Integrand size = 71, antiderivative size = 17 \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=x^{5+e^{e^{e^{16 e^{-x}}}}} \]
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\[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=\int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (5 x^{4+e^{e^{e^{16 e^{-x}}}}}+e^{e^{e^{16 e^{-x}}}-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx \\ & = 5 \int x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx+\int e^{e^{e^{16 e^{-x}}}-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right ) \, dx \\ & = 5 \int x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx+\int \left (e^{e^{e^{16 e^{-x}}}} x^{4+e^{e^{e^{16 e^{-x}}}}}-16 \exp \left (e^{e^{16 e^{-x}}}+e^{-x} \left (16+e^{16 e^{-x}+x}\right )-x\right ) x^{5+e^{e^{e^{16 e^{-x}}}}} \log (x)\right ) \, dx \\ & = 5 \int x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx-16 \int \exp \left (e^{e^{16 e^{-x}}}+e^{-x} \left (16+e^{16 e^{-x}+x}\right )-x\right ) x^{5+e^{e^{e^{16 e^{-x}}}}} \log (x) \, dx+\int e^{e^{e^{16 e^{-x}}}} x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx \\ & = 5 \int x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx+16 \int \frac {\int e^{e^{e^{16 e^{-x}}}+e^{16 e^{-x}}+16 e^{-x}-x} x^{5+e^{e^{e^{16 e^{-x}}}}} \, dx}{x} \, dx-(16 \log (x)) \int \exp \left (e^{e^{16 e^{-x}}}+e^{-x} \left (16+e^{16 e^{-x}+x}\right )-x\right ) x^{5+e^{e^{e^{16 e^{-x}}}}} \, dx+\int e^{e^{e^{16 e^{-x}}}} x^{4+e^{e^{e^{16 e^{-x}}}}} \, dx \\ \end{align*}
Time = 0.72 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=x^{5+e^{e^{e^{16 e^{-x}}}}} \]
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Time = 0.07 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.94
\[x^{{\mathrm e}^{{\mathrm e}^{{\mathrm e}^{16 \,{\mathrm e}^{-x}}}}} x^{5}\]
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Leaf count of result is larger than twice the leaf count of optimal. 34 vs. \(2 (13) = 26\).
Time = 0.27 (sec) , antiderivative size = 34, normalized size of antiderivative = 2.00 \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=e^{\left (e^{\left (e^{\left ({\left (e^{\left (x + 16 \, e^{\left (-x\right )}\right )} + 16\right )} e^{\left (-x\right )} - 16 \, e^{\left (-x\right )}\right )}\right )} \log \left (x\right ) + 5 \, \log \left (x\right )\right )} \]
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Timed out. \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=\text {Timed out} \]
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none
Time = 0.43 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=x^{5} x^{e^{\left (e^{\left (e^{\left (16 \, e^{\left (-x\right )}\right )}\right )}\right )}} \]
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\[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=\int { -\frac {{\left ({\left (16 \, x e^{\left (16 \, e^{\left (-x\right )} + e^{\left (16 \, e^{\left (-x\right )}\right )}\right )} \log \left (x\right ) - e^{x}\right )} e^{\left (e^{\left (e^{\left (16 \, e^{\left (-x\right )}\right )}\right )}\right )} - 5 \, e^{x}\right )} e^{\left (e^{\left (e^{\left (e^{\left (16 \, e^{\left (-x\right )}\right )}\right )}\right )} \log \left (x\right ) - x + 5 \, \log \left (x\right )\right )}}{x} \,d x } \]
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Time = 13.59 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int e^{-x} x^{4+e^{e^{e^{16 e^{-x}}}}} \left (5 e^x+e^{e^{e^{16 e^{-x}}}} \left (e^x-16 e^{e^{16 e^{-x}}+16 e^{-x}} x \log (x)\right )\right ) \, dx=x^{{\mathrm {e}}^{{\mathrm {e}}^{{\mathrm {e}}^{16\,{\mathrm {e}}^{-x}}}}}\,x^5 \]
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