Integrand size = 74, antiderivative size = 28 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 e^{4+\frac {x+\frac {2}{(3-x) (1+x)}}{2+x}} \]
[Out]
\[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=\int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{\left (6+7 x-x^3\right )^2} \, dx \\ & = \int \left (\frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{5 (-3+x)^2}-\frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{(1+x)^2}+\frac {24 e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{5 (2+x)^2}\right ) \, dx \\ & = \frac {1}{5} \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{(-3+x)^2} \, dx+\frac {24}{5} \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{(2+x)^2} \, dx-\int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}}}{(1+x)^2} \, dx \\ \end{align*}
Time = 1.80 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 e^{5-\frac {2 \left (-2-2 x+x^2\right )}{-6-7 x+x^3}} \]
[In]
[Out]
Time = 0.26 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07
method | result | size |
gosper | \(2 \,{\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{x^{3}-7 x -6}}\) | \(30\) |
parallelrisch | \(2 \,{\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{x^{3}-7 x -6}}\) | \(30\) |
risch | \(2 \,{\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{\left (-3+x \right ) \left (2+x \right ) \left (1+x \right )}}\) | \(35\) |
norman | \(\frac {-14 x \,{\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{x^{3}-7 x -6}}+2 x^{3} {\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{x^{3}-7 x -6}}-12 \,{\mathrm e}^{\frac {5 x^{3}-2 x^{2}-31 x -26}{x^{3}-7 x -6}}}{x^{3}-7 x -6}\) | \(104\) |
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.04 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 \, e^{\left (\frac {5 \, x^{3} - 2 \, x^{2} - 31 \, x - 26}{x^{3} - 7 \, x - 6}\right )} \]
[In]
[Out]
Time = 0.11 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 e^{\frac {5 x^{3} - 2 x^{2} - 31 x - 26}{x^{3} - 7 x - 6}} \]
[In]
[Out]
none
Time = 0.32 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 \, e^{\left (-\frac {12}{5 \, {\left (x + 2\right )}} + \frac {1}{2 \, {\left (x + 1\right )}} - \frac {1}{10 \, {\left (x - 3\right )}} + 5\right )} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 59 vs. \(2 (25) = 50\).
Time = 0.28 (sec) , antiderivative size = 59, normalized size of antiderivative = 2.11 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2 \, e^{\left (\frac {5 \, x^{3}}{x^{3} - 7 \, x - 6} - \frac {2 \, x^{2}}{x^{3} - 7 \, x - 6} - \frac {31 \, x}{x^{3} - 7 \, x - 6} - \frac {26}{x^{3} - 7 \, x - 6}\right )} \]
[In]
[Out]
Time = 12.35 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.11 \[ \int \frac {e^{\frac {-26-31 x-2 x^2+5 x^3}{-6-7 x+x^3}} \left (8+48 x+4 x^2-16 x^3+4 x^4\right )}{36+84 x+49 x^2-12 x^3-14 x^4+x^6} \, dx=2\,{\mathrm {e}}^{\frac {-5\,x^3+2\,x^2+31\,x+26}{-x^3+7\,x+6}} \]
[In]
[Out]