Integrand size = 19, antiderivative size = 27 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=4 e^{-1/x} x^2 \left (-x^2+(1-x) x^2\right ) \]
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Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.04 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1607, 2258, 2250} \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-20 \Gamma \left (-5,\frac {1}{x}\right )-4 \Gamma \left (-4,\frac {1}{x}\right ) \]
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Rule 1607
Rule 2250
Rule 2258
Rubi steps \begin{align*} \text {integral}& = \int e^{-1/x} (-4-20 x) x^3 \, dx \\ & = \int \left (-4 e^{-1/x} x^3-20 e^{-1/x} x^4\right ) \, dx \\ & = -\left (4 \int e^{-1/x} x^3 \, dx\right )-20 \int e^{-1/x} x^4 \, dx \\ & = -20 \Gamma \left (-5,\frac {1}{x}\right )-4 \Gamma \left (-4,\frac {1}{x}\right ) \\ \end{align*}
Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.01 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-4 \left (5 \Gamma \left (-5,\frac {1}{x}\right )+\Gamma \left (-4,\frac {1}{x}\right )\right ) \]
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Time = 0.15 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.44
method | result | size |
gosper | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
derivativedivides | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
default | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
norman | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
risch | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
parallelrisch | \(-4 x^{5} {\mathrm e}^{-\frac {1}{x}}\) | \(12\) |
meijerg | \(-4 x^{5}+4 x^{4}-2 x^{3}+\frac {2 x^{2}}{3}-\frac {x}{6}+\frac {1}{30}+\frac {x^{5} \left (-\frac {137}{x^{5}}+\frac {300}{x^{4}}-\frac {600}{x^{3}}+\frac {1200}{x^{2}}-\frac {1800}{x}+1440\right )}{360}-\frac {x^{5} \left (\frac {6}{x^{4}}-\frac {6}{x^{3}}+\frac {12}{x^{2}}-\frac {36}{x}+144\right ) {\mathrm e}^{-\frac {1}{x}}}{36}+\frac {x^{4} \left (\frac {125}{x^{4}}-\frac {240}{x^{3}}+\frac {360}{x^{2}}-\frac {480}{x}+360\right )}{360}-\frac {x^{4} \left (-\frac {5}{x^{3}}+\frac {5}{x^{2}}-\frac {10}{x}+30\right ) {\mathrm e}^{-\frac {1}{x}}}{30}\) | \(146\) |
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Time = 0.26 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.41 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-4 \, x^{5} e^{\left (-\frac {1}{x}\right )} \]
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Time = 0.04 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.37 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=- 4 x^{5} e^{- \frac {1}{x}} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.22 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-4 \, \Gamma \left (-4, \frac {1}{x}\right ) - 20 \, \Gamma \left (-5, \frac {1}{x}\right ) \]
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Time = 0.28 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.41 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-4 \, x^{5} e^{\left (-\frac {1}{x}\right )} \]
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Time = 13.95 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.41 \[ \int e^{-1/x} \left (-4 x^3-20 x^4\right ) \, dx=-4\,x^5\,{\mathrm {e}}^{-\frac {1}{x}} \]
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