Integrand size = 206, antiderivative size = 26 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=\frac {13}{6 \left (-x+\log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )\right )} \]
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Time = 0.40 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.015, Rules used = {6820, 12, 6818} \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=-\frac {13}{6 \left (x-\log \left (\log \left (e^{x^2}+e^{x/2}-3\right )\right )\right )} \]
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Rule 12
Rule 6818
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {13 \left (e^{x/2}+4 e^{x^2} x-2 \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )\right )}{12 \left (3-e^{x/2}-e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \left (x-\log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )\right )^2} \, dx \\ & = \frac {13}{12} \int \frac {e^{x/2}+4 e^{x^2} x-2 \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (3-e^{x/2}-e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \left (x-\log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )\right )^2} \, dx \\ & = -\frac {13}{6 \left (x-\log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )\right )} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=\frac {13}{6 \left (-x+\log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )\right )} \]
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Time = 12.20 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.81
method | result | size |
risch | \(-\frac {13}{6 \left (x -\ln \left (\ln \left ({\mathrm e}^{x^{2}}+{\mathrm e}^{\frac {x}{2}}-3\right )\right )\right )}\) | \(21\) |
parallelrisch | \(-\frac {13}{6 \left (x -\ln \left (\ln \left ({\mathrm e}^{x^{2}}+{\mathrm e}^{\frac {x}{2}}-3\right )\right )\right )}\) | \(21\) |
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Time = 0.42 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=-\frac {13}{6 \, {\left (x - \log \left (\log \left (e^{\left (x^{2}\right )} + e^{\left (\frac {1}{2} \, x\right )} - 3\right )\right )\right )}} \]
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Time = 6.34 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=\frac {13}{- 6 x + 6 \log {\left (\log {\left (e^{\frac {x}{2}} + e^{x^{2}} - 3 \right )} \right )}} \]
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Time = 0.29 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=-\frac {13}{6 \, {\left (x - \log \left (\log \left (e^{\left (x^{2}\right )} + e^{\left (\frac {1}{2} \, x\right )} - 3\right )\right )\right )}} \]
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Time = 1.13 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=-\frac {13}{6 \, {\left (x - \log \left (\log \left (e^{\left (x^{2}\right )} + e^{\left (\frac {1}{2} \, x\right )} - 3\right )\right )\right )}} \]
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Time = 12.72 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.85 \[ \int \frac {-13 e^{x/2}-52 e^{x^2} x+\left (-78+26 e^{x/2}+26 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )}{\left (-36 x^2+12 e^{x/2} x^2+12 e^{x^2} x^2\right ) \log \left (-3+e^{x/2}+e^{x^2}\right )+\left (72 x-24 e^{x/2} x-24 e^{x^2} x\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log \left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )+\left (-36+12 e^{x/2}+12 e^{x^2}\right ) \log \left (-3+e^{x/2}+e^{x^2}\right ) \log ^2\left (\log \left (-3+e^{x/2}+e^{x^2}\right )\right )} \, dx=-\frac {13}{6\,\left (x-\ln \left (\ln \left ({\mathrm {e}}^{x/2}+{\mathrm {e}}^{x^2}-3\right )\right )\right )} \]
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