Integrand size = 212, antiderivative size = 30 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {4}{x \left (e+\frac {1+x}{4}-\log \left (-x+e^{x^2} x\right )\right )} \]
[Out]
Time = 0.58 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.93, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.019, Rules used = {6, 6820, 12, 6819} \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {16}{x \left (-4 \log \left (-\left (\left (1-e^{x^2}\right ) x\right )\right )+x+4 e+1\right )} \]
[In]
[Out]
Rule 6
Rule 12
Rule 6819
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{\left (-1-16 e^2\right ) x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx \\ & = \int \frac {16 \left (3 \left (1-\frac {4 e}{3}\right )+4 e^{1+x^2}-2 x-e^{x^2} \left (3-2 x+8 x^2\right )-4 \left (-1+e^{x^2}\right ) \log \left (\left (-1+e^{x^2}\right ) x\right )\right )}{\left (1-e^{x^2}\right ) x^2 \left (1+4 e+x-4 \log \left (\left (-1+e^{x^2}\right ) x\right )\right )^2} \, dx \\ & = 16 \int \frac {3 \left (1-\frac {4 e}{3}\right )+4 e^{1+x^2}-2 x-e^{x^2} \left (3-2 x+8 x^2\right )-4 \left (-1+e^{x^2}\right ) \log \left (\left (-1+e^{x^2}\right ) x\right )}{\left (1-e^{x^2}\right ) x^2 \left (1+4 e+x-4 \log \left (\left (-1+e^{x^2}\right ) x\right )\right )^2} \, dx \\ & = \frac {16}{x \left (1+4 e+x-4 \log \left (-\left (\left (1-e^{x^2}\right ) x\right )\right )\right )} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {16}{x+4 e x+x^2-4 x \log \left (\left (-1+e^{x^2}\right ) x\right )} \]
[In]
[Out]
Time = 1.50 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87
method | result | size |
parallelrisch | \(\frac {16}{x \left (-4 \ln \left (\left ({\mathrm e}^{x^{2}}-1\right ) x \right )+1+4 \,{\mathrm e}+x \right )}\) | \(26\) |
risch | \(\frac {16 i}{x \left (2 \pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{x^{2}}-1\right )\right ) {\operatorname {csgn}\left (i x \left ({\mathrm e}^{x^{2}}-1\right )\right )}^{2}-2 \pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{x^{2}}-1\right )\right ) \operatorname {csgn}\left (i x \left ({\mathrm e}^{x^{2}}-1\right )\right ) \operatorname {csgn}\left (i x \right )-2 \pi {\operatorname {csgn}\left (i x \left ({\mathrm e}^{x^{2}}-1\right )\right )}^{3}+2 \pi {\operatorname {csgn}\left (i x \left ({\mathrm e}^{x^{2}}-1\right )\right )}^{2} \operatorname {csgn}\left (i x \right )+4 i {\mathrm e}+i x -4 i \ln \left (x \right )-4 i \ln \left ({\mathrm e}^{x^{2}}-1\right )+i\right )}\) | \(128\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.93 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {16}{x^{2} + 4 \, x e - 4 \, x \log \left (x e^{\left (x^{2}\right )} - x\right ) + x} \]
[In]
[Out]
Time = 0.16 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.90 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=- \frac {16}{- x^{2} + 4 x \log {\left (x e^{x^{2}} - x \right )} - 4 e x - x} \]
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.03 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {16}{x^{2} + x {\left (4 \, e + 1\right )} - 4 \, x \log \left (x\right ) - 4 \, x \log \left (e^{\left (x^{2}\right )} - 1\right )} \]
[In]
[Out]
none
Time = 0.42 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.93 \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=\frac {16}{x^{2} + 4 \, x e - 4 \, x \log \left (x e^{\left (x^{2}\right )} - x\right ) + x} \]
[In]
[Out]
Timed out. \[ \int \frac {-48+64 e+32 x+e^{x^2} \left (48-64 e-32 x+128 x^2\right )+\left (-64+64 e^{x^2}\right ) \log \left (-x+e^{x^2} x\right )}{-x^2-16 e^2 x^2-2 x^3-x^4+e \left (-8 x^2-8 x^3\right )+e^{x^2} \left (x^2+16 e^2 x^2+2 x^3+x^4+e \left (8 x^2+8 x^3\right )\right )+\left (8 x^2+32 e x^2+8 x^3+e^{x^2} \left (-8 x^2-32 e x^2-8 x^3\right )\right ) \log \left (-x+e^{x^2} x\right )+\left (-16 x^2+16 e^{x^2} x^2\right ) \log ^2\left (-x+e^{x^2} x\right )} \, dx=-\int \frac {32\,x+64\,\mathrm {e}+\ln \left (x\,{\mathrm {e}}^{x^2}-x\right )\,\left (64\,{\mathrm {e}}^{x^2}-64\right )-{\mathrm {e}}^{x^2}\,\left (-128\,x^2+32\,x+64\,\mathrm {e}-48\right )-48}{\mathrm {e}\,\left (8\,x^3+8\,x^2\right )-{\ln \left (x\,{\mathrm {e}}^{x^2}-x\right )}^2\,\left (16\,x^2\,{\mathrm {e}}^{x^2}-16\,x^2\right )-\ln \left (x\,{\mathrm {e}}^{x^2}-x\right )\,\left (32\,x^2\,\mathrm {e}-{\mathrm {e}}^{x^2}\,\left (32\,x^2\,\mathrm {e}+8\,x^2+8\,x^3\right )+8\,x^2+8\,x^3\right )-{\mathrm {e}}^{x^2}\,\left (\mathrm {e}\,\left (8\,x^3+8\,x^2\right )+16\,x^2\,{\mathrm {e}}^2+x^2+2\,x^3+x^4\right )+16\,x^2\,{\mathrm {e}}^2+x^2+2\,x^3+x^4} \,d x \]
[In]
[Out]