Integrand size = 92, antiderivative size = 21 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{-1+e^{3+\frac {4}{\log (\log (3+x+2 e x))}}} \]
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Time = 0.93 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.076, Rules used = {6, 12, 2494, 6820, 6847, 2320, 2225} \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{e^{\frac {4}{\log (\log (2 e x+x+3))}+3}-1} \]
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Rule 6
Rule 12
Rule 2225
Rule 2320
Rule 2494
Rule 6820
Rule 6847
Rubi steps \begin{align*} \text {integral}& = \int \frac {(-4-8 e) \exp \left (-1+\exp \left (\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )}{(3+(1+2 e) x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx \\ & = -\left ((4 (1+2 e)) \int \frac {\exp \left (-1+\exp \left (\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )}{(3+(1+2 e) x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx\right ) \\ & = -\left ((4 (1+2 e)) \int \frac {\exp \left (-1+\exp \left (\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}\right )}{(3+(1+2 e) x) \log (3+(1+2 e) x) \log ^2(\log (3+x+2 e x))} \, dx\right ) \\ & = -\left ((4 (1+2 e)) \int \frac {\exp \left (2+e^{3+\frac {4}{\log (\log (3+x+2 e x))}}+\frac {4}{\log (\log (3+x+2 e x))}\right )}{(3+(1+2 e) x) \log (3+(1+2 e) x) \log ^2(\log (3+(1+2 e) x))} \, dx\right ) \\ & = -\left (4 \text {Subst}\left (\int \frac {e^{2+e^{3+\frac {4}{\log (\log (x))}}+\frac {4}{\log (\log (x))}}}{x \log (x) \log ^2(\log (x))} \, dx,x,3+(1+2 e) x\right )\right ) \\ & = -\left (4 \text {Subst}\left (\int \frac {e^{2+e^{3+\frac {4}{\log (x)}}+\frac {4}{\log (x)}}}{x \log ^2(x)} \, dx,x,\log (3+x+2 e x)\right )\right ) \\ & = -\left (4 \text {Subst}\left (\int \frac {e^{2+e^{3+\frac {4}{x}}+\frac {4}{x}}}{x^2} \, dx,x,\log (\log (3+x+2 e x))\right )\right ) \\ & = 4 \text {Subst}\left (\int e^{2+e^{3+4 x}+4 x} \, dx,x,\frac {1}{\log (\log (3+x+2 e x))}\right ) \\ & = \text {Subst}\left (\int e^{2+e^3 x} \, dx,x,e^{\frac {4}{\log (\log (3+x+2 e x))}}\right ) \\ & = e^{-1+e^{3+\frac {4}{\log (\log (3+x+2 e x))}}} \\ \end{align*}
Time = 0.38 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{-1+e^{3+\frac {4}{\log (\log (3+x+2 e x))}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(47\) vs. \(2(20)=40\).
Time = 100.45 (sec) , antiderivative size = 48, normalized size of antiderivative = 2.29
method | result | size |
derivativedivides | \(-\frac {\left (-2 \,{\mathrm e}-1\right ) {\mathrm e}^{{\mathrm e}^{\frac {3 \ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )+4}{\ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )}}-1}}{2 \,{\mathrm e}+1}\) | \(48\) |
default | \(-\frac {\left (-8 \,{\mathrm e}-4\right ) {\mathrm e}^{{\mathrm e}^{\frac {3 \ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )+4}{\ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )}}-1}}{4 \left (2 \,{\mathrm e}+1\right )}\) | \(48\) |
parallelrisch | \(-\frac {\left (-8 \,{\mathrm e}-4\right ) {\mathrm e}^{{\mathrm e}^{\frac {3 \ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )+4}{\ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )}}-1}}{4 \left (2 \,{\mathrm e}+1\right )}\) | \(48\) |
risch | \(\frac {2 \,{\mathrm e}^{{\mathrm e}^{\frac {3 \ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )+4}{\ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )}}-1} {\mathrm e}}{2 \,{\mathrm e}+1}+\frac {{\mathrm e}^{{\mathrm e}^{\frac {3 \ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )+4}{\ln \left (\ln \left (2 x \,{\mathrm e}+3+x \right )\right )}}-1}}{2 \,{\mathrm e}+1}\) | \(85\) |
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Leaf count of result is larger than twice the leaf count of optimal. 96 vs. \(2 (20) = 40\).
Time = 0.33 (sec) , antiderivative size = 96, normalized size of antiderivative = 4.57 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{\left (\frac {e^{\left (\frac {3 \, \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )}\right )} \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 2 \, \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )} - \frac {3 \, \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )}\right )} \]
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Time = 0.66 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.62 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{e^{\frac {3 \log {\left (\log {\left (x + 2 e x + 3 \right )} \right )} + 4}{\log {\left (\log {\left (x + 2 e x + 3 \right )} \right )}}} - 1} \]
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Time = 0.24 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=e^{\left (e^{\left (\frac {4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )} + 3\right )} - 1\right )} \]
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\[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx=\int { -\frac {4 \, {\left (2 \, e + 1\right )} e^{\left (\frac {3 \, \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )} + e^{\left (\frac {3 \, \log \left (\log \left (2 \, x e + x + 3\right )\right ) + 4}{\log \left (\log \left (2 \, x e + x + 3\right )\right )}\right )} - 1\right )}}{{\left (2 \, x e + x + 3\right )} \log \left (2 \, x e + x + 3\right ) \log \left (\log \left (2 \, x e + x + 3\right )\right )^{2}} \,d x } \]
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Time = 13.64 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.05 \[ \int \frac {(-4-8 e) e^{-1+e^{\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}+\frac {4+3 \log (\log (3+x+2 e x))}{\log (\log (3+x+2 e x))}}}{(3+x+2 e x) \log (3+x+2 e x) \log ^2(\log (3+x+2 e x))} \, dx={\mathrm {e}}^{{\mathrm {e}}^{\frac {4}{\ln \left (\ln \left (x+2\,x\,\mathrm {e}+3\right )\right )}}\,{\mathrm {e}}^3}\,{\mathrm {e}}^{-1} \]
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