Integrand size = 117, antiderivative size = 28 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\frac {2 x+\frac {1+x}{-1+x}}{7+2 x-\frac {\log (x)}{x^2}} \]
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\[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {x \left (-1+2 x-3 x^2+4 x^3-32 x^4+12 x^5+\left (2-4 x+10 x^2-6 x^3\right ) \log (x)\right )}{(1-x)^2 \left (x^2 (7+2 x)-\log (x)\right )^2} \, dx \\ & = \int \left (-\frac {x \left (-1+x+12 x^2-8 x^3+22 x^4+12 x^5\right )}{(-1+x) \left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {2 x \left (-1+2 x-5 x^2+3 x^3\right )}{(-1+x)^2 \left (7 x^2+2 x^3-\log (x)\right )}\right ) \, dx \\ & = 2 \int \frac {x \left (-1+2 x-5 x^2+3 x^3\right )}{(-1+x)^2 \left (7 x^2+2 x^3-\log (x)\right )} \, dx-\int \frac {x \left (-1+x+12 x^2-8 x^3+22 x^4+12 x^5\right )}{(-1+x) \left (7 x^2+2 x^3-\log (x)\right )^2} \, dx \\ & = 2 \int \left (\frac {1}{7 x^2+2 x^3-\log (x)}-\frac {1}{(-1+x)^2 \left (7 x^2+2 x^3-\log (x)\right )}+\frac {x}{7 x^2+2 x^3-\log (x)}+\frac {3 x^2}{7 x^2+2 x^3-\log (x)}\right ) \, dx-\int \left (\frac {38}{\left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {38}{(-1+x) \left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {39 x}{\left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {38 x^2}{\left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {26 x^3}{\left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {34 x^4}{\left (7 x^2+2 x^3-\log (x)\right )^2}+\frac {12 x^5}{\left (7 x^2+2 x^3-\log (x)\right )^2}\right ) \, dx \\ & = 2 \int \frac {1}{7 x^2+2 x^3-\log (x)} \, dx-2 \int \frac {1}{(-1+x)^2 \left (7 x^2+2 x^3-\log (x)\right )} \, dx+2 \int \frac {x}{7 x^2+2 x^3-\log (x)} \, dx+6 \int \frac {x^2}{7 x^2+2 x^3-\log (x)} \, dx-12 \int \frac {x^5}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-26 \int \frac {x^3}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-34 \int \frac {x^4}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-38 \int \frac {1}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-38 \int \frac {1}{(-1+x) \left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-38 \int \frac {x^2}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx-39 \int \frac {x}{\left (7 x^2+2 x^3-\log (x)\right )^2} \, dx \\ \end{align*}
Time = 0.44 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.25 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=-\frac {x^2 \left (1-x+2 x^2\right )}{(-1+x) \left (-7 x^2-2 x^3+\log (x)\right )} \]
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Time = 0.78 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.32
method | result | size |
default | \(-\frac {2 x^{4}-x^{3}+x^{2}}{\left (-1+x \right ) \left (-2 x^{3}-7 x^{2}+\ln \left (x \right )\right )}\) | \(37\) |
risch | \(\frac {\left (2 x^{2}-x +1\right ) x^{2}}{\left (-1+x \right ) \left (2 x^{3}+7 x^{2}-\ln \left (x \right )\right )}\) | \(37\) |
parallelrisch | \(\frac {2 x^{4}-x^{3}+x^{2}}{2 x^{4}+5 x^{3}-7 x^{2}-x \ln \left (x \right )+\ln \left (x \right )}\) | \(41\) |
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Time = 0.27 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.43 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\frac {2 \, x^{4} - x^{3} + x^{2}}{2 \, x^{4} + 5 \, x^{3} - 7 \, x^{2} - {\left (x - 1\right )} \log \left (x\right )} \]
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Time = 0.07 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\frac {- 2 x^{4} + x^{3} - x^{2}}{- 2 x^{4} - 5 x^{3} + 7 x^{2} + \left (x - 1\right ) \log {\left (x \right )}} \]
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Time = 0.21 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.43 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\frac {2 \, x^{4} - x^{3} + x^{2}}{2 \, x^{4} + 5 \, x^{3} - 7 \, x^{2} - {\left (x - 1\right )} \log \left (x\right )} \]
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Time = 0.27 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.43 \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\frac {2 \, x^{4} - x^{3} + x^{2}}{2 \, x^{4} + 5 \, x^{3} - 7 \, x^{2} - x \log \left (x\right ) + \log \left (x\right )} \]
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Timed out. \[ \int \frac {-x+2 x^2-3 x^3+4 x^4-32 x^5+12 x^6+\left (2 x-4 x^2+10 x^3-6 x^4\right ) \log (x)}{49 x^4-70 x^5-3 x^6+20 x^7+4 x^8+\left (-14 x^2+24 x^3-6 x^4-4 x^5\right ) \log (x)+\left (1-2 x+x^2\right ) \log ^2(x)} \, dx=\int \frac {\ln \left (x\right )\,\left (-6\,x^4+10\,x^3-4\,x^2+2\,x\right )-x+2\,x^2-3\,x^3+4\,x^4-32\,x^5+12\,x^6}{{\ln \left (x\right )}^2\,\left (x^2-2\,x+1\right )-\ln \left (x\right )\,\left (4\,x^5+6\,x^4-24\,x^3+14\,x^2\right )+49\,x^4-70\,x^5-3\,x^6+20\,x^7+4\,x^8} \,d x \]
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