Integrand size = 103, antiderivative size = 29 \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\log ^4\left (e^{-x+\frac {-1+x+2 \log (5)}{2 x}}-16 x^4\right ) \]
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Time = 0.34 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.17, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.010, Rules used = {6818} \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\log ^4\left (5^{\frac {1}{x}} e^{-\frac {2 x^2-x+1}{2 x}}-16 x^4\right ) \]
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Rule 6818
Rubi steps \begin{align*} \text {integral}& = \log ^4\left (5^{\frac {1}{x}} e^{-\frac {1-x+2 x^2}{2 x}}-16 x^4\right ) \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\log ^4\left (e^{\frac {-1+x-2 x^2+\log (25)}{2 x}}-16 x^4\right ) \]
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Time = 3.47 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.17
method | result | size |
risch | \(\ln \left (5^{\frac {1}{x}} {\mathrm e}^{-\frac {2 x^{2}-x +1}{2 x}}-16 x^{4}\right )^{4}-\frac {3}{2}\) | \(34\) |
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none
Time = 0.32 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\log \left (-16 \, x^{4} + e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )^{4} \]
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Time = 0.25 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.83 \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\log {\left (- 16 x^{4} + e^{\frac {- x^{2} + \frac {x}{2} - \frac {1}{2} + \log {\left (5 \right )}}{x}} \right )}^{4} \]
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Leaf count of result is larger than twice the leaf count of optimal. 574 vs. \(2 (26) = 52\).
Time = 0.49 (sec) , antiderivative size = 574, normalized size of antiderivative = 19.79 \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=-2 \, {\left (\frac {2 \, x^{2} + 1}{x} - 2 \, \log \left (-{\left (16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} - e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )} e^{\left (-\frac {1}{2}\right )}\right )\right )} \log \left (-16 \, x^{4} + e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )^{3} - \frac {3 \, {\left (4 \, x^{4} + 4 \, x^{2} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{2} + 4 \, x^{3} - 4 \, {\left (2 \, x^{3} + x^{2} + x\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right ) + 2 \, x + 1\right )} \log \left (-16 \, x^{4} + e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )^{2}}{2 \, x^{2}} - \frac {{\left (8 \, x^{6} - 8 \, x^{3} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{3} + 12 \, x^{5} - 12 \, x^{4} + 12 \, {\left (2 \, x^{4} + x^{3} + x^{2}\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{2} - 6 \, x^{2} - 6 \, {\left (4 \, x^{5} + 4 \, x^{4} + 2 \, x^{2} + x\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right ) + 3 \, x + 1\right )} \log \left (-16 \, x^{4} + e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )}{2 \, x^{3}} - \frac {16 \, x^{8} + 16 \, x^{4} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{4} + 32 \, x^{7} - 64 \, x^{6} - 48 \, x^{5} - 32 \, {\left (2 \, x^{5} + x^{4} + x^{3}\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{3} - 24 \, x^{3} + 24 \, {\left (4 \, x^{6} + 4 \, x^{5} + 2 \, x^{3} + x^{2}\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right )^{2} - 16 \, x^{2} - 8 \, {\left (8 \, x^{7} + 12 \, x^{6} - 12 \, x^{5} - 6 \, x^{3} + 3 \, x^{2} + x\right )} \log \left (-16 \, x^{4} e^{\left (x + \frac {1}{2 \, x}\right )} + e^{\left (\frac {\log \left (5\right )}{x} + \frac {1}{2}\right )}\right ) + 4 \, x + 1}{16 \, x^{4}} \]
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\[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\int { \frac {2 \, {\left (128 \, x^{5} + {\left (2 \, x^{2} + 2 \, \log \left (5\right ) - 1\right )} e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )} \log \left (-16 \, x^{4} + e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}\right )^{3}}{16 \, x^{6} - x^{2} e^{\left (-\frac {2 \, x^{2} - x - 2 \, \log \left (5\right ) + 1}{2 \, x}\right )}} \,d x } \]
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Timed out. \[ \int \frac {\left (-256 x^5+e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} \left (2-4 x^2-4 \log (5)\right )\right ) \log ^3\left (e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}}-16 x^4\right )}{e^{\frac {-1+x-2 x^2+2 \log (5)}{2 x}} x^2-16 x^6} \, dx=\int -\frac {{\ln \left ({\mathrm {e}}^{\frac {-x^2+\frac {x}{2}+\ln \left (5\right )-\frac {1}{2}}{x}}-16\,x^4\right )}^3\,\left ({\mathrm {e}}^{\frac {-x^2+\frac {x}{2}+\ln \left (5\right )-\frac {1}{2}}{x}}\,\left (4\,x^2+4\,\ln \left (5\right )-2\right )+256\,x^5\right )}{x^2\,{\mathrm {e}}^{\frac {-x^2+\frac {x}{2}+\ln \left (5\right )-\frac {1}{2}}{x}}-16\,x^6} \,d x \]
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