Integrand size = 7, antiderivative size = 24 \[ \int -\frac {1}{3 x} \, dx=\frac {1}{6} \left (4-\log (5)+\log \left (\frac {(1+\log (2))^4}{9 x^2}\right )\right ) \]
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Time = 0.00 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.25, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {12, 29} \[ \int -\frac {1}{3 x} \, dx=-\frac {\log (x)}{3} \]
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Rule 12
Rule 29
Rubi steps \begin{align*} \text {integral}& = -\left (\frac {1}{3} \int \frac {1}{x} \, dx\right ) \\ & = -\frac {\log (x)}{3} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.25 \[ \int -\frac {1}{3 x} \, dx=-\frac {\log (x)}{3} \]
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Time = 0.02 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.21
method | result | size |
default | \(-\frac {\ln \left (x \right )}{3}\) | \(5\) |
norman | \(-\frac {\ln \left (x \right )}{3}\) | \(5\) |
risch | \(-\frac {\ln \left (x \right )}{3}\) | \(5\) |
parallelrisch | \(-\frac {\ln \left (x \right )}{3}\) | \(5\) |
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none
Time = 0.29 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.17 \[ \int -\frac {1}{3 x} \, dx=-\frac {1}{3} \, \log \left (x\right ) \]
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Time = 0.02 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.21 \[ \int -\frac {1}{3 x} \, dx=- \frac {\log {\left (x \right )}}{3} \]
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none
Time = 0.19 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.17 \[ \int -\frac {1}{3 x} \, dx=-\frac {1}{3} \, \log \left (x\right ) \]
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none
Time = 0.29 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.21 \[ \int -\frac {1}{3 x} \, dx=-\frac {1}{3} \, \log \left ({\left | x \right |}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 4, normalized size of antiderivative = 0.17 \[ \int -\frac {1}{3 x} \, dx=-\frac {\ln \left (x\right )}{3} \]
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