log ^2(5)}+\frac {x^6}{5 \log ^2(5)}+\frac {4 x^2}{5 \log (5)}-\frac {4 x^4}{5 \log (5)}-\frac {4 x^5}{5 \log (5)}+\frac {4 x^7}{5 \log (5)} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.08 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {x^2 \left (-1+x^2-\log (25)+x^3 \log (25)\right )^2}{5 \log ^2(5)} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(62\) vs. \(2(24)=48\).
Time = 0.13 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.42
method | result | size |
default | \(\frac {4 x^{8} \ln \left (5\right )^{2}+4 x^{7} \ln \left (5\right )+x^{6}+4 \left (-2 \ln \left (5\right )-1\right ) \ln \left (5\right ) x^{5}+\frac {\left (-8 \ln \left (5\right )-4\right ) x^{4}}{2}+\left (-2 \ln \left (5\right )-1\right )^{2} x^{2}}{5 \ln \left (5\right )^{2}}\) | \(63\) |
norman | \(\frac {\left (-\frac {8 \ln \left (5\right )}{5}-\frac {4}{5}\right ) x^{5}+\frac {4 x^{7}}{5}+\frac {4 x^{8} \ln \left (5\right )}{5}+\frac {x^{6}}{5 \ln \left (5\right )}-\frac {2 \left (2 \ln \left (5\right )+1\right ) x^{4}}{5 \ln \left (5\right )}+\frac {\left (4 \ln \left (5\right )^{2}+4 \ln \left (5\right )+1\right ) x^{2}}{5 \ln \left (5\right )}}{\ln \left (5\right )}\) | \(74\) |
parallelrisch | \(\frac {4 x^{8} \ln \left (5\right )^{2}+4 x^{7} \ln \left (5\right )-8 x^{5} \ln \left (5\right )^{2}-4 x^{5} \ln \left (5\right )+x^{6}-4 x^{4} \ln \left (5\right )+4 x^{2} \ln \left (5\right )^{2}-2 x^{4}+4 x^{2} \ln \left (5\right )+x^{2}}{5 \ln \left (5\right )^{2}}\) | \(74\) |
risch | \(\frac {4 x^{8}}{5}+\frac {4 x^{7}}{5 \ln \left (5\right )}+\frac {x^{6}}{5 \ln \left (5\right )^{2}}-\frac {8 x^{5}}{5}-\frac {4 x^{5}}{5 \ln \left (5\right )}-\frac {4 x^{4}}{5 \ln \left (5\right )}-\frac {2 x^{4}}{5 \ln \left (5\right )^{2}}+\frac {4 x^{2}}{5}+\frac {4 x^{2}}{5 \ln \left (5\right )}+\frac {x^{2}}{5 \ln \left (5\right )^{2}}\) | \(80\) |
gosper | \(\frac {\left (-1+x \right ) \left (4 x^{5} \ln \left (5\right )^{2}+4 x^{4} \ln \left (5\right )^{2}+4 x^{3} \ln \left (5\right )^{2}+4 x^{4} \ln \left (5\right )-4 x^{2} \ln \left (5\right )^{2}+4 x^{3} \ln \left (5\right )-4 x \ln \left (5\right )^{2}+x^{3}-4 \ln \left (5\right )^{2}-4 x \ln \left (5\right )+x^{2}-4 \ln \left (5\right )-x -1\right ) x^{2}}{5 \ln \left (5\right )^{2}}\) | \(96\) |
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (24) = 48\).
Time = 0.27 (sec) , antiderivative size = 57, normalized size of antiderivative = 2.19 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {x^{6} - 2 \, x^{4} + 4 \, {\left (x^{8} - 2 \, x^{5} + x^{2}\right )} \log \left (5\right )^{2} + x^{2} + 4 \, {\left (x^{7} - x^{5} - x^{4} + x^{2}\right )} \log \left (5\right )}{5 \, \log \left (5\right )^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 85 vs. \(2 (20) = 40\).
Time = 0.03 (sec) , antiderivative size = 85, normalized size of antiderivative = 3.27 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {4 x^{8}}{5} + \frac {4 x^{7}}{5 \log {\left (5 \right )}} + \frac {x^{6}}{5 \log {\left (5 \right )}^{2}} + \frac {x^{5} \left (- 8 \log {\left (5 \right )} - 4\right )}{5 \log {\left (5 \right )}} + \frac {x^{4} \left (- 4 \log {\left (5 \right )} - 2\right )}{5 \log {\left (5 \right )}^{2}} + \frac {x^{2} \cdot \left (1 + 4 \log {\left (5 \right )} + 4 \log {\left (5 \right )}^{2}\right )}{5 \log {\left (5 \right )}^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (24) = 48\).
Time = 0.18 (sec) , antiderivative size = 57, normalized size of antiderivative = 2.19 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {x^{6} - 2 \, x^{4} + 4 \, {\left (x^{8} - 2 \, x^{5} + x^{2}\right )} \log \left (5\right )^{2} + x^{2} + 4 \, {\left (x^{7} - x^{5} - x^{4} + x^{2}\right )} \log \left (5\right )}{5 \, \log \left (5\right )^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (24) = 48\).
Time = 0.28 (sec) , antiderivative size = 57, normalized size of antiderivative = 2.19 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {x^{6} - 2 \, x^{4} + 4 \, {\left (x^{8} - 2 \, x^{5} + x^{2}\right )} \log \left (5\right )^{2} + x^{2} + 4 \, {\left (x^{7} - x^{5} - x^{4} + x^{2}\right )} \log \left (5\right )}{5 \, \log \left (5\right )^{2}} \]
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Time = 14.85 (sec) , antiderivative size = 80, normalized size of antiderivative = 3.08 \[ \int \frac {2 x-8 x^3+6 x^5+\left (8 x-16 x^3-20 x^4+28 x^6\right ) \log (5)+\left (8 x-40 x^4+32 x^7\right ) \log ^2(5)}{5 \log ^2(5)} \, dx=\frac {4\,x^8}{5}+\frac {4\,x^7}{5\,\ln \left (5\right )}+\frac {x^6}{5\,{\ln \left (5\right )}^2}-\frac {\left (20\,\ln \left (5\right )+40\,{\ln \left (5\right )}^2\right )\,x^5}{25\,{\ln \left (5\right )}^2}-\frac {\left (16\,\ln \left (5\right )+8\right )\,x^4}{20\,{\ln \left (5\right )}^2}+\frac {\left (8\,\ln \left (5\right )+8\,{\ln \left (5\right )}^2+2\right )\,x^2}{10\,{\ln \left (5\right )}^2} \]
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