Integrand size = 22, antiderivative size = 10 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {-7+x}{1+\log (x)} \]
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Time = 0.13 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.70, number of steps used = 12, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6820, 6874, 2395, 2334, 2336, 2209, 2339, 30} \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x}{\log (x)+1}-\frac {7}{\log (x)+1} \]
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Rule 30
Rule 2209
Rule 2334
Rule 2336
Rule 2339
Rule 2395
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {7+x \log (x)}{x (1+\log (x))^2} \, dx \\ & = \int \left (\frac {7-x}{x (1+\log (x))^2}+\frac {1}{1+\log (x)}\right ) \, dx \\ & = \int \frac {7-x}{x (1+\log (x))^2} \, dx+\int \frac {1}{1+\log (x)} \, dx \\ & = \int \left (-\frac {1}{(1+\log (x))^2}+\frac {7}{x (1+\log (x))^2}\right ) \, dx+\text {Subst}\left (\int \frac {e^x}{1+x} \, dx,x,\log (x)\right ) \\ & = \frac {\operatorname {ExpIntegralEi}(1+\log (x))}{e}+7 \int \frac {1}{x (1+\log (x))^2} \, dx-\int \frac {1}{(1+\log (x))^2} \, dx \\ & = \frac {\operatorname {ExpIntegralEi}(1+\log (x))}{e}+\frac {x}{1+\log (x)}+7 \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,1+\log (x)\right )-\int \frac {1}{1+\log (x)} \, dx \\ & = \frac {\operatorname {ExpIntegralEi}(1+\log (x))}{e}-\frac {7}{1+\log (x)}+\frac {x}{1+\log (x)}-\text {Subst}\left (\int \frac {e^x}{1+x} \, dx,x,\log (x)\right ) \\ & = -\frac {7}{1+\log (x)}+\frac {x}{1+\log (x)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {-7+x}{1+\log (x)} \]
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Time = 0.25 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.10
method | result | size |
norman | \(\frac {-7+x}{\ln \left (x \right )+1}\) | \(11\) |
risch | \(\frac {-7+x}{\ln \left (x \right )+1}\) | \(11\) |
parallelrisch | \(\frac {-7+x}{\ln \left (x \right )+1}\) | \(11\) |
default | \(\frac {x}{\ln \left (x \right )+1}-\frac {7}{\ln \left (x \right )+1}\) | \(18\) |
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Time = 0.23 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x - 7}{\log \left (x\right ) + 1} \]
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Time = 0.04 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.70 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x - 7}{\log {\left (x \right )} + 1} \]
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Time = 0.21 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.70 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x}{\log \left (x\right ) + 1} - \frac {7}{\log \left (x\right ) + 1} \]
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Time = 0.29 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x - 7}{\log \left (x\right ) + 1} \]
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Time = 12.46 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {7+x \log (x)}{x+2 x \log (x)+x \log ^2(x)} \, dx=\frac {x-7}{\ln \left (x\right )+1} \]
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