Integrand size = 62, antiderivative size = 24 \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=-5+2 e^{-\frac {\left (3-\frac {19 x}{20}\right )^2}{\log ^2(x)}} x \log (x) \]
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Leaf count is larger than twice the leaf count of optimal. \(81\) vs. \(2(24)=48\).
Time = 0.15 (sec) , antiderivative size = 81, normalized size of antiderivative = 3.38, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.032, Rules used = {12, 2326} \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=\frac {2 e^{-\frac {361 x^2-2280 x+3600}{400 \log ^2(x)}} \left (361 x^2+19 \left (60 x-19 x^2\right ) \log (x)-2280 x+3600\right )}{\left (\frac {361 x^2-2280 x+3600}{x \log ^3(x)}+\frac {19 (60-19 x)}{\log ^2(x)}\right ) \log ^2(x)} \]
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Rule 12
Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {1}{100} \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{\log ^2(x)} \, dx \\ & = \frac {2 e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+19 \left (60 x-19 x^2\right ) \log (x)\right )}{\left (\frac {3600-2280 x+361 x^2}{x \log ^3(x)}+\frac {19 (60-19 x)}{\log ^2(x)}\right ) \log ^2(x)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=2 e^{-\frac {(60-19 x)^2}{400 \log ^2(x)}} x \log (x) \]
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Time = 0.39 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.83
method | result | size |
risch | \(2 x \ln \left (x \right ) {\mathrm e}^{-\frac {\left (19 x -60\right )^{2}}{400 \ln \left (x \right )^{2}}}\) | \(20\) |
parallelrisch | \(2 x \ln \left (x \right ) {\mathrm e}^{-\frac {361 x^{2}-2280 x +3600}{400 \ln \left (x \right )^{2}}}\) | \(25\) |
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Time = 0.25 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=2 \, x e^{\left (-\frac {361 \, x^{2} - 2280 \, x + 3600}{400 \, \log \left (x\right )^{2}}\right )} \log \left (x\right ) \]
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Time = 1.63 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=2 x e^{- \frac {\frac {361 x^{2}}{400} - \frac {57 x}{10} + 9}{\log {\left (x \right )}^{2}}} \log {\left (x \right )} \]
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\[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=\int { \frac {{\left (200 \, \log \left (x\right )^{3} + 361 \, x^{2} - 19 \, {\left (19 \, x^{2} - 60 \, x\right )} \log \left (x\right ) + 200 \, \log \left (x\right )^{2} - 2280 \, x + 3600\right )} e^{\left (-\frac {361 \, x^{2} - 2280 \, x + 3600}{400 \, \log \left (x\right )^{2}}\right )}}{100 \, \log \left (x\right )^{2}} \,d x } \]
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\[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=\int { \frac {{\left (200 \, \log \left (x\right )^{3} + 361 \, x^{2} - 19 \, {\left (19 \, x^{2} - 60 \, x\right )} \log \left (x\right ) + 200 \, \log \left (x\right )^{2} - 2280 \, x + 3600\right )} e^{\left (-\frac {361 \, x^{2} - 2280 \, x + 3600}{400 \, \log \left (x\right )^{2}}\right )}}{100 \, \log \left (x\right )^{2}} \,d x } \]
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Time = 13.34 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {e^{-\frac {3600-2280 x+361 x^2}{400 \log ^2(x)}} \left (3600-2280 x+361 x^2+\left (1140 x-361 x^2\right ) \log (x)+200 \log ^2(x)+200 \log ^3(x)\right )}{100 \log ^2(x)} \, dx=2\,x\,{\mathrm {e}}^{-\frac {361\,x^2-2280\,x+3600}{400\,{\ln \left (x\right )}^2}}\,\ln \left (x\right ) \]
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