Integrand size = 46, antiderivative size = 28 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=x+x^2 \left (x+\frac {3 (2+x)}{x}+\frac {\log (2)}{5}\right )^2 \log ^2(9) \]
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Leaf count is larger than twice the leaf count of optimal. \(80\) vs. \(2(28)=56\).
Time = 0.02 (sec) , antiderivative size = 80, normalized size of antiderivative = 2.86, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {12, 6} \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=x^4 \log ^2(9)+\frac {2}{5} x^3 \log (2) \log ^2(9)+6 x^3 \log ^2(9)+\frac {1}{25} x^2 \left (525+\log ^2(2)\right ) \log ^2(9)+\frac {6}{5} x^2 \log (2) \log ^2(9)+x+\frac {12}{5} x \log (2) \log ^2(9)+36 x \log ^2(9) \]
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Rule 6
Rule 12
Rubi steps \begin{align*} \text {integral}& = \frac {1}{25} \int \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx \\ & = x+\frac {1}{25} \log ^2(9) \int \left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \, dx \\ & = x+\frac {1}{25} \log ^2(9) \int \left (900+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+x \left (1050+2 \log ^2(2)\right )\right ) \, dx \\ & = x+36 x \log ^2(9)+6 x^3 \log ^2(9)+x^4 \log ^2(9)+\frac {1}{25} x^2 \left (525+\log ^2(2)\right ) \log ^2(9)+\frac {1}{25} \left (\log (2) \log ^2(9)\right ) \int \left (60+60 x+30 x^2\right ) \, dx \\ & = x+36 x \log ^2(9)+6 x^3 \log ^2(9)+x^4 \log ^2(9)+\frac {12}{5} x \log (2) \log ^2(9)+\frac {6}{5} x^2 \log (2) \log ^2(9)+\frac {2}{5} x^3 \log (2) \log ^2(9)+\frac {1}{25} x^2 \left (525+\log ^2(2)\right ) \log ^2(9) \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(59\) vs. \(2(28)=56\).
Time = 0.03 (sec) , antiderivative size = 59, normalized size of antiderivative = 2.11 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=x+x^4 \log ^2(9)+\frac {12}{5} x (15+\log (2)) \log ^2(9)+\frac {2}{5} x^3 (15+\log (2)) \log ^2(9)+\frac {1}{25} x^2 \left (525+30 \log (2)+\log ^2(2)\right ) \log ^2(9) \]
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Time = 0.10 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.96
method | result | size |
parallelrisch | \(\frac {4 \ln \left (3\right )^{2} \left (x^{2} \ln \left (2\right )^{2}+10 x^{3} \ln \left (2\right )+25 x^{4}+30 x^{2} \ln \left (2\right )+150 x^{3}+60 x \ln \left (2\right )+525 x^{2}+900 x \right )}{25}+x\) | \(55\) |
gosper | \(\frac {x \left (4 \ln \left (2\right )^{2} \ln \left (3\right )^{2} x +40 \ln \left (2\right ) \ln \left (3\right )^{2} x^{2}+100 x^{3} \ln \left (3\right )^{2}+120 x \ln \left (2\right ) \ln \left (3\right )^{2}+600 x^{2} \ln \left (3\right )^{2}+240 \ln \left (2\right ) \ln \left (3\right )^{2}+2100 x \ln \left (3\right )^{2}+3600 \ln \left (3\right )^{2}+25\right )}{25}\) | \(76\) |
norman | \(\left (\frac {8 \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+24 \ln \left (3\right )^{2}\right ) x^{3}+\left (\frac {48 \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+144 \ln \left (3\right )^{2}+1\right ) x +\left (\frac {4 \ln \left (3\right )^{2} \ln \left (2\right )^{2}}{25}+\frac {24 \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+84 \ln \left (3\right )^{2}\right ) x^{2}+4 x^{4} \ln \left (3\right )^{2}\) | \(77\) |
default | \(\frac {4 x^{2} \ln \left (3\right )^{2} \ln \left (2\right )^{2}}{25}+\frac {8 \ln \left (2\right ) \ln \left (3\right )^{2} x^{3}}{5}+4 x^{4} \ln \left (3\right )^{2}+\frac {24 \ln \left (2\right ) \ln \left (3\right )^{2} x^{2}}{5}+24 x^{3} \ln \left (3\right )^{2}+\frac {48 x \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+84 x^{2} \ln \left (3\right )^{2}+144 x \ln \left (3\right )^{2}+x\) | \(81\) |
