Integrand size = 164, antiderivative size = 29 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=\frac {\left (x-\log (3)+x^2 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )\right )^2}{x^2} \]
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\[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=\int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{x^3 \left (e^2+x\right )} \, dx \\ & = \int \frac {2 \left (x-\log (3)+x^2 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )\right ) \left (\left (e^2+x\right ) \log (3)-2 e^2 x^2 \log \left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \left (e^2+x\right ) \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )\right )}{x^3 \left (e^2+x\right )} \, dx \\ & = 2 \int \frac {\left (x-\log (3)+x^2 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )\right ) \left (\left (e^2+x\right ) \log (3)-2 e^2 x^2 \log \left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \left (e^2+x\right ) \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )\right )}{x^3 \left (e^2+x\right )} \, dx \\ & = 2 \int \left (\frac {(x-\log (3)) \log (3)}{x^3}+\frac {2 e^2 (-x+\log (3)) \log \left (12+\frac {12 e^2}{x}\right )}{x \left (e^2+x\right )}+\log ^2\left (12+\frac {12 e^2}{x}\right )+\frac {2 e^2 x \log ^3\left (12+\frac {12 e^2}{x}\right )}{-e^2-x}+x \log ^4\left (12+\frac {12 e^2}{x}\right )\right ) \, dx \\ & = 2 \int \log ^2\left (12+\frac {12 e^2}{x}\right ) \, dx+2 \int x \log ^4\left (12+\frac {12 e^2}{x}\right ) \, dx+\left (4 e^2\right ) \int \frac {(-x+\log (3)) \log \left (12+\frac {12 e^2}{x}\right )}{x \left (e^2+x\right )} \, dx+\left (4 e^2\right ) \int \frac {x \log ^3\left (12+\frac {12 e^2}{x}\right )}{-e^2-x} \, dx+(2 \log (3)) \int \frac {x-\log (3)}{x^3} \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-2 \text {Subst}\left (\int \frac {\log ^4\left (12+12 e^2 x\right )}{x^3} \, dx,x,\frac {1}{x}\right )+\left (4 e^2\right ) \int \frac {\log \left (12+\frac {12 e^2}{x}\right )}{x} \, dx+\left (4 e^2\right ) \int \left (-\log ^3\left (12+\frac {12 e^2}{x}\right )+\frac {e^2 \log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x}\right ) \, dx+\left (4 e^2\right ) \int \frac {(-x+\log (3)) \log \left (\frac {12 e^2+12 x}{x}\right )}{x \left (e^2+x\right )} \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )-\left (4 e^2\right ) \int \log ^3\left (12+\frac {12 e^2}{x}\right ) \, dx-\left (4 e^2\right ) \int \frac {(-x+\log (3)) \log (x)}{x \left (e^2+x\right )} \, dx+\left (4 e^2\right ) \int \frac {(-x+\log (3)) \log \left (12 e^2+12 x\right )}{x \left (e^2+x\right )} \, dx-\left (4 e^2\right ) \text {Subst}\left (\int \frac {\log \left (12+12 e^2 x\right )}{x} \, dx,x,\frac {1}{x}\right )-\left (48 e^2\right ) \text {Subst}\left (\int \frac {\log ^3\left (12+12 e^2 x\right )}{x^2 \left (12+12 e^2 x\right )} \, dx,x,\frac {1}{x}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx-\left (4 e^2 \left (-\log (x)+\log \left (12 e^2+12 x\right )-\log \left (\frac {12 e^2+12 x}{x}\right )\right )\right ) \int \frac {-x+\log (3)}{x \left (e^2+x\right )} \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )-4 \text {Subst}\left (\int \frac {\log ^3(x)}{x \left (-\frac {1}{e^2}+\frac {x}{12 e^2}\right )^2} \, dx,x,12+\frac {12 e^2}{x}\right )-\left (4 e^2\right ) \int \left (\frac {\left (-e^2-\log (3)\right ) \log (x)}{e^2 \left (e^2+x\right )}+\frac {\log (3) \log (x)}{e^2 x}\right ) \, dx+\left (4 e^2\right ) \int \left (\frac {\left (-e^2-\log (3)\right ) \log \left (12 e^2+12 x\right )}{e^2 \left (e^2+x\right )}+\frac {\log (3) \log \left (12 e^2+12 x\right )}{e^2 x}\right ) \, dx-\left (4 e^2\right ) \text {Subst}\left (\int \frac {\log \left (1+e^2 x\right )}{x} \, dx,x,\frac {1}{x}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx-\left (12 e^4\right ) \int \frac {\log ^2\left (12+\frac {12 e^2}{x}\right )}{x} \, dx-\left (4 e^2 \left (-\log (x)+\log \left (12 e^2+12 x\right )-\log \left (\frac {12 e^2+12 x}{x}\right )\right )\right ) \int \left (\frac {-e^2-\log (3)}{e^2 \left (e^2+x\right )}+\frac {\log (3)}{e^2 x}\right ) \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 \log (3) \log (x) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )-4 \left (e^2+\log (3)\right ) \log \left (e^2+x\right ) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )+4 e^2 \operatorname {PolyLog}\left (2,-\frac {e^2}{x}\right )-\frac {1}{3} \text {Subst}\left (\int \frac {\log ^3(x)}{\left (-\frac {1}{e^2}+\frac {x}{12 e^2}\right )^2} \, dx,x,12+\frac {12 e^2}{x}\right )+\left (4 e^2\right ) \text {Subst}\left (\int \frac {\log ^3(x)}{x \left (-\frac {1}{e^2}+\frac {x}{12 e^2}\right )} \, dx,x,12+\frac {12 e^2}{x}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx+\left (12 e^4\right ) \text {Subst}\left (\int \frac {\log ^2\left (12+12 e^2 x\right )}{x} \, dx,x,\frac {1}{x}\right )-(4 \log (3)) \int \frac {\log (x)}{x} \, dx+(4 \log (3)) \int \frac {\log \left (12 e^2+12 x\right )}{x} \, dx+\left (4 \left (e^2+\log (3)\right )\right ) \int \frac {\log (x)}{e^2+x} \, dx-\left (4 \left (e^2+\log (3)\right )\right ) \int \frac {\log \left (12 e^2+12 x\right )}{e^2+x} \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+4 \log (3) (2+\log (12)) \log (x)-2 \log (3) \log ^2(x)+12 e^4 \log \left (-\frac {e^2}{x}\right ) \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 e^2 \left (1+\frac {e^2}{x}\right ) x \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 e^4 \log \left (1-\frac {1}{1+\frac {e^2}{x}}\right ) \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 \log (3) \log (x) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )-4 \left (e^2+\log (3)\right ) \log \left (e^2+x\right ) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )+4 \left (e^2+\log (3)\right ) \log (x) \log \left (1+\frac {x}{e^2}\right )+4 e^2 \operatorname {PolyLog}\left (2,-\frac {e^2}{x}\right )-e^2 \text {Subst}\left (\int \frac {\log ^2(x)}{-\frac {1}{e^2}+\frac {x}{12 e^2}} \, dx,x,12+\frac {12 e^2}{x}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx-\left (12 e^4\right ) \text {Subst}\left (\int \frac {\log \left (1-\frac {12}{x}\right ) \log ^2(x)}{x} \, dx,x,12+\frac {12 e^2}{x}\right )-\left (288 e^6\right ) \text {Subst}\left (\int \frac {\log \left (-e^2 x\right ) \log \left (12+12 e^2 x\right )}{12+12 e^2 x} \, dx,x,\frac {1}{x}\right )+(4 \log (3)) \int \frac {\log \left (1+\frac {x}{e^2}\right )}{x} \, dx-\frac {1}{3} \left (e^2+\log (3)\right ) \text {Subst}\left (\int \frac {12 \log (x)}{x} \, dx,x,12 e^2+12 x\right )-\left (4 \left (e^2+\log (3)\right )\right ) \int \frac {\log \left (1+\frac {x}{e^2}\right )}{x} \, dx \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+4 \log (3) (2+\log (12)) \log (x)-2 \log (3) \log ^2(x)+4 e^2 \left (1+\frac {e^2}{x}\right ) x \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 e^4 \log \left (1-\frac {1}{1+\frac {e^2}{x}}\right ) \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 \log (3) \log (x) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )-4 \left (e^2+\log (3)\right ) \log \left (e^2+x\right ) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )+4 \left (e^2+\log (3)\right ) \log (x) \log \left (1+\frac {x}{e^2}\right )-12 e^4 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right ) \operatorname {PolyLog}\left (2,\frac {1}{1+\frac {e^2}{x}}\right )+4 e^2 \operatorname {PolyLog}\left (2,-\frac {e^2}{x}\right )-4 \log (3) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )+4 \left (e^2+\log (3)\right ) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx+\left (24 e^4\right ) \text {Subst}\left (\int \frac {\log \left (1-\frac {x}{12}\right ) \log (x)}{x} \, dx,x,12+\frac {12 e^2}{x}\right )-\left (24 e^4\right ) \text {Subst}\left (\int \frac {\log (x) \log \left (-e^2 \left (-\frac {1}{e^2}+\frac {x}{12 e^2}\right )\right )}{x} \, dx,x,12+\frac {12 e^2}{x}\right )+\left (24 e^4\right ) \text {Subst}\left (\int \frac {\log (x) \operatorname {PolyLog}\left (2,\frac {12}{x}\right )}{x} \, dx,x,12+\frac {12 e^2}{x}\right )-\left (4 \left (e^2+\log (3)\right )\right ) \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,12 e^2+12 x\right ) \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+4 \log (3) (2+\log (12)) \log (x)-2 \log (3) \log ^2(x)-2 \left (e^2+\log (3)\right ) \log ^2\left (12 \left (e^2+x\right )\right )+4 e^2 \left (1+\frac {e^2}{x}\right ) x \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 e^4 \log \left (1-\frac {1}{1+\frac {e^2}{x}}\right ) \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 \log (3) \log (x) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )-4 \left (e^2+\log (3)\right ) \log \left (e^2+x\right ) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )+4 \left (e^2+\log (3)\right ) \log (x) \log \left (1+\frac {x}{e^2}\right )-12 e^4 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right ) \operatorname {PolyLog}\left (2,\frac {1}{1+\frac {e^2}{x}}\right )+4 e^2 \operatorname {PolyLog}\left (2,-\frac {e^2}{x}\right )-4 \log (3) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )+4 \left (e^2+\log (3)\right ) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )-24 e^4 \log \left (\frac {12 \left (e^2+x\right )}{x}\right ) \operatorname {PolyLog}\left (3,\frac {1}{1+\frac {e^2}{x}}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx+\left (24 e^4\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (3,\frac {12}{x}\right )}{x} \, dx,x,12+\frac {12 e^2}{x}\right ) \\ & = \frac {(x-\log (3))^2}{x^2}+2 \left (e^2+x\right ) \log ^2\left (12+\frac {12 e^2}{x}\right )-4 e^2 \left (e^2+x\right ) \log ^3\left (12+\frac {12 e^2}{x}\right )+4 e^2 \log (12) \log (x)+4 \log (3) (2+\log (12)) \log (x)-2 \log (3) \log ^2(x)-2 \left (e^2+\log (3)\right ) \log ^2\left (12 \left (e^2+x\right )\right )+4 e^2 \left (1+\frac {e^2}{x}\right ) x \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 e^4 \log \left (1-\frac {1}{1+\frac {e^2}{x}}\right ) \log ^3\left (\frac {12 \left (e^2+x\right )}{x}\right )+x^2 \log ^4\left (\frac {12 \left (e^2+x\right )}{x}\right )+4 \log (3) \log (x) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )-4 \left (e^2+\log (3)\right ) \log \left (e^2+x\right ) \left (\log (x)+\log \left (\frac {12 \left (e^2+x\right )}{x}\right )-\log \left (12 e^2+12 x\right )\right )+4 \left (e^2+\log (3)\right ) \log (x) \log \left (1+\frac {x}{e^2}\right )-12 e^4 \log ^2\left (\frac {12 \left (e^2+x\right )}{x}\right ) \operatorname {PolyLog}\left (2,\frac {1}{1+\frac {e^2}{x}}\right )+4 e^2 \operatorname {PolyLog}\left (2,-\frac {e^2}{x}\right )-4 \log (3) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )+4 \left (e^2+\log (3)\right ) \operatorname {PolyLog}\left (2,-\frac {x}{e^2}\right )-24 e^4 \log \left (\frac {12 \left (e^2+x\right )}{x}\right ) \operatorname {PolyLog}\left (3,\frac {1}{1+\frac {e^2}{x}}\right )-24 e^4 \operatorname {PolyLog}\left (4,\frac {1}{1+\frac {e^2}{x}}\right )+\left (4 e^4\right ) \int \frac {\log ^3\left (12+\frac {12 e^2}{x}\right )}{e^2+x} \, dx \\ \end{align*}
\[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=\int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. \(66\) vs. \(2(28)=56\).
