Integrand size = 9, antiderivative size = 21 \[ \int \frac {-1+2 x}{x} \, dx=-2+2 x+(i \pi +\log (5))^2-\log (2 x) \]
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Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.38, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {45} \[ \int \frac {-1+2 x}{x} \, dx=2 x-\log (x) \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (2-\frac {1}{x}\right ) \, dx \\ & = 2 x-\log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.38 \[ \int \frac {-1+2 x}{x} \, dx=2 x-\log (x) \]
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Time = 0.03 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.43
method | result | size |
default | \(2 x -\ln \left (x \right )\) | \(9\) |
norman | \(2 x -\ln \left (x \right )\) | \(9\) |
risch | \(2 x -\ln \left (x \right )\) | \(9\) |
parallelrisch | \(2 x -\ln \left (x \right )\) | \(9\) |
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none
Time = 0.24 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.38 \[ \int \frac {-1+2 x}{x} \, dx=2 \, x - \log \left (x\right ) \]
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Time = 0.03 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.24 \[ \int \frac {-1+2 x}{x} \, dx=2 x - \log {\left (x \right )} \]
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none
Time = 0.17 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.38 \[ \int \frac {-1+2 x}{x} \, dx=2 \, x - \log \left (x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.43 \[ \int \frac {-1+2 x}{x} \, dx=2 \, x - \log \left ({\left | x \right |}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.38 \[ \int \frac {-1+2 x}{x} \, dx=2\,x-\ln \left (x\right ) \]
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