Integrand size = 25, antiderivative size = 14 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-64 \log ^2\left (7+(1-x)^2\right ) \]
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Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.28 (sec) , antiderivative size = 249, normalized size of antiderivative = 17.79, number of steps used = 18, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {2608, 2604, 2465, 2437, 2338, 2441, 2440, 2438} \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=128 \operatorname {PolyLog}\left (2,-\frac {-i x-\sqrt {7}+i}{2 \sqrt {7}}\right )+128 \operatorname {PolyLog}\left (2,\frac {-i x+\sqrt {7}+i}{2 \sqrt {7}}\right )-128 \log \left (2 x-2 \left (1-i \sqrt {7}\right )\right ) \log \left (x^2-2 x+8\right )-128 \log \left (2 x-2 \left (1+i \sqrt {7}\right )\right ) \log \left (x^2-2 x+8\right )+64 \log ^2\left (-2 \left (-x-i \sqrt {7}+1\right )\right )+64 \log ^2\left (-2 \left (-x+i \sqrt {7}+1\right )\right )+128 \log \left (-\frac {i \left (-x+i \sqrt {7}+1\right )}{2 \sqrt {7}}\right ) \log \left (2 x-2 \left (1-i \sqrt {7}\right )\right )+128 \log \left (\frac {i \left (-x-i \sqrt {7}+1\right )}{2 \sqrt {7}}\right ) \log \left (2 x-2 \left (1+i \sqrt {7}\right )\right ) \]
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Rule 2338
Rule 2437
Rule 2438
Rule 2440
Rule 2441
Rule 2465
Rule 2604
Rule 2608
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {256 \log \left (8-2 x+x^2\right )}{-2-2 i \sqrt {7}+2 x}-\frac {256 \log \left (8-2 x+x^2\right )}{-2+2 i \sqrt {7}+2 x}\right ) \, dx \\ & = -\left (256 \int \frac {\log \left (8-2 x+x^2\right )}{-2-2 i \sqrt {7}+2 x} \, dx\right )-256 \int \frac {\log \left (8-2 x+x^2\right )}{-2+2 i \sqrt {7}+2 x} \, dx \\ & = -128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )+128 \int \frac {(-2+2 x) \log \left (-2-2 i \sqrt {7}+2 x\right )}{8-2 x+x^2} \, dx+128 \int \frac {(-2+2 x) \log \left (-2+2 i \sqrt {7}+2 x\right )}{8-2 x+x^2} \, dx \\ & = -128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )+128 \int \left (\frac {2 \log \left (-2-2 i \sqrt {7}+2 x\right )}{-2-2 i \sqrt {7}+2 x}+\frac {2 \log \left (-2-2 i \sqrt {7}+2 x\right )}{-2+2 i \sqrt {7}+2 x}\right ) \, dx+128 \int \left (\frac {2 \log \left (-2+2 i \sqrt {7}+2 x\right )}{-2-2 i \sqrt {7}+2 x}+\frac {2 \log \left (-2+2 i \sqrt {7}+2 x\right )}{-2+2 i \sqrt {7}+2 x}\right ) \, dx \\ & = -128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )+256 \int \frac {\log \left (-2-2 i \sqrt {7}+2 x\right )}{-2-2 i \sqrt {7}+2 x} \, dx+256 \int \frac {\log \left (-2-2 i \sqrt {7}+2 x\right )}{-2+2 i \sqrt {7}+2 x} \, dx+256 \int \frac {\log \left (-2+2 i \sqrt {7}+2 x\right )}{-2-2 i \sqrt {7}+2 x} \, dx+256 \int \frac {\log \left (-2+2 i \sqrt {7}+2 x\right )}{-2+2 i \sqrt {7}+2 x} \, dx \\ & = 128 \log \left (-\frac {i \left (1+i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right )+128 \log \left (\frac {i \left (1-i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right )-128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )+128 \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,-2-2 i \sqrt {7}+2 x\right )+128 \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,-2+2 i \sqrt {7}+2 x\right )-256 \int \frac {\log \left (\frac {2 \left (-2-2 i \sqrt {7}+2 x\right )}{2 \left (-2-2 i \sqrt {7}\right )-2 \left (-2+2 i \sqrt {7}\right )}\right )}{-2+2 i \sqrt {7}+2 x} \, dx-256 \int \frac {\log \left (\frac {2 \left (-2+2 i \sqrt {7}+2 x\right )}{-2 \left (-2-2 i \sqrt {7}\right )+2 \left (-2+2 i \sqrt {7}\right )}\right )}{-2-2 i \sqrt {7}+2 x} \, dx \\ & = 64 \log ^2\left (-2 \left (1-i \sqrt {7}-x\right )\right )+64 \log ^2\left (-2 \left (1+i \sqrt {7}-x\right )\right )+128 \log \left (-\frac {i \left (1+i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right )+128 \log \left (\frac {i \left (1-i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right )-128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \text {Subst}\left (\int \frac {\log \left (1+\frac {2 x}{2 \left (-2-2 i \sqrt {7}\right )-2 \left (-2+2 i \sqrt {7}\right )}\right )}{x} \, dx,x,-2+2 i \sqrt {7}+2 x\right )-128 \text {Subst}\left (\int \frac {\log \left (1+\frac {2 x}{-2 \left (-2-2 i \sqrt {7}\right )+2 \left (-2+2 i \sqrt {7}\right )}\right )}{x} \, dx,x,-2-2 i \sqrt {7}+2 x\right ) \\ & = 64 \log ^2\left (-2 \left (1-i \sqrt {7}-x\right )\right )+64 \log ^2\left (-2 \left (1+i \sqrt {7}-x\right )\right )+128 \log \left (-\frac {i \left (1+i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right )+128 \log \left (\frac {i \left (1-i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right )-128 \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )-128 \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right ) \log \left (8-2 x+x^2\right )+128 \operatorname {PolyLog}\left (2,-\frac {i-\sqrt {7}-i x}{2 \sqrt {7}}\right )+128 \operatorname {PolyLog}\left (2,\frac {i+\sqrt {7}-i x}{2 \sqrt {7}}\right ) \\ \end{align*}
Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.05 (sec) , antiderivative size = 265, normalized size of antiderivative = 18.93 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-256 \left (-\frac {1}{2} \log \left (-\frac {i \left (1+i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1-i \sqrt {7}\right )+2 x\right )-\frac {1}{4} \log ^2\left (-2 \left (1-i \sqrt {7}\right )+2 x\right )-\frac {1}{2} \log \left (\frac {i \left (1-i \sqrt {7}-x\right )}{2 \sqrt {7}}\right ) \log \left (-2 \left (1+i \sqrt {7}\right )+2 x\right )-\frac {1}{4} \log ^2\left (-2 \left (1+i \sqrt {7}\right )+2 x\right )+\frac {1}{2} \log \left (-2-2 i \sqrt {7}+2 x\right ) \log \left (8-2 x+x^2\right )+\frac {1}{2} \log \left (-2+2 i \sqrt {7}+2 x\right ) \log \left (8-2 x+x^2\right )-\frac {1}{2} \operatorname {PolyLog}\left (2,\frac {i \left (1-i \sqrt {7}-x\right )}{2 \sqrt {7}}\right )-\frac {1}{2} \operatorname {PolyLog}\left (2,-\frac {i \left (1+i \sqrt {7}-x\right )}{2 \sqrt {7}}\right )\right ) \]
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Time = 1.49 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00
method | result | size |
norman | \(-64 \ln \left (x^{2}-2 x +8\right )^{2}\) | \(14\) |
risch | \(-64 \ln \left (x^{2}-2 x +8\right )^{2}\) | \(14\) |
default | \(-128 \ln \left (x -1-i \sqrt {7}\right ) \ln \left (x^{2}-2 x +8\right )+64 \ln \left (x -1-i \sqrt {7}\right )^{2}+128 \operatorname {dilog}\left (-\frac {i \left (-1+i \sqrt {7}+x \right ) \sqrt {7}}{14}\right )+128 \ln \left (x -1-i \sqrt {7}\right ) \ln \left (-\frac {i \left (-1+i \sqrt {7}+x \right ) \sqrt {7}}{14}\right )-128 \ln \left (-1+i \sqrt {7}+x \right ) \ln \left (x^{2}-2 x +8\right )+64 \ln \left (-1+i \sqrt {7}+x \right )^{2}+128 \operatorname {dilog}\left (\frac {i \left (x -1-i \sqrt {7}\right ) \sqrt {7}}{14}\right )+128 \ln \left (-1+i \sqrt {7}+x \right ) \ln \left (\frac {i \left (x -1-i \sqrt {7}\right ) \sqrt {7}}{14}\right )\) | \(164\) |
parts | \(-128 \ln \left (x^{2}-2 x +8\right )^{2}+128 \ln \left (x -1-i \sqrt {7}\right ) \ln \left (x^{2}-2 x +8\right )-64 \ln \left (x -1-i \sqrt {7}\right )^{2}-128 \operatorname {dilog}\left (-\frac {i \left (-1+i \sqrt {7}+x \right ) \sqrt {7}}{14}\right )-128 \ln \left (x -1-i \sqrt {7}\right ) \ln \left (-\frac {i \left (-1+i \sqrt {7}+x \right ) \sqrt {7}}{14}\right )+128 \ln \left (-1+i \sqrt {7}+x \right ) \ln \left (x^{2}-2 x +8\right )-64 \ln \left (-1+i \sqrt {7}+x \right )^{2}-128 \operatorname {dilog}\left (\frac {i \left (x -1-i \sqrt {7}\right ) \sqrt {7}}{14}\right )-128 \ln \left (-1+i \sqrt {7}+x \right ) \ln \left (\frac {i \left (x -1-i \sqrt {7}\right ) \sqrt {7}}{14}\right )\) | \(177\) |
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Time = 0.25 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-64 \, \log \left (x^{2} - 2 \, x + 8\right )^{2} \]
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Time = 0.07 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=- 64 \log {\left (x^{2} - 2 x + 8 \right )}^{2} \]
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Time = 0.21 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-64 \, \log \left (x^{2} - 2 \, x + 8\right )^{2} \]
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Time = 0.28 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-64 \, \log \left (x^{2} - 2 \, x + 8\right )^{2} \]
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Time = 0.15 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93 \[ \int \frac {(256-256 x) \log \left (8-2 x+x^2\right )}{8-2 x+x^2} \, dx=-64\,{\ln \left (x^2-2\,x+8\right )}^2 \]
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