parts | \(\frac {4 x^{2} \ln \left (3\right )^{2} \ln \left (2\right )^{2}}{25}+\frac {8 \ln \left (2\right ) \ln \left (3\right )^{2} x^{3}}{5}+4 x^{4} \ln \left (3\right )^{2}+\frac {24 \ln \left (2\right ) \ln \left (3\right )^{2} x^{2}}{5}+24 x^{3} \ln \left (3\right )^{2}+\frac {48 x \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+84 x^{2} \ln \left (3\right )^{2}+144 x \ln \left (3\right )^{2}+x\) | \(81\) |
risch | \(\frac {4 x^{2} \ln \left (3\right )^{2} \ln \left (2\right )^{2}}{25}+\frac {8 \ln \left (2\right ) \ln \left (3\right )^{2} x^{3}}{5}+4 x^{4} \ln \left (3\right )^{2}+\frac {24 \ln \left (2\right ) \ln \left (3\right )^{2} x^{2}}{5}+24 x^{3} \ln \left (3\right )^{2}+\frac {48 x \ln \left (2\right ) \ln \left (3\right )^{2}}{5}+84 x^{2} \ln \left (3\right )^{2}+144 x \ln \left (3\right )^{2}+144 \ln \left (3\right )^{2}+x\) | \(87\) |
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Time = 0.27 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.82 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=\frac {4}{25} \, {\left (25 \, x^{4} + x^{2} \log \left (2\right )^{2} + 150 \, x^{3} + 525 \, x^{2} + 10 \, {\left (x^{3} + 3 \, x^{2} + 6 \, x\right )} \log \left (2\right ) + 900 \, x\right )} \log \left (3\right )^{2} + x \]
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Leaf count of result is larger than twice the leaf count of optimal. 88 vs. \(2 (26) = 52\).
Time = 0.03 (sec) , antiderivative size = 88, normalized size of antiderivative = 3.14 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=4 x^{4} \log {\left (3 \right )}^{2} + x^{3} \cdot \left (\frac {8 \log {\left (2 \right )} \log {\left (3 \right )}^{2}}{5} + 24 \log {\left (3 \right )}^{2}\right ) + x^{2} \cdot \left (\frac {4 \log {\left (2 \right )}^{2} \log {\left (3 \right )}^{2}}{25} + \frac {24 \log {\left (2 \right )} \log {\left (3 \right )}^{2}}{5} + 84 \log {\left (3 \right )}^{2}\right ) + x \left (1 + \frac {48 \log {\left (2 \right )} \log {\left (3 \right )}^{2}}{5} + 144 \log {\left (3 \right )}^{2}\right ) \]
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Time = 0.22 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.82 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=\frac {4}{25} \, {\left (25 \, x^{4} + x^{2} \log \left (2\right )^{2} + 150 \, x^{3} + 525 \, x^{2} + 10 \, {\left (x^{3} + 3 \, x^{2} + 6 \, x\right )} \log \left (2\right ) + 900 \, x\right )} \log \left (3\right )^{2} + x \]
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Time = 0.27 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.82 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=\frac {4}{25} \, {\left (25 \, x^{4} + x^{2} \log \left (2\right )^{2} + 150 \, x^{3} + 525 \, x^{2} + 10 \, {\left (x^{3} + 3 \, x^{2} + 6 \, x\right )} \log \left (2\right ) + 900 \, x\right )} \log \left (3\right )^{2} + x \]
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Time = 0.08 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.21 \[ \int \frac {1}{25} \left (25+\left (900+1050 x+450 x^2+100 x^3+\left (60+60 x+30 x^2\right ) \log (2)+2 x \log ^2(2)\right ) \log ^2(9)\right ) \, dx=4\,{\ln \left (3\right )}^2\,x^4+\frac {4\,{\ln \left (3\right )}^2\,\left (30\,\ln \left (2\right )+450\right )\,x^3}{75}+\frac {2\,{\ln \left (3\right )}^2\,\left (60\,\ln \left (2\right )+2\,{\ln \left (2\right )}^2+1050\right )\,x^2}{25}+\left (\frac {4\,{\ln \left (3\right )}^2\,\left (60\,\ln \left (2\right )+900\right )}{25}+1\right )\,x \]
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