Integrand size = 50, antiderivative size = 29 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {\frac {3}{4 x^2}+\frac {2}{x}+x+\frac {1+5 x}{\log (x)}}{\log ^2(x)} \]
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\[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{x^3 \log ^4(x)} \, dx \\ & = \frac {1}{2} \int \left (-\frac {6 (1+5 x)}{x \log ^4(x)}+\frac {-3-8 x+6 x^3}{x^3 \log ^3(x)}+\frac {-3-4 x+2 x^3}{x^3 \log ^2(x)}\right ) \, dx \\ & = \frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-3 \int \frac {1+5 x}{x \log ^4(x)} \, dx \\ & = \frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-3 \int \left (\frac {5}{\log ^4(x)}+\frac {1}{x \log ^4(x)}\right ) \, dx \\ & = \frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-3 \int \frac {1}{x \log ^4(x)} \, dx-15 \int \frac {1}{\log ^4(x)} \, dx \\ & = \frac {5 x}{\log ^3(x)}+\frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-3 \text {Subst}\left (\int \frac {1}{x^4} \, dx,x,\log (x)\right )-5 \int \frac {1}{\log ^3(x)} \, dx \\ & = \frac {1}{\log ^3(x)}+\frac {5 x}{\log ^3(x)}+\frac {5 x}{2 \log ^2(x)}+\frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-\frac {5}{2} \int \frac {1}{\log ^2(x)} \, dx \\ & = \frac {1}{\log ^3(x)}+\frac {5 x}{\log ^3(x)}+\frac {5 x}{2 \log ^2(x)}+\frac {5 x}{2 \log (x)}+\frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx-\frac {5}{2} \int \frac {1}{\log (x)} \, dx \\ & = \frac {1}{\log ^3(x)}+\frac {5 x}{\log ^3(x)}+\frac {5 x}{2 \log ^2(x)}+\frac {5 x}{2 \log (x)}-\frac {5 \operatorname {LogIntegral}(x)}{2}+\frac {1}{2} \int \frac {-3-8 x+6 x^3}{x^3 \log ^3(x)} \, dx+\frac {1}{2} \int \frac {-3-4 x+2 x^3}{x^3 \log ^2(x)} \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.31 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {1}{\log ^3(x)}+\frac {5 x}{\log ^3(x)}+\frac {3}{4 x^2 \log ^2(x)}+\frac {2}{x \log ^2(x)}+\frac {x}{\log ^2(x)} \]
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Time = 0.05 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14
method | result | size |
norman | \(\frac {x^{2}+x^{3} \ln \left (x \right )+5 x^{3}+2 x \ln \left (x \right )+\frac {3 \ln \left (x \right )}{4}}{x^{2} \ln \left (x \right )^{3}}\) | \(33\) |
default | \(\frac {x}{\ln \left (x \right )^{2}}+\frac {5 x}{\ln \left (x \right )^{3}}+\frac {2}{x \ln \left (x \right )^{2}}+\frac {1}{\ln \left (x \right )^{3}}+\frac {3}{4 x^{2} \ln \left (x \right )^{2}}\) | \(37\) |
risch | \(\frac {4 x^{3} \ln \left (x \right )+20 x^{3}+4 x^{2}+8 x \ln \left (x \right )+3 \ln \left (x \right )}{4 x^{2} \ln \left (x \right )^{3}}\) | \(37\) |
parallelrisch | \(-\frac {-4 x^{3} \ln \left (x \right )-20 x^{3}-4 x^{2}-8 x \ln \left (x \right )-3 \ln \left (x \right )}{4 x^{2} \ln \left (x \right )^{3}}\) | \(37\) |
parts | \(\frac {x}{\ln \left (x \right )^{2}}+\frac {5 x}{\ln \left (x \right )^{3}}+\frac {2}{x \ln \left (x \right )^{2}}+\frac {1}{\ln \left (x \right )^{3}}+\frac {3}{4 x^{2} \ln \left (x \right )^{2}}\) | \(37\) |
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Time = 0.30 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {20 \, x^{3} + 4 \, x^{2} + {\left (4 \, x^{3} + 8 \, x + 3\right )} \log \left (x\right )}{4 \, x^{2} \log \left (x\right )^{3}} \]
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Time = 0.06 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {20 x^{3} + 4 x^{2} + \left (4 x^{3} + 8 x + 3\right ) \log {\left (x \right )}}{4 x^{2} \log {\left (x \right )}^{3}} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.25 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.90 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {1}{\log \left (x\right )^{3}} + 3 \, \Gamma \left (-1, 2 \, \log \left (x\right )\right ) + \Gamma \left (-1, -\log \left (x\right )\right ) + 2 \, \Gamma \left (-1, \log \left (x\right )\right ) + 6 \, \Gamma \left (-2, 2 \, \log \left (x\right )\right ) - 3 \, \Gamma \left (-2, -\log \left (x\right )\right ) + 4 \, \Gamma \left (-2, \log \left (x\right )\right ) - 15 \, \Gamma \left (-3, -\log \left (x\right )\right ) \]
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Time = 0.29 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.24 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {4 \, x^{3} \log \left (x\right ) + 20 \, x^{3} + 4 \, x^{2} + 8 \, x \log \left (x\right ) + 3 \, \log \left (x\right )}{4 \, x^{2} \log \left (x\right )^{3}} \]
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Time = 12.90 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {-6 x^2-30 x^3+\left (-3-8 x+6 x^3\right ) \log (x)+\left (-3-4 x+2 x^3\right ) \log ^2(x)}{2 x^3 \log ^4(x)} \, dx=\frac {\ln \left (x\right )\,\left (x^3+2\,x+\frac {3}{4}\right )+x^2+5\,x^3}{x^2\,{\ln \left (x\right )}^3} \]
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