Integrand size = 76, antiderivative size = 34 \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\frac {\frac {4 \left (-1+e^{\frac {e^x}{\log (6)}}\right )}{x}+\frac {1}{5} \left (-x+x^2\right )}{\log (x)} \]
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\[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{x^2 \log ^2(x)} \, dx}{5 \log (6)} \\ & = \frac {\int \left (\frac {\log (6) \left (20+x^2-x^3+20 \log (x)-x^2 \log (x)+2 x^3 \log (x)\right )}{x^2 \log ^2(x)}+\frac {20 e^{\frac {e^x}{\log (6)}} \left (-\log (6)+e^x x \log (x)-\log (6) \log (x)\right )}{x^2 \log ^2(x)}\right ) \, dx}{5 \log (6)} \\ & = \frac {1}{5} \int \frac {20+x^2-x^3+20 \log (x)-x^2 \log (x)+2 x^3 \log (x)}{x^2 \log ^2(x)} \, dx+\frac {4 \int \frac {e^{\frac {e^x}{\log (6)}} \left (-\log (6)+e^x x \log (x)-\log (6) \log (x)\right )}{x^2 \log ^2(x)} \, dx}{\log (6)} \\ & = \frac {4 e^{\frac {e^x}{\log (6)}}}{x \log (x)}+\frac {1}{5} \int \left (\frac {20+x^2-x^3}{x^2 \log ^2(x)}+\frac {20-x^2+2 x^3}{x^2 \log (x)}\right ) \, dx \\ & = \frac {4 e^{\frac {e^x}{\log (6)}}}{x \log (x)}+\frac {1}{5} \int \frac {20+x^2-x^3}{x^2 \log ^2(x)} \, dx+\frac {1}{5} \int \frac {20-x^2+2 x^3}{x^2 \log (x)} \, dx \\ \end{align*}
Time = 0.44 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.97 \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\frac {-20+20 e^{\frac {e^x}{\log (6)}}-x^2+x^3}{5 x \log (x)} \]
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Time = 0.68 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.29
method | result | size |
parallelrisch | \(\frac {\ln \left (6\right ) x^{3}-x^{2} \ln \left (6\right )+20 \,{\mathrm e}^{\frac {{\mathrm e}^{x}}{\ln \left (6\right )}} \ln \left (6\right )-20 \ln \left (6\right )}{5 \ln \left (6\right ) x \ln \left (x \right )}\) | \(44\) |
risch | \(\frac {x^{3} \ln \left (3\right )+x^{3} \ln \left (2\right )-x^{2} \ln \left (3\right )-x^{2} \ln \left (2\right )-20 \ln \left (3\right )-20 \ln \left (2\right )}{5 \left (\ln \left (2\right )+\ln \left (3\right )\right ) x \ln \left (x \right )}+\frac {4 \,{\mathrm e}^{\frac {{\mathrm e}^{x}}{\ln \left (2\right )+\ln \left (3\right )}}}{\ln \left (x \right ) x}\) | \(73\) |
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Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.85 \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\frac {x^{3} - x^{2} + 20 \, e^{\left (\frac {e^{x}}{\log \left (6\right )}\right )} - 20}{5 \, x \log \left (x\right )} \]
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Time = 0.12 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.85 \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\frac {x^{3} - x^{2} - 20}{5 x \log {\left (x \right )}} + \frac {4 e^{\frac {e^{x}}{\log {\left (6 \right )}}}}{x \log {\left (x \right )}} \]
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\[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\int { \frac {{\left (2 \, x^{3} - x^{2} + 20\right )} \log \left (6\right ) \log \left (x\right ) + 20 \, {\left ({\left (x e^{x} - \log \left (6\right )\right )} \log \left (x\right ) - \log \left (6\right )\right )} e^{\left (\frac {e^{x}}{\log \left (6\right )}\right )} - {\left (x^{3} - x^{2} - 20\right )} \log \left (6\right )}{5 \, x^{2} \log \left (6\right ) \log \left (x\right )^{2}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 58 vs. \(2 (28) = 56\).
Time = 0.28 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.71 \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\frac {{\left (x^{3} e^{x} \log \left (6\right ) - x^{2} e^{x} \log \left (6\right ) - 20 \, e^{x} \log \left (6\right ) + 20 \, e^{\left (\frac {x \log \left (6\right ) + e^{x}}{\log \left (6\right )}\right )} \log \left (6\right )\right )} e^{\left (-x\right )}}{5 \, x \log \left (6\right ) \log \left (x\right )} \]
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Timed out. \[ \int \frac {\left (20+x^2-x^3\right ) \log (6)+\left (20-x^2+2 x^3\right ) \log (6) \log (x)+e^{\frac {e^x}{\log (6)}} \left (-20 \log (6)+\left (20 e^x x-20 \log (6)\right ) \log (x)\right )}{5 x^2 \log (6) \log ^2(x)} \, dx=\int \frac {\frac {\ln \left (6\right )\,\left (-x^3+x^2+20\right )}{5}-\frac {{\mathrm {e}}^{\frac {{\mathrm {e}}^x}{\ln \left (6\right )}}\,\left (20\,\ln \left (6\right )+\ln \left (x\right )\,\left (20\,\ln \left (6\right )-20\,x\,{\mathrm {e}}^x\right )\right )}{5}+\frac {\ln \left (6\right )\,\ln \left (x\right )\,\left (2\,x^3-x^2+20\right )}{5}}{x^2\,\ln \left (6\right )\,{\ln \left (x\right )}^2} \,d x \]
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