Integrand size = 16, antiderivative size = 22 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=3-2 x+x (4+x)-e \left (5-x^2\right )^2 \]
[Out]
Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86, number of steps used = 2, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=-e x^4+10 e x^2+x^2+2 x \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = 2 x+x^2+e \int \left (20 x-4 x^3\right ) \, dx \\ & = 2 x+x^2+10 e x^2-e x^4 \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=2 x+(1+10 e) x^2-e x^4 \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91
method | result | size |
gosper | \(-x \left (x^{3} {\mathrm e}-10 x \,{\mathrm e}-x -2\right )\) | \(20\) |
default | \(-x^{4} {\mathrm e}+10 x^{2} {\mathrm e}+x^{2}+2 x\) | \(22\) |
norman | \(\left (10 \,{\mathrm e}+1\right ) x^{2}+2 x -x^{4} {\mathrm e}\) | \(22\) |
parallelrisch | \(-x^{4} {\mathrm e}+10 x^{2} {\mathrm e}+x^{2}+2 x\) | \(22\) |
parts | \(-x^{4} {\mathrm e}+10 x^{2} {\mathrm e}+x^{2}+2 x\) | \(22\) |
risch | \(-x^{4} {\mathrm e}+10 x^{2} {\mathrm e}+x^{2}-25 \,{\mathrm e}+2 x\) | \(26\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=x^{2} - {\left (x^{4} - 10 \, x^{2}\right )} e + 2 \, x \]
[In]
[Out]
Time = 0.02 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=- e x^{4} + x^{2} \cdot \left (1 + 10 e\right ) + 2 x \]
[In]
[Out]
none
Time = 0.23 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=x^{2} - {\left (x^{4} - 10 \, x^{2}\right )} e + 2 \, x \]
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=x^{2} - {\left (x^{4} - 10 \, x^{2}\right )} e + 2 \, x \]
[In]
[Out]
Time = 0.04 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \left (2+2 x+e \left (20 x-4 x^3\right )\right ) \, dx=-\mathrm {e}\,x^4+\left (10\,\mathrm {e}+1\right )\,x^2+2\,x \]
[In]
[Out]