Integrand size = 260, antiderivative size = 35 \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=-1+x-\left (e^{1-\frac {5}{x}}+\log \left (\log \left (\frac {1}{4} \log \left (x-\left (4+x^2\right )^2\right )\right )\right )\right )^2 \]
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\[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=\int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{x^2 \left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx \\ & = \int \left (-\frac {10 e^{2-\frac {10}{x}}}{x^2}+\frac {16}{16-x+8 x^2+x^4}-\frac {x}{16-x+8 x^2+x^4}+\frac {8 x^2}{16-x+8 x^2+x^4}+\frac {x^4}{16-x+8 x^2+x^4}+\frac {2 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}-\frac {32 x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}-\frac {8 x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}-\frac {2 e^{1-\frac {5}{x}} \left (-x^2+16 x^3+4 x^5+80 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-5 x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+40 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+5 x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{x^2 \left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}\right ) \, dx \\ & = 2 \int \frac {\log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-2 \int \frac {e^{1-\frac {5}{x}} \left (-x^2+16 x^3+4 x^5+80 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-5 x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+40 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+5 x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{x^2 \left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+8 \int \frac {x^2}{16-x+8 x^2+x^4} \, dx-8 \int \frac {x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-10 \int \frac {e^{2-\frac {10}{x}}}{x^2} \, dx+16 \int \frac {1}{16-x+8 x^2+x^4} \, dx-32 \int \frac {x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-\int \frac {x}{16-x+8 x^2+x^4} \, dx+\int \frac {x^4}{16-x+8 x^2+x^4} \, dx \\ & = -e^{2-\frac {10}{x}}-\frac {2 e^{1-\frac {5}{x}} \left (16 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+8 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}+2 \int \frac {\log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+8 \int \frac {x^2}{16-x+8 x^2+x^4} \, dx-8 \int \frac {x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+16 \int \frac {1}{16-x+8 x^2+x^4} \, dx-32 \int \frac {x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-\int \frac {x}{16-x+8 x^2+x^4} \, dx+\int \left (1-\frac {16-x+8 x^2}{16-x+8 x^2+x^4}\right ) \, dx \\ & = -e^{2-\frac {10}{x}}+x-\frac {2 e^{1-\frac {5}{x}} \left (16 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+8 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}+2 \int \frac {\log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+8 \int \frac {x^2}{16-x+8 x^2+x^4} \, dx-8 \int \frac {x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+16 \int \frac {1}{16-x+8 x^2+x^4} \, dx-32 \int \frac {x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-\int \frac {x}{16-x+8 x^2+x^4} \, dx-\int \frac {16-x+8 x^2}{16-x+8 x^2+x^4} \, dx \\ & = -e^{2-\frac {10}{x}}+x-\frac {2 e^{1-\frac {5}{x}} \left (16 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+8 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}+2 \int \frac {\log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+8 \int \frac {x^2}{16-x+8 x^2+x^4} \, dx-8 \int \frac {x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx+16 \int \frac {1}{16-x+8 x^2+x^4} \, dx-32 \int \frac {x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-\int \frac {x}{16-x+8 x^2+x^4} \, dx-\int \left (\frac {16}{16-x+8 x^2+x^4}-\frac {x}{16-x+8 x^2+x^4}+\frac {8 x^2}{16-x+8 x^2+x^4}\right ) \, dx \\ & = -e^{2-\frac {10}{x}}+x-\frac {2 e^{1-\frac {5}{x}} \left (16 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-x \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+8 x^2 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )+x^4 \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )}+2 \int \frac {\log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-8 \int \frac {x^3 \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx-32 \int \frac {x \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16-x+8 x^2+x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.94 \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=-e^{2-\frac {10}{x}}+x-2 e^{1-\frac {5}{x}} \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )-\log ^2\left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \]
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Time = 0.07 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.83
\[-{\mathrm e}^{\frac {2 x -10}{x}}-2 \,{\mathrm e}^{\frac {-5+x}{x}} \ln \left (\ln \left (\frac {\ln \left (-x^{4}-8 x^{2}+x -16\right )}{4}\right )\right )-{\ln \left (\ln \left (\frac {\ln \left (-x^{4}-8 x^{2}+x -16\right )}{4}\right )\right )}^{2}+x\]
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Time = 0.25 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.80 \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=-2 \, e^{\left (\frac {x - 5}{x}\right )} \log \left (\log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )\right ) - \log \left (\log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )\right )^{2} + x - e^{\left (\frac {2 \, {\left (x - 5\right )}}{x}\right )} \]
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Timed out. \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 81 vs. \(2 (32) = 64\).
