Integrand size = 86, antiderivative size = 23 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=\frac {13}{4}-x+\frac {5}{\log \left (-4-\frac {3}{x}+x+x^2\right )} \]
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Time = 0.16 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.87, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.023, Rules used = {6820, 6818} \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=\frac {5}{\log \left (x^2+x-\frac {3}{x}-4\right )}-x \]
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Rule 6818
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \left (-1-\frac {5 \left (3+x^2+2 x^3\right )}{x \left (-3-4 x+x^2+x^3\right ) \log ^2\left (-4-\frac {3}{x}+x+x^2\right )}\right ) \, dx \\ & = -x-5 \int \frac {3+x^2+2 x^3}{x \left (-3-4 x+x^2+x^3\right ) \log ^2\left (-4-\frac {3}{x}+x+x^2\right )} \, dx \\ & = -x+\frac {5}{\log \left (-4-\frac {3}{x}+x+x^2\right )} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.87 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=-x+\frac {5}{\log \left (-4-\frac {3}{x}+x+x^2\right )} \]
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Time = 0.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.09
method | result | size |
default | \(-x +\frac {5}{\ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}\) | \(25\) |
risch | \(-x +\frac {5}{\ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}\) | \(25\) |
parts | \(-x +\frac {5}{\ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}\) | \(25\) |
norman | \(\frac {5-x \ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}{\ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}\) | \(41\) |
parallelrisch | \(-\frac {-5+x \ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )-2 \ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}{\ln \left (\frac {x^{3}+x^{2}-4 x -3}{x}\right )}\) | \(59\) |
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Time = 0.24 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.74 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=-\frac {x \log \left (\frac {x^{3} + x^{2} - 4 \, x - 3}{x}\right ) - 5}{\log \left (\frac {x^{3} + x^{2} - 4 \, x - 3}{x}\right )} \]
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Time = 0.06 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=- x + \frac {5}{\log {\left (\frac {x^{3} + x^{2} - 4 x - 3}{x} \right )}} \]
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Time = 0.23 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.83 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=-\frac {x \log \left (x^{3} + x^{2} - 4 \, x - 3\right ) - x \log \left (x\right ) - 5}{\log \left (x^{3} + x^{2} - 4 \, x - 3\right ) - \log \left (x\right )} \]
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Time = 0.53 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=-x + \frac {5}{\log \left (\frac {x^{3} + x^{2} - 4 \, x - 3}{x}\right )} \]
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Time = 13.34 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.26 \[ \int \frac {-15-5 x^2-10 x^3+\left (3 x+4 x^2-x^3-x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )}{\left (-3 x-4 x^2+x^3+x^4\right ) \log ^2\left (\frac {-3-4 x+x^2+x^3}{x}\right )} \, dx=\frac {5}{\ln \left (-\frac {-x^3-x^2+4\,x+3}{x}\right )}-x \]
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