Integrand size = 125, antiderivative size = 33 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\log \left (6-\log (x)+\frac {e^{-2 x} \left (1-\frac {x+\log (x)}{x}\right )^2}{x^2}\right )}{x} \]
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\[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\log (x) \left (12-25 \log (x)-12 x \log (x)+4 \log ^2(x)+2 x \log ^2(x)\right )}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}+\frac {1+6 \log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )-\log (x) \log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2 (-6+\log (x))}\right ) \, dx \\ & = \int \frac {\log (x) \left (12-25 \log (x)-12 x \log (x)+4 \log ^2(x)+2 x \log ^2(x)\right )}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+\int \frac {1+6 \log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )-\log (x) \log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2 (-6+\log (x))} \, dx \\ & = \int \left (\frac {12 \log (x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}-\frac {25 \log ^2(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}-\frac {12 \log ^2(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}+\frac {4 \log ^3(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}+\frac {2 \log ^3(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )}\right ) \, dx+\int \frac {\frac {1}{-6+\log (x)}-\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2} \, dx \\ & = 2 \int \frac {\log ^3(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+4 \int \frac {\log ^3(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+12 \int \frac {\log (x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-12 \int \frac {\log ^2(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-25 \int \frac {\log ^2(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+\int \left (\frac {1}{x^2 (-6+\log (x))}-\frac {\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2}\right ) \, dx \\ & = 2 \int \frac {\log ^3(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+4 \int \frac {\log ^3(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+12 \int \frac {\log (x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-12 \int \frac {\log ^2(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-25 \int \frac {\log ^2(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+\int \frac {1}{x^2 (-6+\log (x))} \, dx-\int \frac {\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2} \, dx \\ & = 2 \int \frac {\log ^3(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+4 \int \frac {\log ^3(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+12 \int \frac {\log (x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-12 \int \frac {\log ^2(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-25 \int \frac {\log ^2(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-\int \frac {\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2} \, dx+\text {Subst}\left (\int \frac {e^{-x}}{-6+x} \, dx,x,\log (x)\right ) \\ & = \frac {\operatorname {ExpIntegralEi}(6-\log (x))}{e^6}+2 \int \frac {\log ^3(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+4 \int \frac {\log ^3(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx+12 \int \frac {\log (x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-12 \int \frac {\log ^2(x)}{x (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-25 \int \frac {\log ^2(x)}{x^2 (-6+\log (x)) \left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right )} \, dx-\int \frac {\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x^2} \, dx \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=2+\frac {\log \left (6-\log (x)+\frac {e^{-2 x} \log ^2(x)}{x^4}\right )}{x} \]
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Time = 96.03 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.18
method | result | size |
parallelrisch | \(\frac {\ln \left (\frac {\left (\ln \left (x \right )^{2}-x^{4} {\mathrm e}^{2 x} \ln \left (x \right )+6 \,{\mathrm e}^{2 x} x^{4}\right ) {\mathrm e}^{-2 x}}{x^{4}}\right )}{x}\) | \(39\) |
risch | \(\text {Expression too large to display}\) | \(722\) |
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Time = 0.26 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.21 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\log \left (-\frac {{\left (x^{4} e^{\left (2 \, x\right )} \log \left (x\right ) - 6 \, x^{4} e^{\left (2 \, x\right )} - \log \left (x\right )^{2}\right )} e^{\left (-2 \, x\right )}}{x^{4}}\right )}{x} \]
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Time = 0.53 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.12 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\log {\left (\frac {\left (- x^{4} e^{2 x} \log {\left (x \right )} + 6 x^{4} e^{2 x} + \log {\left (x \right )}^{2}\right ) e^{- 2 x}}{x^{4}} \right )}}{x} \]
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Time = 0.24 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.06 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\log \left (-x^{4} e^{\left (2 \, x\right )} \log \left (x\right ) + 6 \, x^{4} e^{\left (2 \, x\right )} + \log \left (x\right )^{2}\right ) - 4 \, \log \left (x\right )}{x} \]
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Time = 0.38 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.27 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\log \left (-{\left (x^{4} e^{\left (2 \, x\right )} \log \left (x\right ) - 6 \, x^{4} e^{\left (2 \, x\right )} - \log \left (x\right )^{2}\right )} e^{\left (-2 \, x\right )}\right ) - 4 \, \log \left (x\right )}{x} \]
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Time = 13.08 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.97 \[ \int \frac {-e^{2 x} x^4+2 \log (x)+(-4-2 x) \log ^2(x)+\left (-6 e^{2 x} x^4+e^{2 x} x^4 \log (x)-\log ^2(x)\right ) \log \left (\frac {e^{-2 x} \left (6 e^{2 x} x^4-e^{2 x} x^4 \log (x)+\log ^2(x)\right )}{x^4}\right )}{6 e^{2 x} x^6-e^{2 x} x^6 \log (x)+x^2 \log ^2(x)} \, dx=\frac {\ln \left (\frac {1}{x^4}\right )+\ln \left (6\,x^4-x^4\,\ln \left (x\right )+{\mathrm {e}}^{-2\,x}\,{\ln \left (x\right )}^2\right )}{x} \]
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