Integrand size = 117, antiderivative size = 27 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\frac {2}{x}+x-\log \left (-4+\frac {1}{5} e^{\frac {x}{\log (\log (x))}}+\log (x)\right ) \]
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\[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-\left (\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))\right )-e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{x^2 \left (20-e^{\frac {x}{\log (\log (x))}}-5 \log (x)\right ) \log (x) \log ^2(\log (x))} \, dx \\ & = \int \left (\frac {5 \left (4 x-x \log (x)-4 x \log (x) \log (\log (x))+x \log ^2(x) \log (\log (x))-\log (x) \log ^2(\log (x))\right )}{x \log (x) \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))}+\frac {x^2-x^2 \log (x) \log (\log (x))-2 \log (x) \log ^2(\log (x))+x^2 \log (x) \log ^2(\log (x))}{x^2 \log (x) \log ^2(\log (x))}\right ) \, dx \\ & = 5 \int \frac {4 x-x \log (x)-4 x \log (x) \log (\log (x))+x \log ^2(x) \log (\log (x))-\log (x) \log ^2(\log (x))}{x \log (x) \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))} \, dx+\int \frac {x^2-x^2 \log (x) \log (\log (x))-2 \log (x) \log ^2(\log (x))+x^2 \log (x) \log ^2(\log (x))}{x^2 \log (x) \log ^2(\log (x))} \, dx \\ & = 5 \int \left (-\frac {1}{x \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right )}-\frac {1}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))}+\frac {4}{\log (x) \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))}-\frac {4}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log (\log (x))}+\frac {\log (x)}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log (\log (x))}\right ) \, dx+\int \left (1-\frac {2}{x^2}+\frac {1}{\log (x) \log ^2(\log (x))}-\frac {1}{\log (\log (x))}\right ) \, dx \\ & = \frac {2}{x}+x-5 \int \frac {1}{x \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right )} \, dx-5 \int \frac {1}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))} \, dx+5 \int \frac {\log (x)}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log (\log (x))} \, dx+20 \int \frac {1}{\log (x) \left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log ^2(\log (x))} \, dx-20 \int \frac {1}{\left (-20+e^{\frac {x}{\log (\log (x))}}+5 \log (x)\right ) \log (\log (x))} \, dx+\int \frac {1}{\log (x) \log ^2(\log (x))} \, dx-\int \frac {1}{\log (\log (x))} \, dx \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\frac {2}{x}+x-\log \left (20-e^{\frac {x}{\log (\log (x))}}-5 \log (x)\right ) \]
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Time = 6.09 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04
method | result | size |
risch | \(\frac {x^{2}+2}{x}-\ln \left (5 \ln \left (x \right )+{\mathrm e}^{\frac {x}{\ln \left (\ln \left (x \right )\right )}}-20\right )\) | \(28\) |
parallelrisch | \(-\frac {\ln \left (\ln \left (x \right )-4+\frac {{\mathrm e}^{\frac {x}{\ln \left (\ln \left (x \right )\right )}}}{5}\right ) x -x^{2}-2}{x}\) | \(30\) |
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Time = 0.24 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\frac {x^{2} - x \log \left (e^{\frac {x}{\log \left (\log \left (x\right )\right )}} + 5 \, \log \left (x\right ) - 20\right ) + 2}{x} \]
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Time = 0.24 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.74 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=x - \log {\left (e^{\frac {x}{\log {\left (\log {\left (x \right )} \right )}}} + 5 \log {\left (x \right )} - 20 \right )} + \frac {2}{x} \]
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Time = 0.25 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\frac {x^{2} + 2}{x} - \log \left (e^{\frac {x}{\log \left (\log \left (x\right )\right )}} + 5 \, \log \left (x\right ) - 20\right ) \]
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\[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=\int { \frac {5 \, {\left ({\left (x^{2} - 2\right )} \log \left (x\right )^{2} - {\left (4 \, x^{2} + x - 8\right )} \log \left (x\right )\right )} \log \left (\log \left (x\right )\right )^{2} - {\left (x^{2} \log \left (x\right ) \log \left (\log \left (x\right )\right ) - {\left (x^{2} - 2\right )} \log \left (x\right ) \log \left (\log \left (x\right )\right )^{2} - x^{2}\right )} e^{\frac {x}{\log \left (\log \left (x\right )\right )}}}{x^{2} e^{\frac {x}{\log \left (\log \left (x\right )\right )}} \log \left (x\right ) \log \left (\log \left (x\right )\right )^{2} + 5 \, {\left (x^{2} \log \left (x\right )^{2} - 4 \, x^{2} \log \left (x\right )\right )} \log \left (\log \left (x\right )\right )^{2}} \,d x } \]
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Time = 13.85 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89 \[ \int \frac {\left (\left (40-5 x-20 x^2\right ) \log (x)+\left (-10+5 x^2\right ) \log ^2(x)\right ) \log ^2(\log (x))+e^{\frac {x}{\log (\log (x))}} \left (x^2-x^2 \log (x) \log (\log (x))+\left (-2+x^2\right ) \log (x) \log ^2(\log (x))\right )}{e^{\frac {x}{\log (\log (x))}} x^2 \log (x) \log ^2(\log (x))+\left (-20 x^2 \log (x)+5 x^2 \log ^2(x)\right ) \log ^2(\log (x))} \, dx=x-\ln \left (5\,\ln \left (x\right )+{\mathrm {e}}^{\frac {x}{\ln \left (\ln \left (x\right )\right )}}-20\right )+\frac {2}{x} \]
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