Time = 0.34 (sec) , antiderivative size = 81, normalized size of antiderivative = 2.31 \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=-{\left (e^{\frac {10}{x}} \log \left (-2 \, \log \left (2\right ) + \log \left (\log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )\right )^{2} - x e^{\frac {10}{x}} + 2 \, e^{\left (\frac {5}{x} + 1\right )} \log \left (-2 \, \log \left (2\right ) + \log \left (\log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )\right ) + e^{2}\right )} e^{\left (-\frac {10}{x}\right )} \]
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\[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=\int { \frac {{\left (x^{6} + 8 \, x^{4} - x^{3} + 16 \, x^{2} - 10 \, {\left (x^{4} + 8 \, x^{2} - x + 16\right )} e^{\left (\frac {2 \, {\left (x - 5\right )}}{x}\right )}\right )} \log \left (-x^{4} - 8 \, x^{2} + x - 16\right ) \log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right ) - 2 \, {\left (4 \, x^{5} + 16 \, x^{3} - x^{2}\right )} e^{\left (\frac {x - 5}{x}\right )} - 2 \, {\left (4 \, x^{5} + 5 \, {\left (x^{4} + 8 \, x^{2} - x + 16\right )} e^{\left (\frac {x - 5}{x}\right )} \log \left (-x^{4} - 8 \, x^{2} + x - 16\right ) \log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right ) + 16 \, x^{3} - x^{2}\right )} \log \left (\log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )\right )}{{\left (x^{6} + 8 \, x^{4} - x^{3} + 16 \, x^{2}\right )} \log \left (-x^{4} - 8 \, x^{2} + x - 16\right ) \log \left (\frac {1}{4} \, \log \left (-x^{4} - 8 \, x^{2} + x - 16\right )\right )} \,d x } \]
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Timed out. \[ \int \frac {e^{\frac {-5+x}{x}} \left (2 x^2-32 x^3-8 x^5\right )+\left (16 x^2-x^3+8 x^4+x^6+e^{\frac {2 (-5+x)}{x}} \left (-160+10 x-80 x^2-10 x^4\right )\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )+\left (2 x^2-32 x^3-8 x^5+e^{\frac {-5+x}{x}} \left (-160+10 x-80 x^2-10 x^4\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right ) \log \left (\log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )\right )}{\left (16 x^2-x^3+8 x^4+x^6\right ) \log \left (-16+x-8 x^2-x^4\right ) \log \left (\frac {1}{4} \log \left (-16+x-8 x^2-x^4\right )\right )} \, dx=\int -\frac {{\mathrm {e}}^{\frac {x-5}{x}}\,\left (8\,x^5+32\,x^3-2\,x^2\right )+\ln \left (\ln \left (\frac {\ln \left (-x^4-8\,x^2+x-16\right )}{4}\right )\right )\,\left (32\,x^3-2\,x^2+8\,x^5+{\mathrm {e}}^{\frac {x-5}{x}}\,\ln \left (\frac {\ln \left (-x^4-8\,x^2+x-16\right )}{4}\right )\,\ln \left (-x^4-8\,x^2+x-16\right )\,\left (10\,x^4+80\,x^2-10\,x+160\right )\right )-\ln \left (\frac {\ln \left (-x^4-8\,x^2+x-16\right )}{4}\right )\,\ln \left (-x^4-8\,x^2+x-16\right )\,\left (16\,x^2-{\mathrm {e}}^{\frac {2\,\left (x-5\right )}{x}}\,\left (10\,x^4+80\,x^2-10\,x+160\right )-x^3+8\,x^4+x^6\right )}{\ln \left (\frac {\ln \left (-x^4-8\,x^2+x-16\right )}{4}\right )\,\ln \left (-x^4-8\,x^2+x-16\right )\,\left (x^6+8\,x^4-x^3+16\,x^2\right )} \,d x \]
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