Integrand size = 29, antiderivative size = 31 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=x-\frac {1}{2} x^2 \left (4+\frac {1}{5} \left (-3 x+x^2-\log \left (\frac {x}{\log ^2(4)}\right )\right )\right ) \]
[Out]
Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.13, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {12, 2341} \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=-\frac {x^4}{10}+\frac {3 x^3}{10}-2 x^2+\frac {1}{10} x^2 \log \left (\frac {x}{\log ^2(4)}\right )+x \]
[In]
[Out]
Rule 12
Rule 2341
Rubi steps \begin{align*} \text {integral}& = \frac {1}{10} \int \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx \\ & = x-\frac {39 x^2}{20}+\frac {3 x^3}{10}-\frac {x^4}{10}+\frac {1}{5} \int x \log \left (\frac {x}{\log ^2(4)}\right ) \, dx \\ & = x-2 x^2+\frac {3 x^3}{10}-\frac {x^4}{10}+\frac {1}{10} x^2 \log \left (\frac {x}{\log ^2(4)}\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.13 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=x-2 x^2+\frac {3 x^3}{10}-\frac {x^4}{10}+\frac {1}{10} x^2 \log \left (\frac {x}{\log ^2(4)}\right ) \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00
method | result | size |
default | \(x -2 x^{2}+\frac {3 x^{3}}{10}-\frac {x^{4}}{10}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{10}\) | \(31\) |
norman | \(x -2 x^{2}+\frac {3 x^{3}}{10}-\frac {x^{4}}{10}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{10}\) | \(31\) |
risch | \(x -2 x^{2}+\frac {3 x^{3}}{10}-\frac {x^{4}}{10}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{10}\) | \(31\) |
parallelrisch | \(x -2 x^{2}+\frac {3 x^{3}}{10}-\frac {x^{4}}{10}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{10}\) | \(31\) |
parts | \(x -2 x^{2}+\frac {3 x^{3}}{10}-\frac {x^{4}}{10}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{10}\) | \(31\) |
derivativedivides | \(\frac {4 \ln \left (2\right )^{2} \left (\frac {5 x}{4 \ln \left (2\right )^{2}}-\frac {5 x^{2}}{2 \ln \left (2\right )^{2}}+\frac {3 x^{3}}{8 \ln \left (2\right )^{2}}-\frac {x^{4}}{8 \ln \left (2\right )^{2}}+\frac {x^{2} \ln \left (\frac {x}{4 \ln \left (2\right )^{2}}\right )}{8 \ln \left (2\right )^{2}}\right )}{5}\) | \(59\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=-\frac {1}{10} \, x^{4} + \frac {3}{10} \, x^{3} + \frac {1}{10} \, x^{2} \log \left (\frac {x}{4 \, \log \left (2\right )^{2}}\right ) - 2 \, x^{2} + x \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.03 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=- \frac {x^{4}}{10} + \frac {3 x^{3}}{10} + \frac {x^{2} \log {\left (\frac {x}{4 \log {\left (2 \right )}^{2}} \right )}}{10} - 2 x^{2} + x \]
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=-\frac {1}{10} \, x^{4} + \frac {3}{10} \, x^{3} + \frac {1}{10} \, x^{2} \log \left (\frac {x}{4 \, \log \left (2\right )^{2}}\right ) - 2 \, x^{2} + x \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=-\frac {1}{10} \, x^{4} + \frac {3}{10} \, x^{3} + \frac {1}{10} \, x^{2} \log \left (\frac {x}{4 \, \log \left (2\right )^{2}}\right ) - 2 \, x^{2} + x \]
[In]
[Out]
Time = 13.61 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.03 \[ \int \frac {1}{10} \left (10-39 x+9 x^2-4 x^3+2 x \log \left (\frac {x}{\log ^2(4)}\right )\right ) \, dx=-\frac {x\,\left (20\,x+2\,x\,\ln \left (2\right )+2\,x\,\ln \left (\ln \left (2\right )\right )-x\,\ln \left (x\right )-3\,x^2+x^3-10\right )}{10} \]
[In]
[Out]