Integrand size = 98, antiderivative size = 30 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {-2+x-\frac {x}{-6+3 e^{x-x^2} \log (x)}}{3 x} \]
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\[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{2 x} \left (24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)\right )}{9 x^2 \left (2 e^{x^2}-e^x \log (x)\right )^2} \, dx \\ & = \frac {1}{9} \int \frac {e^{2 x} \left (24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)\right )}{x^2 \left (2 e^{x^2}-e^x \log (x)\right )^2} \, dx \\ & = \frac {1}{9} \int \left (\frac {6}{x^2}-\frac {e^{2 x} \log (x) \left (-1-x \log (x)+2 x^2 \log (x)\right )}{2 x \left (-2 e^{x^2}+e^x \log (x)\right )^2}+\frac {e^x \left (-1-x \log (x)+2 x^2 \log (x)\right )}{2 x \left (-2 e^{x^2}+e^x \log (x)\right )}\right ) \, dx \\ & = -\frac {2}{3 x}-\frac {1}{18} \int \frac {e^{2 x} \log (x) \left (-1-x \log (x)+2 x^2 \log (x)\right )}{x \left (-2 e^{x^2}+e^x \log (x)\right )^2} \, dx+\frac {1}{18} \int \frac {e^x \left (-1-x \log (x)+2 x^2 \log (x)\right )}{x \left (-2 e^{x^2}+e^x \log (x)\right )} \, dx \\ & = -\frac {2}{3 x}-\frac {1}{18} \int \left (-\frac {e^{2 x} \log (x)}{x \left (-2 e^{x^2}+e^x \log (x)\right )^2}-\frac {e^{2 x} \log ^2(x)}{\left (-2 e^{x^2}+e^x \log (x)\right )^2}+\frac {2 e^{2 x} x \log ^2(x)}{\left (-2 e^{x^2}+e^x \log (x)\right )^2}\right ) \, dx+\frac {1}{18} \int \left (\frac {e^x}{x \left (2 e^{x^2}-e^x \log (x)\right )}-\frac {e^x \log (x)}{-2 e^{x^2}+e^x \log (x)}+\frac {2 e^x x \log (x)}{-2 e^{x^2}+e^x \log (x)}\right ) \, dx \\ & = -\frac {2}{3 x}+\frac {1}{18} \int \frac {e^x}{x \left (2 e^{x^2}-e^x \log (x)\right )} \, dx+\frac {1}{18} \int \frac {e^{2 x} \log (x)}{x \left (-2 e^{x^2}+e^x \log (x)\right )^2} \, dx+\frac {1}{18} \int \frac {e^{2 x} \log ^2(x)}{\left (-2 e^{x^2}+e^x \log (x)\right )^2} \, dx-\frac {1}{18} \int \frac {e^x \log (x)}{-2 e^{x^2}+e^x \log (x)} \, dx-\frac {1}{9} \int \frac {e^{2 x} x \log ^2(x)}{\left (-2 e^{x^2}+e^x \log (x)\right )^2} \, dx+\frac {1}{9} \int \frac {e^x x \log (x)}{-2 e^{x^2}+e^x \log (x)} \, dx \\ \end{align*}
Time = 0.67 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.10 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {1}{9} \left (-\frac {6}{x}-\frac {e^{x^2}}{-2 e^{x^2}+e^x \log (x)}\right ) \]
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Time = 0.13 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00
method | result | size |
risch | \(-\frac {2}{3 x}+\frac {{\mathrm e}^{x \left (-1+x \right )}}{18 \,{\mathrm e}^{x \left (-1+x \right )}-9 \ln \left (x \right )}\) | \(30\) |
parallelrisch | \(\frac {-x \ln \left (x \right )-12 \ln \left (x \right )+24 \,{\mathrm e}^{x^{2}-x}}{18 x \left (\ln \left (x \right )-2 \,{\mathrm e}^{x^{2}-x}\right )}\) | \(41\) |
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Time = 0.28 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.27 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {{\left (x - 12\right )} e^{\left (x^{2} - x\right )} + 6 \, \log \left (x\right )}{9 \, {\left (2 \, x e^{\left (x^{2} - x\right )} - x \log \left (x\right )\right )}} \]
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Time = 0.08 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.67 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {\log {\left (x \right )}}{36 e^{x^{2} - x} - 18 \log {\left (x \right )}} - \frac {2}{3 x} \]
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Time = 0.25 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.10 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=-\frac {{\left (x + 12\right )} e^{x} \log \left (x\right ) - 24 \, e^{\left (x^{2}\right )}}{18 \, {\left (x e^{x} \log \left (x\right ) - 2 \, x e^{\left (x^{2}\right )}\right )}} \]
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Time = 0.32 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.33 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {x \log \left (x\right ) - 24 \, e^{\left (x^{2} - x\right )} + 12 \, \log \left (x\right )}{18 \, {\left (2 \, x e^{\left (x^{2} - x\right )} - x \log \left (x\right )\right )}} \]
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Time = 13.48 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {24 e^{-2 x+2 x^2}+e^{-x+x^2} x+e^{-x+x^2} \left (-24+x^2-2 x^3\right ) \log (x)+6 \log ^2(x)}{36 e^{-2 x+2 x^2} x^2-36 e^{-x+x^2} x^2 \log (x)+9 x^2 \log ^2(x)} \, dx=\frac {\ln \left (x\right )}{18\,\left (2\,{\mathrm {e}}^{x^2-x}-\ln \left (x\right )\right )}-\frac {2}{3\,x} \]
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