Integrand size = 50, antiderivative size = 19 \[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=e^{-\frac {27}{2} e^{-x} (-25+x) x} x^2 \]
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\[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=\int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx \\ & = \frac {1}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx \\ & = \frac {1}{2} \int \left (4 e^{x-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x+675 e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^2-729 e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^3+27 e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^4\right ) \, dx \\ & = 2 \int e^{x-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x \, dx+\frac {27}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^4 \, dx+\frac {675}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^2 \, dx-\frac {729}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^3 \, dx \\ & = 2 \int e^{-\frac {27}{2} e^{-x} (-25+x) x} x \, dx+\frac {27}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^4 \, dx+\frac {675}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^2 \, dx-\frac {729}{2} \int e^{-\frac {1}{2} e^{-x} x \left (-675+2 e^x+27 x\right )} x^3 \, dx \\ \end{align*}
Time = 0.35 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=e^{-\frac {27}{2} e^{-x} (-25+x) x} x^2 \]
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Time = 0.14 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.84
method | result | size |
risch | \(x^{2} {\mathrm e}^{-\frac {27 x \left (x -25\right ) {\mathrm e}^{-x}}{2}}\) | \(16\) |
parallelrisch | \(x^{2} {\mathrm e}^{-\frac {27 x \left (x -25\right ) {\mathrm e}^{-x}}{2}}\) | \(18\) |
norman | \(x^{2} {\mathrm e}^{-\frac {\left (27 x^{2}-675 x \right ) {\mathrm e}^{-x}}{2}}\) | \(23\) |
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.42 \[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=x^{2} e^{\left (-\frac {1}{2} \, {\left (27 \, x^{2} + 2 \, x e^{x} - 675 \, x\right )} e^{\left (-x\right )} + x\right )} \]
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Time = 0.11 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=x^{2} e^{- \left (\frac {27 x^{2}}{2} - \frac {675 x}{2}\right ) e^{- x}} \]
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\[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=\int { \frac {1}{2} \, {\left (27 \, x^{4} - 729 \, x^{3} + 675 \, x^{2} + 4 \, x e^{x}\right )} e^{\left (-\frac {27}{2} \, {\left (x^{2} - 25 \, x\right )} e^{\left (-x\right )} - x\right )} \,d x } \]
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\[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=\int { \frac {1}{2} \, {\left (27 \, x^{4} - 729 \, x^{3} + 675 \, x^{2} + 4 \, x e^{x}\right )} e^{\left (-\frac {27}{2} \, {\left (x^{2} - 25 \, x\right )} e^{\left (-x\right )} - x\right )} \,d x } \]
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Time = 12.92 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.16 \[ \int \frac {1}{2} e^{-x-\frac {1}{2} e^{-x} \left (-675 x+27 x^2\right )} \left (4 e^x x+675 x^2-729 x^3+27 x^4\right ) \, dx=x^2\,{\mathrm {e}}^{\frac {675\,x\,{\mathrm {e}}^{-x}}{2}}\,{\mathrm {e}}^{-\frac {27\,x^2\,{\mathrm {e}}^{-x}}{2}} \]
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