Integrand size = 79, antiderivative size = 17 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=\log \left (x+8 x^2 (4+\log (9+x \log (4)))\right ) \]
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Time = 0.18 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.06, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.025, Rules used = {6873, 6817} \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=\log (x (32 x+8 x \log (x \log (4)+9)+1)) \]
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Rule 6817
Rule 6873
Rubi steps \begin{align*} \text {integral}& = \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{x (9+x \log (4)) (1+32 x+8 x \log (9+x \log (4)))} \, dx \\ & = \log (x (1+32 x+8 x \log (9+x \log (4)))) \\ \end{align*}
Time = 5.03 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=\log (x)+\log (1+32 x+8 x \log (9+x \log (4))) \]
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Time = 0.41 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18
method | result | size |
parallelrisch | \(\ln \left (x \right )+\ln \left (x \ln \left (2 x \ln \left (2\right )+9\right )+4 x +\frac {1}{8}\right )\) | \(20\) |
norman | \(\ln \left (x \right )+\ln \left (8 x \ln \left (2 x \ln \left (2\right )+9\right )+32 x +1\right )\) | \(21\) |
risch | \(2 \ln \left (x \right )+\ln \left (\ln \left (2 x \ln \left (2\right )+9\right )+\frac {32 x +1}{8 x}\right )\) | \(26\) |
derivativedivides | \(\ln \left (2 x \ln \left (2\right )\right )+\ln \left (4 \left (2 x \ln \left (2\right )+9\right ) \ln \left (2 x \ln \left (2\right )+9\right )+\ln \left (2\right )-36 \ln \left (2 x \ln \left (2\right )+9\right )+32 x \ln \left (2\right )\right )\) | \(44\) |
default | \(\ln \left (2 x \ln \left (2\right )\right )+\ln \left (4 \left (2 x \ln \left (2\right )+9\right ) \ln \left (2 x \ln \left (2\right )+9\right )+\ln \left (2\right )-36 \ln \left (2 x \ln \left (2\right )+9\right )+32 x \ln \left (2\right )\right )\) | \(44\) |
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Time = 0.25 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.53 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=2 \, \log \left (x\right ) + \log \left (\frac {8 \, x \log \left (2 \, x \log \left (2\right ) + 9\right ) + 32 \, x + 1}{x}\right ) \]
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Time = 0.15 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.41 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=2 \log {\left (x \right )} + \log {\left (\log {\left (2 x \log {\left (2 \right )} + 9 \right )} + \frac {32 x + 1}{8 x} \right )} \]
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Time = 0.31 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.59 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=2 \, \log \left (x\right ) + \log \left (\frac {8 \, x \log \left (2 \, x \log \left (2\right ) + 9\right ) + 32 \, x + 1}{8 \, x}\right ) \]
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Time = 0.27 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=\log \left (8 \, x \log \left (2 \, x \log \left (2\right ) + 9\right ) + 32 \, x + 1\right ) + \log \left (x\right ) \]
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Time = 13.90 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.53 \[ \int \frac {9+576 x+\left (x+72 x^2\right ) \log (4)+\left (144 x+16 x^2 \log (4)\right ) \log (9+x \log (4))}{9 x+288 x^2+\left (x^2+32 x^3\right ) \log (4)+\left (72 x^2+8 x^3 \log (4)\right ) \log (9+x \log (4))} \, dx=\ln \left (\frac {32\,x+8\,x\,\ln \left (2\,x\,\ln \left (2\right )+9\right )+1}{x}\right )+2\,\ln \left (x\right ) \]
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