Integrand size = 229, antiderivative size = 27 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\log (x)}{\log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \]
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\[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\frac {\left (-2 x^2-2 e^2 (-1+x) x \left (125+25 e+x^2\right )\right ) \log (x)}{\left (125+25 e+x^2\right ) \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}+\log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}{x \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ & = \int \left (\frac {2 \left (25 e^2 (5+e)-\left (1+125 e^2+25 e^3\right ) x+e^2 x^2-e^2 x^3\right ) \log (x)}{\left (125+25 e+x^2\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}+\frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}\right ) \, dx \\ & = 2 \int \frac {\left (25 e^2 (5+e)-\left (1+125 e^2+25 e^3\right ) x+e^2 x^2-e^2 x^3\right ) \log (x)}{\left (125+25 e+x^2\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx+\int \frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ & = 2 \int \left (\frac {e^2 \log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}-\frac {e^2 x \log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}-\frac {x \log (x)}{\left (125+25 e+x^2\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}\right ) \, dx+\int \frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ & = -\left (2 \int \frac {x \log (x)}{\left (125+25 e+x^2\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx\right )+\left (2 e^2\right ) \int \frac {\log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx-\left (2 e^2\right ) \int \frac {x \log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx+\int \frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ & = -\left (2 \int \left (-\frac {\log (x)}{2 \left (5 i \sqrt {5+e}-x\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}+\frac {\log (x)}{2 \left (5 i \sqrt {5+e}+x\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )}\right ) \, dx\right )+\left (2 e^2\right ) \int \frac {\log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx-\left (2 e^2\right ) \int \frac {x \log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx+\int \frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ & = \left (2 e^2\right ) \int \frac {\log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx-\left (2 e^2\right ) \int \frac {x \log (x)}{\left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx+\int \frac {\log (x)}{\left (5 i \sqrt {5+e}-x\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx-\int \frac {\log (x)}{\left (5 i \sqrt {5+e}+x\right ) \left (e^2-2 e^2 x+e^2 x^2+\log \left (5+e+\frac {x^2}{25}\right )\right ) \log ^2\left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx+\int \frac {1}{x \log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \, dx \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\log (x)}{\log \left (e^2 (-1+x)^2+\log \left (5+e+\frac {x^2}{25}\right )\right )} \]
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Time = 7.14 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.07
\[\frac {\ln \left (x \right )}{\ln \left (\ln \left ({\mathrm e}+\frac {x^{2}}{25}+5\right )+\left (x^{2}-2 x +1\right ) {\mathrm e}^{2}\right )}\]
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Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\log \left (x\right )}{\log \left ({\left (x^{2} - 2 \, x + 1\right )} e^{2} + \log \left (\frac {1}{25} \, x^{2} + e + 5\right )\right )} \]
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Time = 3.76 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\log {\left (x \right )}}{\log {\left (\left (x^{2} - 2 x + 1\right ) e^{2} + \log {\left (\frac {x^{2}}{25} + e + 5 \right )} \right )}} \]
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Time = 0.37 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.26 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\log \left (x\right )}{\log \left (x^{2} e^{2} - 2 \, x e^{2} + e^{2} - 2 \, \log \left (5\right ) + \log \left (x^{2} + 25 \, e + 125\right )\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1134 vs. \(2 (25) = 50\).
Time = 1.34 (sec) , antiderivative size = 1134, normalized size of antiderivative = 42.00 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\text {Too large to display} \]
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Time = 18.14 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04 \[ \int \frac {\left (-2 x^2+e^2 \left (250 x-250 x^2+2 x^3-2 x^4+e \left (50 x-50 x^2\right )\right )\right ) \log (x)+\left (e^2 \left (125-250 x+126 x^2-2 x^3+x^4+e \left (25-50 x+25 x^2\right )\right )+\left (125+25 e+x^2\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log \left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )}{\left (e^2 \left (125 x-250 x^2+126 x^3-2 x^4+x^5+e \left (25 x-50 x^2+25 x^3\right )\right )+\left (125 x+25 e x+x^3\right ) \log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right ) \log ^2\left (e^2 \left (1-2 x+x^2\right )+\log \left (\frac {1}{25} \left (125+25 e+x^2\right )\right )\right )} \, dx=\frac {\ln \left (x\right )}{\ln \left (\ln \left (\frac {x^2}{25}+\mathrm {e}+5\right )+{\mathrm {e}}^2\,\left (x^2-2\,x+1\right )\right )} \]
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