Integrand size = 39, antiderivative size = 38 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {3}{2}+\frac {4-e^{5/x}+e^x-x \left (1-\frac {\log \left (\frac {x}{3}\right )}{x}\right )}{x} \]
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Time = 0.07 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.92, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {14, 2228, 2326, 2341} \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=-\frac {e^{5/x}}{x}+\frac {e^x}{x}+\frac {1}{x}+\frac {\log \left (\frac {x}{3}\right )+3}{x} \]
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Rule 14
Rule 2228
Rule 2326
Rule 2341
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {e^x (-1+x)}{x^2}+\frac {5 e^{5/x}-3 x+e^{5/x} x-x \log \left (\frac {x}{3}\right )}{x^3}\right ) \, dx \\ & = \int \frac {e^x (-1+x)}{x^2} \, dx+\int \frac {5 e^{5/x}-3 x+e^{5/x} x-x \log \left (\frac {x}{3}\right )}{x^3} \, dx \\ & = \frac {e^x}{x}+\int \left (\frac {e^{5/x} (5+x)}{x^3}+\frac {-3-\log \left (\frac {x}{3}\right )}{x^2}\right ) \, dx \\ & = \frac {e^x}{x}+\int \frac {e^{5/x} (5+x)}{x^3} \, dx+\int \frac {-3-\log \left (\frac {x}{3}\right )}{x^2} \, dx \\ & = \frac {1}{x}-\frac {e^{5/x}}{x}+\frac {e^x}{x}+\frac {3+\log \left (\frac {x}{3}\right )}{x} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.63 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {4-e^{5/x}+e^x+\log \left (\frac {x}{3}\right )}{x} \]
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Time = 0.12 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.63
method | result | size |
parallelrisch | \(-\frac {-4-{\mathrm e}^{x}-\ln \left (\frac {x}{3}\right )+{\mathrm e}^{\frac {5}{x}}}{x}\) | \(24\) |
risch | \(\frac {\ln \left (\frac {x}{3}\right )}{x}+\frac {4+{\mathrm e}^{x}-{\mathrm e}^{\frac {5}{x}}}{x}\) | \(26\) |
default | \(\frac {{\mathrm e}^{x}}{x}-\frac {{\mathrm e}^{\frac {5}{x}}}{x}+\frac {4}{x}+\frac {\ln \left (\frac {x}{3}\right )}{x}\) | \(32\) |
parts | \(\frac {{\mathrm e}^{x}}{x}-\frac {{\mathrm e}^{\frac {5}{x}}}{x}+\frac {4}{x}+\frac {\ln \left (\frac {x}{3}\right )}{x}\) | \(32\) |
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none
Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.53 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {e^{x} - e^{\frac {5}{x}} + \log \left (\frac {1}{3} \, x\right ) + 4}{x} \]
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Time = 0.14 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.53 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=- \frac {e^{\frac {5}{x}}}{x} + \frac {e^{x}}{x} + \frac {\log {\left (\frac {x}{3} \right )}}{x} + \frac {4}{x} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.22 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.05 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {\log \left (\frac {1}{3} \, x\right )}{x} + \frac {4}{x} + {\rm Ei}\left (x\right ) - \frac {1}{5} \, e^{\frac {5}{x}} + \frac {1}{5} \, \Gamma \left (2, -\frac {5}{x}\right ) - \Gamma \left (-1, -x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.53 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {e^{x} - e^{\frac {5}{x}} + \log \left (\frac {1}{3} \, x\right ) + 4}{x} \]
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Time = 11.96 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.53 \[ \int \frac {-3 x+e^{5/x} (5+x)+e^x \left (-x+x^2\right )-x \log \left (\frac {x}{3}\right )}{x^3} \, dx=\frac {\ln \left (\frac {x}{3}\right )-{\mathrm {e}}^{5/x}+{\mathrm {e}}^x+4}{x} \]
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