Integrand size = 16, antiderivative size = 13 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=-\frac {2}{3} (-3+6 x) \log (2 x) \]
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Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {14, 45, 2332} \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=2 \log (x)-4 x \log (2 x) \]
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Rule 14
Rule 45
Rule 2332
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2 (-1+2 x)}{x}-4 \log (2 x)\right ) \, dx \\ & = -\left (2 \int \frac {-1+2 x}{x} \, dx\right )-4 \int \log (2 x) \, dx \\ & = 4 x-4 x \log (2 x)-2 \int \left (2-\frac {1}{x}\right ) \, dx \\ & = 2 \log (x)-4 x \log (2 x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=2 \log (x)-4 x \log (2 x) \]
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Time = 0.04 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00
method | result | size |
risch | \(-4 x \ln \left (2 x \right )+2 \ln \left (x \right )\) | \(13\) |
parts | \(-4 x \ln \left (2 x \right )+2 \ln \left (x \right )\) | \(13\) |
derivativedivides | \(-4 x \ln \left (2 x \right )+2 \ln \left (2 x \right )\) | \(15\) |
default | \(-4 x \ln \left (2 x \right )+2 \ln \left (2 x \right )\) | \(15\) |
norman | \(-4 x \ln \left (2 x \right )+2 \ln \left (2 x \right )\) | \(15\) |
parallelrisch | \(-4 x \ln \left (2 x \right )+2 \ln \left (2 x \right )\) | \(15\) |
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Time = 0.38 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=-2 \, {\left (2 \, x - 1\right )} \log \left (2 \, x\right ) \]
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Time = 0.05 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=- 4 x \log {\left (2 x \right )} + 2 \log {\left (x \right )} \]
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Time = 0.20 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=-4 \, x \log \left (2 \, x\right ) + 2 \, \log \left (x\right ) \]
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Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=-4 \, x \log \left (2 \, x\right ) + 2 \, \log \left (x\right ) \]
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Time = 13.34 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.15 \[ \int \frac {2-4 x-4 x \log (2 x)}{x} \, dx=2\,\ln \left (x\right )-4\,x\,\ln \left (2\right )-4\,x\,\ln \left (x\right ) \]
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