Integrand size = 168, antiderivative size = 26 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=2-3 x+\frac {\log (5)}{\log \left (\log \left (2+\left (4+e^2-x\right )^2+\log (4)\right )\right )} \]
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Leaf count is larger than twice the leaf count of optimal. \(265\) vs. \(2(26)=52\).
Time = 0.66 (sec) , antiderivative size = 265, normalized size of antiderivative = 10.19, number of steps used = 19, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {6820, 6860, 717, 648, 632, 210, 642, 6818} \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=-\frac {48 \left (4+e^2\right ) \arctan \left (\frac {2 \left (-x+e^2+4\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}-\frac {12 e^4 \arctan \left (\frac {2 \left (-x+e^2+4\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}+\frac {6 \left (18+e^4+\log (4)\right ) \arctan \left (\frac {2 \left (-x+e^2+4\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}+\frac {6 \left (14+8 e^2+e^4-\log (4)\right ) \arctan \left (\frac {2 \left (-x+e^2+4\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}-3 \left (4+e^2\right ) \log \left (x^2-2 \left (4+e^2\right ) x+e^4+8 e^2+18+\log (4)\right )+3 e^2 \log \left (x^2-2 \left (4+e^2\right ) x+e^4+8 e^2+18+\log (4)\right )+12 \log \left (x^2-2 \left (4+e^2\right ) x+e^4+8 e^2+18+\log (4)\right )+\frac {\log (5)}{\log \left (\log \left (x^2-2 \left (4+e^2\right ) x+e^4+8 e^2+18+\log (4)\right )\right )}-3 x \]
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Rule 210
Rule 632
Rule 642
Rule 648
Rule 717
Rule 6818
Rule 6820
Rule 6860
Rubi steps \begin{align*} \text {integral}& = \int \frac {6 e^2 (-4+x)+24 x-3 x^2-54 \left (1+\frac {1}{18} \left (e^4+\log (4)\right )\right )+\frac {2 \left (4+e^2-x\right ) \log (5)}{\log \left (18+e^4-2 e^2 (-4+x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4-2 e^2 (-4+x)-8 x+x^2+\log (4)\right )\right )}}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx \\ & = \int \left (\frac {3 x^2}{-18-8 e^2-e^4+2 \left (4+e^2\right ) x-x^2-\log (4)}+\frac {6 e^2 (-4+x)}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)}+\frac {24 x}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)}+\frac {3 \left (-18-e^4-\log (4)\right )}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)}+\frac {2 \left (4+e^2-x\right ) \log (5)}{\left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right ) \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )}\right ) \, dx \\ & = 3 \int \frac {x^2}{-18-8 e^2-e^4+2 \left (4+e^2\right ) x-x^2-\log (4)} \, dx+24 \int \frac {x}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+\left (6 e^2\right ) \int \frac {-4+x}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx-\left (3 \left (18+e^4+\log (4)\right )\right ) \int \frac {1}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+(2 \log (5)) \int \frac {4+e^2-x}{\left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right ) \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )} \, dx \\ & = -3 x+\frac {\log (5)}{\log \left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )}-3 \int \frac {18+8 e^2+e^4-2 \left (4+e^2\right ) x+\log (4)}{-18-8 e^2-e^4+2 \left (4+e^2\right ) x-x^2-\log (4)} \, dx+12 \int \frac {-2 \left (4+e^2\right )+2 x}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+\left (3 e^2\right ) \int \frac {-2 \left (4+e^2\right )+2 x}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+\left (6 e^4\right ) \int \frac {1}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+\left (24 \left (4+e^2\right )\right ) \int \frac {1}{18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)} \, dx+\left (6 \left (18+e^4+\log (4)\right )\right ) \text {Subst}\left (\int \frac {1}{-x^2-4 (2+\log (4))} \, dx,x,-2 \left (4+e^2\right )+2 x\right ) \\ & = -3 x+\frac {6 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right ) \left (18+e^4+\log (4)\right )}{\sqrt {8+\log (256)}}+12 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+3 e^2 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+\frac {\log (5)}{\log \left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )}-\left (12 e^4\right ) \text {Subst}\left (\int \frac {1}{-x^2-4 (2+\log (4))} \, dx,x,-2 \left (4+e^2\right )+2 x\right )-\left (3 \left (4+e^2\right )\right ) \int \frac {2 \left (4+e^2\right )-2 x}{-18-8 e^2-e^4+2 \left (4+e^2\right ) x-x^2-\log (4)} \, dx-\left (48 \left (4+e^2\right )\right ) \text {Subst}\left (\int \frac {1}{-x^2-4 (2+\log (4))} \, dx,x,-2 \left (4+e^2\right )+2 x\right )+\left (3 \left (14+8 e^2+e^4-\log (4)\right )\right ) \int \frac {1}{-18-8 e^2-e^4+2 \left (4+e^2\right ) x-x^2-\log (4)} \, dx \\ & = -3 x-\frac {12 e^4 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}-\frac {48 \left (4+e^2\right ) \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}+\frac {6 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right ) \left (18+e^4+\log (4)\right )}{\sqrt {8+\log (256)}}+12 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+3 e^2 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )-3 \left (4+e^2\right ) \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+\frac {\log (5)}{\log \left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )}-\left (6 \left (14+8 e^2+e^4-\log (4)\right )\right ) \text {Subst}\left (\int \frac {1}{-x^2-4 (2+\log (4))} \, dx,x,2 \left (4+e^2\right )-2 x\right ) \\ & = -3 x-\frac {12 e^4 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}-\frac {48 \left (4+e^2\right ) \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right )}{\sqrt {8+\log (256)}}+\frac {6 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right ) \left (14+8 e^2+e^4-\log (4)\right )}{\sqrt {8+\log (256)}}+\frac {6 \arctan \left (\frac {2 \left (4+e^2-x\right )}{\sqrt {8+\log (256)}}\right ) \left (18+e^4+\log (4)\right )}{\sqrt {8+\log (256)}}+12 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+3 e^2 \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )-3 \left (4+e^2\right ) \log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )+\frac {\log (5)}{\log \left (\log \left (18+8 e^2+e^4-2 \left (4+e^2\right ) x+x^2+\log (4)\right )\right )} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.23 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=-3 x+\frac {\log (5)}{\log \left (\log \left (18+e^4-2 e^2 (-4+x)-8 x+x^2+\log (4)\right )\right )} \]
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Time = 2.94 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31
method | result | size |
risch | \(-3 x +\frac {\ln \left (5\right )}{\ln \left (\ln \left (2 \ln \left (2\right )+{\mathrm e}^{4}+\left (-2 x +8\right ) {\mathrm e}^{2}+x^{2}-8 x +18\right )\right )}\) | \(34\) |
default | \(-3 x +\frac {\ln \left (5\right )}{\ln \left (\ln \left (-2 \,{\mathrm e}^{2} x +x^{2}+8 \,{\mathrm e}^{2}+{\mathrm e}^{4}+2 \ln \left (2\right )-8 x +18\right )\right )}\) | \(37\) |
parts | \(-3 x +\frac {\ln \left (5\right )}{\ln \left (\ln \left (-2 \,{\mathrm e}^{2} x +x^{2}+8 \,{\mathrm e}^{2}+{\mathrm e}^{4}+2 \ln \left (2\right )-8 x +18\right )\right )}\) | \(37\) |
parallelrisch | \(-\frac {12 \,{\mathrm e}^{2} \ln \left (\ln \left (2 \ln \left (2\right )+{\mathrm e}^{4}+\left (-2 x +8\right ) {\mathrm e}^{2}+x^{2}-8 x +18\right )\right )+3 x \ln \left (\ln \left (2 \ln \left (2\right )+{\mathrm e}^{4}+\left (-2 x +8\right ) {\mathrm e}^{2}+x^{2}-8 x +18\right )\right )-\ln \left (5\right )+48 \ln \left (\ln \left (2 \ln \left (2\right )+{\mathrm e}^{4}+\left (-2 x +8\right ) {\mathrm e}^{2}+x^{2}-8 x +18\right )\right )}{\ln \left (\ln \left (2 \ln \left (2\right )+{\mathrm e}^{4}+\left (-2 x +8\right ) {\mathrm e}^{2}+x^{2}-8 x +18\right )\right )}\) | \(123\) |
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Leaf count of result is larger than twice the leaf count of optimal. 58 vs. \(2 (27) = 54\).
Time = 0.26 (sec) , antiderivative size = 58, normalized size of antiderivative = 2.23 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=-\frac {3 \, x \log \left (\log \left (x^{2} - 2 \, {\left (x - 4\right )} e^{2} - 8 \, x + e^{4} + 2 \, \log \left (2\right ) + 18\right )\right ) - \log \left (5\right )}{\log \left (\log \left (x^{2} - 2 \, {\left (x - 4\right )} e^{2} - 8 \, x + e^{4} + 2 \, \log \left (2\right ) + 18\right )\right )} \]
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Time = 0.13 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=- 3 x + \frac {\log {\left (5 \right )}}{\log {\left (\log {\left (x^{2} - 8 x + \left (8 - 2 x\right ) e^{2} + 2 \log {\left (2 \right )} + 18 + e^{4} \right )} \right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 60 vs. \(2 (27) = 54\).
Time = 0.34 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.31 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=-\frac {3 \, x \log \left (\log \left (x^{2} - 2 \, x {\left (e^{2} + 4\right )} + e^{4} + 8 \, e^{2} + 2 \, \log \left (2\right ) + 18\right )\right ) - \log \left (5\right )}{\log \left (\log \left (x^{2} - 2 \, x {\left (e^{2} + 4\right )} + e^{4} + 8 \, e^{2} + 2 \, \log \left (2\right ) + 18\right )\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 62 vs. \(2 (27) = 54\).
Time = 1.74 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.38 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=-\frac {3 \, x \log \left (\log \left (x^{2} - 2 \, x e^{2} - 8 \, x + e^{4} + 8 \, e^{2} + 2 \, \log \left (2\right ) + 18\right )\right ) - \log \left (5\right )}{\log \left (\log \left (x^{2} - 2 \, x e^{2} - 8 \, x + e^{4} + 8 \, e^{2} + 2 \, \log \left (2\right ) + 18\right )\right )} \]
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Time = 13.44 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31 \[ \int \frac {\left (8+2 e^2-2 x\right ) \log (5)+\left (-54-3 e^4+24 x-3 x^2+e^2 (-24+6 x)-3 \log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )}{\left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right ) \log ^2\left (\log \left (18+e^4+e^2 (8-2 x)-8 x+x^2+\log (4)\right )\right )} \, dx=\frac {\ln \left (5\right )}{\ln \left (\ln \left (8\,{\mathrm {e}}^2-8\,x+{\mathrm {e}}^4+2\,\ln \left (2\right )-2\,x\,{\mathrm {e}}^2+x^2+18\right )\right )}-3\,x \]
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