Integrand size = 47, antiderivative size = 30 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {2}{5} \left (x+\frac {1}{4} \left (-x+\frac {6+\log (x)}{1+\frac {e^5}{x}}\right )\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(69\) vs. \(2(30)=60\).
Time = 0.10 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.30, number of steps used = 12, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.128, Rules used = {27, 12, 6874, 45, 2351, 31} \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {3 x}{10}-\frac {e^5 \left (7-6 e^5\right )}{10 \left (x+e^5\right )}-\frac {3 e^{10}}{5 \left (x+e^5\right )}+\frac {e^5}{10 \left (x+e^5\right )}+\frac {x \log (x)}{10 \left (x+e^5\right )} \]
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Rule 12
Rule 27
Rule 31
Rule 45
Rule 2351
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 \left (e^5+x\right )^2} \, dx \\ & = \frac {1}{10} \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{\left (e^5+x\right )^2} \, dx \\ & = \frac {1}{10} \int \left (\frac {3 e^{10}}{\left (e^5+x\right )^2}+\frac {x}{\left (e^5+x\right )^2}+\frac {3 x^2}{\left (e^5+x\right )^2}+\frac {e^5 (7+6 x)}{\left (e^5+x\right )^2}+\frac {e^5 \log (x)}{\left (e^5+x\right )^2}\right ) \, dx \\ & = -\frac {3 e^{10}}{10 \left (e^5+x\right )}+\frac {1}{10} \int \frac {x}{\left (e^5+x\right )^2} \, dx+\frac {3}{10} \int \frac {x^2}{\left (e^5+x\right )^2} \, dx+\frac {1}{10} e^5 \int \frac {7+6 x}{\left (e^5+x\right )^2} \, dx+\frac {1}{10} e^5 \int \frac {\log (x)}{\left (e^5+x\right )^2} \, dx \\ & = -\frac {3 e^{10}}{10 \left (e^5+x\right )}+\frac {x \log (x)}{10 \left (e^5+x\right )}-\frac {1}{10} \int \frac {1}{e^5+x} \, dx+\frac {1}{10} \int \left (-\frac {e^5}{\left (e^5+x\right )^2}+\frac {1}{e^5+x}\right ) \, dx+\frac {3}{10} \int \left (1+\frac {e^{10}}{\left (e^5+x\right )^2}-\frac {2 e^5}{e^5+x}\right ) \, dx+\frac {1}{10} e^5 \int \left (\frac {7-6 e^5}{\left (e^5+x\right )^2}+\frac {6}{e^5+x}\right ) \, dx \\ & = \frac {3 x}{10}+\frac {e^5}{10 \left (e^5+x\right )}-\frac {3 e^{10}}{5 \left (e^5+x\right )}-\frac {e^5 \left (7-6 e^5\right )}{10 \left (e^5+x\right )}+\frac {x \log (x)}{10 \left (e^5+x\right )} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {1}{10} \left (3 x+\log (x)-\frac {e^5 (6+\log (x))}{e^5+x}\right ) \]
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Time = 0.62 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.97
method | result | size |
norman | \(\frac {\frac {3 x^{2}}{10}+\frac {x \ln \left (x \right )}{10}-\frac {3 \,{\mathrm e}^{10}}{10}-\frac {3 \,{\mathrm e}^{5}}{5}}{{\mathrm e}^{5}+x}\) | \(29\) |
parallelrisch | \(-\frac {3 \,{\mathrm e}^{10}-3 x^{2}-x \ln \left (x \right )+6 \,{\mathrm e}^{5}}{10 \left ({\mathrm e}^{5}+x \right )}\) | \(30\) |
risch | \(-\frac {{\mathrm e}^{5} \ln \left (x \right )}{10 \left ({\mathrm e}^{5}+x \right )}+\frac {{\mathrm e}^{5} \ln \left (x \right )+3 x \,{\mathrm e}^{5}+x \ln \left (x \right )+3 x^{2}-6 \,{\mathrm e}^{5}}{10 \,{\mathrm e}^{5}+10 x}\) | \(46\) |
parts | \(\frac {\frac {3 x^{2}}{10}-\frac {3 \left ({\mathrm e}^{5}\right )^{2}}{10}-\frac {3 \,{\mathrm e}^{5}}{5}}{{\mathrm e}^{5}+x}+\frac {\ln \left ({\mathrm e}^{5}+x \right )}{10}+\frac {{\mathrm e}^{5} \left (\frac {\ln \left (x \right ) \left (\ln \left (\frac {{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )-\ln \left (\frac {{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )\right )}{2 \sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}+\frac {\operatorname {dilog}\left (\frac {{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )-\operatorname {dilog}\left (\frac {{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )}{2 \sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )}{10}\) | \(211\) |
default | \(\frac {3 x^{2}-3 \left ({\mathrm e}^{5}\right )^{2}-6 \,{\mathrm e}^{5}}{10 \,{\mathrm e}^{5}+10 x}+\frac {\ln \left ({\mathrm e}^{5}+x \right )}{10}+\frac {{\mathrm e}^{5} \left (\frac {\ln \left (x \right ) \left (\ln \left (\frac {{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )-\ln \left (\frac {{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )\right )}{2 \sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}+\frac {\operatorname {dilog}\left (\frac {{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}-\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )-\operatorname {dilog}\left (\frac {{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}+x}{{\mathrm e}^{5}+\sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )}{2 \sqrt {\left ({\mathrm e}^{5}\right )^{2}-{\mathrm e}^{10}}}\right )}{10}\) | \(212\) |
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Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {3 \, x^{2} + 3 \, {\left (x - 2\right )} e^{5} + x \log \left (x\right )}{10 \, {\left (x + e^{5}\right )}} \]
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Time = 0.14 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.23 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {3 x}{10} + \frac {\log {\left (x \right )}}{10} - \frac {e^{5} \log {\left (x \right )}}{10 x + 10 e^{5}} - \frac {3 e^{5}}{5 x + 5 e^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 87 vs. \(2 (20) = 40\).
Time = 0.20 (sec) , antiderivative size = 87, normalized size of antiderivative = 2.90 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=-\frac {1}{10} \, {\left (e^{\left (-5\right )} \log \left (x + e^{5}\right ) - e^{\left (-5\right )} \log \left (x\right ) + \frac {\log \left (x\right )}{x + e^{5}}\right )} e^{5} + \frac {3}{5} \, {\left (\frac {e^{5}}{x + e^{5}} + \log \left (x + e^{5}\right )\right )} e^{5} - \frac {3}{5} \, e^{5} \log \left (x + e^{5}\right ) + \frac {3}{10} \, x - \frac {3 \, e^{10}}{5 \, {\left (x + e^{5}\right )}} - \frac {3 \, e^{5}}{5 \, {\left (x + e^{5}\right )}} + \frac {1}{10} \, \log \left (x + e^{5}\right ) \]
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.90 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {3 \, x^{2} + 3 \, x e^{5} + x \log \left (x\right ) - 6 \, e^{5}}{10 \, {\left (x + e^{5}\right )}} \]
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Time = 13.07 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.77 \[ \int \frac {3 e^{10}+x+3 x^2+e^5 (7+6 x)+e^5 \log (x)}{10 e^{10}+20 e^5 x+10 x^2} \, dx=\frac {x\,\left (3\,x+3\,{\mathrm {e}}^5+\ln \left (x\right )+6\right )}{10\,\left (x+{\mathrm {e}}^5\right )} \]
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