Time = 4.18 (sec) , antiderivative size = 67, normalized size of antiderivative = 2.31
method | result | size |
parallelrisch | \(\frac {\ln \left (\frac {12 \,{\mathrm e}^{2}+12 x}{x}\right )^{4} x^{4}-2 \ln \left (3\right ) x^{2} \ln \left (\frac {12 \,{\mathrm e}^{2}+12 x}{x}\right )^{2}+2 \ln \left (\frac {12 \,{\mathrm e}^{2}+12 x}{x}\right )^{2} x^{3}+\ln \left (3\right )^{2}-2 x \ln \left (3\right )}{x^{2}}\) | \(67\) |
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Time = 0.25 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.90 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=\frac {x^{4} \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{4} + 2 \, {\left (x^{3} - x^{2} \log \left (3\right )\right )} \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2} - 2 \, x \log \left (3\right ) + \log \left (3\right )^{2}}{x^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 53 vs. \(2 (26) = 52\).
Time = 0.15 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.83 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=x^{2} \log {\left (\frac {12 x + 12 e^{2}}{x} \right )}^{4} + \left (2 x - 2 \log {\left (3 \right )}\right ) \log {\left (\frac {12 x + 12 e^{2}}{x} \right )}^{2} + \frac {- 2 x \log {\left (3 \right )} + \log {\left (3 \right )}^{2}}{x^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 528 vs. \(2 (28) = 56\).
Time = 0.34 (sec) , antiderivative size = 528, normalized size of antiderivative = 18.21 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=x^{2} \log \left (x + e^{2}\right )^{4} - 4 \, x^{2} {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (x\right )^{3} + x^{2} \log \left (x\right )^{4} + {\left (2 \, e^{\left (-6\right )} \log \left (x + e^{2}\right ) - 2 \, e^{\left (-6\right )} \log \left (x\right ) - \frac {{\left (2 \, x - e^{2}\right )} e^{\left (-4\right )}}{x^{2}}\right )} e^{2} \log \left (3\right )^{2} + 4 \, {\left (x^{2} {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} - x^{2} \log \left (x\right )\right )} \log \left (x + e^{2}\right )^{3} - 4 \, {\left (e^{\left (-2\right )} \log \left (x + e^{2}\right ) - e^{\left (-2\right )} \log \left (x\right )\right )} e^{2} \log \left (3\right ) \log \left (\frac {12 \, e^{2}}{x} + 12\right ) + {\left (\log \left (3\right )^{4} + 8 \, \log \left (3\right )^{3} \log \left (2\right ) + 24 \, \log \left (3\right )^{2} \log \left (2\right )^{2} + 32 \, \log \left (3\right ) \log \left (2\right )^{3} + 16 \, \log \left (2\right )^{4}\right )} x^{2} + 2 \, {\left (e^{\left (-4\right )} \log \left (x + e^{2}\right ) - e^{\left (-4\right )} \log \left (x\right ) - \frac {e^{\left (-2\right )}}{x}\right )} e^{2} \log \left (3\right ) - 2 \, {\left (e^{\left (-4\right )} \log \left (x + e^{2}\right ) - e^{\left (-4\right )} \log \left (x\right ) - \frac {e^{\left (-2\right )}}{x}\right )} \log \left (3\right )^{2} - 2 \, {\left (6 \, x^{2} {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (x\right ) - 3 \, x^{2} \log \left (x\right )^{2} - 3 \, {\left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2}\right )} x^{2} - x\right )} \log \left (x + e^{2}\right )^{2} + 2 \, {\left (3 \, {\left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2}\right )} x^{2} + x\right )} \log \left (x\right )^{2} + 2 \, {\left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2}\right )} x - 2 \, {\left (e^{\left (-2\right )} \log \left (x + e^{2}\right ) - e^{\left (-2\right )} \log \left (x\right )\right )} \log \left (3\right ) + 2 \, {\left (\log \left (x + e^{2}\right )^{2} - 2 \, \log \left (x + e^{2}\right ) \log \left (x\right ) + \log \left (x\right )^{2}\right )} \log \left (3\right ) + 4 \, {\left (3 \, x^{2} {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} \log \left (x\right )^{2} - x^{2} \log \left (x\right )^{3} + {\left (\log \left (3\right )^{3} + 6 \, \log \left (3\right )^{2} \log \left (2\right ) + 12 \, \log \left (3\right ) \log \left (2\right )^{2} + 8 \, \log \left (2\right )^{3}\right )} x^{2} + x {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )} - {\left (3 \, {\left (\log \left (3\right )^{2} + 4 \, \log \left (3\right ) \log \left (2\right ) + 4 \, \log \left (2\right )^{2}\right )} x^{2} + x\right )} \log \left (x\right )\right )} \log \left (x + e^{2}\right ) - 4 \, {\left ({\left (\log \left (3\right )^{3} + 6 \, \log \left (3\right )^{2} \log \left (2\right ) + 12 \, \log \left (3\right ) \log \left (2\right )^{2} + 8 \, \log \left (2\right )^{3}\right )} x^{2} + x {\left (\log \left (3\right ) + 2 \, \log \left (2\right )\right )}\right )} \log \left (x\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 256 vs. \(2 (28) = 56\).
Time = 0.39 (sec) , antiderivative size = 256, normalized size of antiderivative = 8.83 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=\frac {{\left (e^{8} \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{4} - \frac {2 \, {\left (x + e^{2}\right )}^{2} e^{4} \log \left (3\right ) \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2}}{x^{2}} + \frac {4 \, {\left (x + e^{2}\right )} e^{4} \log \left (3\right ) \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2}}{x} - 2 \, e^{4} \log \left (3\right ) \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2} + \frac {2 \, {\left (x + e^{2}\right )} e^{6} \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2}}{x} - 2 \, e^{6} \log \left (\frac {12 \, {\left (x + e^{2}\right )}}{x}\right )^{2} - \frac {2 \, {\left (x + e^{2}\right )}^{3} e^{2} \log \left (3\right )}{x^{3}} + \frac {4 \, {\left (x + e^{2}\right )}^{2} e^{2} \log \left (3\right )}{x^{2}} - \frac {2 \, {\left (x + e^{2}\right )} e^{2} \log \left (3\right )}{x} + \frac {{\left (x + e^{2}\right )}^{4} \log \left (3\right )^{2}}{x^{4}} - \frac {4 \, {\left (x + e^{2}\right )}^{3} \log \left (3\right )^{2}}{x^{3}} + \frac {5 \, {\left (x + e^{2}\right )}^{2} \log \left (3\right )^{2}}{x^{2}} - \frac {2 \, {\left (x + e^{2}\right )} \log \left (3\right )^{2}}{x}\right )} e^{\left (-2\right )}}{\frac {{\left (x + e^{2}\right )}^{2} e^{2}}{x^{2}} - \frac {2 \, {\left (x + e^{2}\right )} e^{2}}{x} + e^{2}} \]
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Time = 14.82 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.90 \[ \int \frac {\left (2 e^2 x+2 x^2\right ) \log (3)+\left (-2 e^2-2 x\right ) \log ^2(3)+\left (-4 e^2 x^3+4 e^2 x^2 \log (3)\right ) \log \left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^3+2 x^4\right ) \log ^2\left (\frac {12 e^2+12 x}{x}\right )-4 e^2 x^4 \log ^3\left (\frac {12 e^2+12 x}{x}\right )+\left (2 e^2 x^4+2 x^5\right ) \log ^4\left (\frac {12 e^2+12 x}{x}\right )}{e^2 x^3+x^4} \, dx=-\frac {\left (\ln \left (3\right )-x^2\,{\ln \left (\frac {12\,x+12\,{\mathrm {e}}^2}{x}\right )}^2\right )\,\left (x^2\,{\ln \left (\frac {12\,x+12\,{\mathrm {e}}^2}{x}\right )}^2+2\,x-\ln \left (3\right )\right )}{x^2} \]
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