Integrand size = 19, antiderivative size = 20 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=9 \left (x-(3-x) x-256 x^4\right )+\log (x) \]
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Time = 0.00 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {14} \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=-2304 x^4+9 x^2-18 x+\log (x) \]
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Rule 14
Rubi steps \begin{align*} \text {integral}& = \int \left (-18+\frac {1}{x}+18 x-9216 x^3\right ) \, dx \\ & = -18 x+9 x^2-2304 x^4+\log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=-18 x+9 x^2-2304 x^4+\log (x) \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85
method | result | size |
default | \(-2304 x^{4}+9 x^{2}-18 x +\ln \left (x \right )\) | \(17\) |
norman | \(-2304 x^{4}+9 x^{2}-18 x +\ln \left (x \right )\) | \(17\) |
risch | \(-2304 x^{4}+9 x^{2}-18 x +\ln \left (x \right )\) | \(17\) |
parallelrisch | \(-2304 x^{4}+9 x^{2}-18 x +\ln \left (x \right )\) | \(17\) |
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none
Time = 0.23 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=-2304 \, x^{4} + 9 \, x^{2} - 18 \, x + \log \left (x\right ) \]
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Time = 0.03 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.75 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=- 2304 x^{4} + 9 x^{2} - 18 x + \log {\left (x \right )} \]
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none
Time = 0.18 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=-2304 \, x^{4} + 9 \, x^{2} - 18 \, x + \log \left (x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=-2304 \, x^{4} + 9 \, x^{2} - 18 \, x + \log \left ({\left | x \right |}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.80 \[ \int \frac {1-18 x+18 x^2-9216 x^4}{x} \, dx=\ln \left (x\right )-18\,x+9\,x^2-2304\,x^4 \]
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