Integrand size = 210, antiderivative size = 25 \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\frac {x}{3 \left (2+\left (4-\frac {5}{x}+6 \left (e^x+x\right )\right )^x\right )} \]
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\[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {10-8 x-12 e^x x-12 x^2-\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{3 \left (5-4 x-6 e^x x-6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = \frac {1}{3} \int \frac {10-8 x-12 e^x x-12 x^2-\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{\left (5-4 x-6 e^x x-6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = \frac {1}{3} \int \left (-\frac {10}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {8 x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {12 e^x x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {12 x^2}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}-\frac {\left (4+6 e^x-\frac {5}{x}+6 x\right )^x \left (5+x-6 e^x x-6 x^2+6 x^3+6 e^x x^3-5 x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+4 x^2 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+6 e^x x^2 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+6 x^3 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}\right ) \, dx \\ & = -\left (\frac {1}{3} \int \frac {\left (4+6 e^x-\frac {5}{x}+6 x\right )^x \left (5+x-6 e^x x-6 x^2+6 x^3+6 e^x x^3-5 x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+4 x^2 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+6 e^x x^2 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )+6 x^3 \log \left (4+6 e^x-\frac {5}{x}+6 x\right )\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx\right )+\frac {8}{3} \int \frac {x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-\frac {10}{3} \int \frac {1}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {e^x x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {x^2}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = -\left (\frac {1}{3} \int \frac {\left (4+6 e^x-\frac {5}{x}+6 x\right )^x \left (-5-x+6 e^x x+6 x^2-6 \left (1+e^x\right ) x^3-x \left (-5+\left (4+6 e^x\right ) x+6 x^2\right ) \log \left (4+6 e^x-\frac {5}{x}+6 x\right )\right )}{\left (5-\left (4+6 e^x\right ) x-6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx\right )+\frac {8}{3} \int \frac {x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-\frac {10}{3} \int \frac {1}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {e^x x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {x^2}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = -\left (\frac {1}{3} \int \left (\frac {5 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}-\frac {6 e^x x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}-\frac {6 x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {6 x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {6 e^x x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}-\frac {5 x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {4 x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {6 e^x x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}+\frac {6 x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2}\right ) \, dx\right )+\frac {8}{3} \int \frac {x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-\frac {10}{3} \int \frac {1}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {e^x x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {x^2}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = -\left (\frac {1}{3} \int \frac {x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx\right )-\frac {4}{3} \int \frac {x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-\frac {5}{3} \int \frac {\left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+\frac {5}{3} \int \frac {x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+2 \int \frac {e^x x \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+2 \int \frac {x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-2 \int \frac {x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-2 \int \frac {e^x x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-2 \int \frac {e^x x^2 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-2 \int \frac {x^3 \left (4+6 e^x-\frac {5}{x}+6 x\right )^x \log \left (4+6 e^x-\frac {5}{x}+6 x\right )}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+\frac {8}{3} \int \frac {x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx-\frac {10}{3} \int \frac {1}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {e^x x}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx+4 \int \frac {x^2}{\left (-5+4 x+6 e^x x+6 x^2\right ) \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )^2} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.23 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.04 \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\frac {x}{3 \left (2+\left (4+6 e^x-\frac {5}{x}+6 x\right )^x\right )} \]
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Time = 12.35 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.24
method | result | size |
parallelrisch | \(\frac {x}{3 \,{\mathrm e}^{x \ln \left (\frac {6 \,{\mathrm e}^{x} x +6 x^{2}+4 x -5}{x}\right )}+6}\) | \(31\) |
risch | \(\frac {x}{3 x^{-x} 3^{x} 2^{x} \left (-\frac {5}{6}+x^{2}+\left (\frac {2}{3}+{\mathrm e}^{x}\right ) x \right )^{x} {\mathrm e}^{-\frac {i \pi \,\operatorname {csgn}\left (\frac {i \left (-\frac {5}{6}+x^{2}+\left (\frac {2}{3}+{\mathrm e}^{x}\right ) x \right )}{x}\right ) x \left (-\operatorname {csgn}\left (\frac {i \left (-\frac {5}{6}+x^{2}+\left (\frac {2}{3}+{\mathrm e}^{x}\right ) x \right )}{x}\right )+\operatorname {csgn}\left (i \left (-\frac {5}{6}+x^{2}+\left (\frac {2}{3}+{\mathrm e}^{x}\right ) x \right )\right )\right ) \left (-\operatorname {csgn}\left (\frac {i \left (-\frac {5}{6}+x^{2}+\left (\frac {2}{3}+{\mathrm e}^{x}\right ) x \right )}{x}\right )+\operatorname {csgn}\left (\frac {i}{x}\right )\right )}{2}}+6}\) | \(121\) |
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\frac {x}{3 \, {\left (\left (\frac {6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5}{x}\right )^{x} + 2\right )}} \]
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Timed out. \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\text {Timed out} \]
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Time = 0.35 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.24 \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\frac {x x^{x}}{3 \, {\left ({\left (6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5\right )}^{x} + 2 \, x^{x}\right )}} \]
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\[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\int { \frac {12 \, x^{2} - {\left (6 \, x^{3} - 6 \, x^{2} + 6 \, {\left (x^{3} - x\right )} e^{x} + {\left (6 \, x^{3} + 6 \, x^{2} e^{x} + 4 \, x^{2} - 5 \, x\right )} \log \left (\frac {6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5}{x}\right ) + x + 5\right )} \left (\frac {6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5}{x}\right )^{x} + 12 \, x e^{x} + 8 \, x - 10}{3 \, {\left (24 \, x^{2} + {\left (6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5\right )} \left (\frac {6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5}{x}\right )^{2 \, x} + 4 \, {\left (6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5\right )} \left (\frac {6 \, x^{2} + 6 \, x e^{x} + 4 \, x - 5}{x}\right )^{x} + 24 \, x e^{x} + 16 \, x - 20\right )}} \,d x } \]
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Time = 13.10 (sec) , antiderivative size = 254, normalized size of antiderivative = 10.16 \[ \int \frac {-10+8 x+12 e^x x+12 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-5-x+6 x^2-6 x^3+e^x \left (6 x-6 x^3\right )+\left (5 x-4 x^2-6 e^x x^2-6 x^3\right ) \log \left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )\right )}{-60+48 x+72 e^x x+72 x^2+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^{2 x} \left (-15+12 x+18 e^x x+18 x^2\right )+\left (\frac {-5+4 x+6 e^x x+6 x^2}{x}\right )^x \left (-60+48 x+72 e^x x+72 x^2\right )} \, dx=\frac {5\,x+6\,x^3\,{\mathrm {e}}^x-5\,x\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+6\,x^3+4\,x^2\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+6\,x^3\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+6\,x^2\,{\mathrm {e}}^x\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )}{3\,\left ({\left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )}^x+2\right )\,\left (6\,x^2\,{\mathrm {e}}^x-5\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+4\,x\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+6\,x^2+6\,x^2\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+6\,x\,{\mathrm {e}}^x\,\ln \left (\frac {4\,x+6\,x\,{\mathrm {e}}^x+6\,x^2-5}{x}\right )+5\right )} \]
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