Integrand size = 92, antiderivative size = 26 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=\log \left (\frac {1}{4 \left (-3+\left (-4 x+\frac {x}{e^3}+\log \left (5 e^x\right )\right )^2\right )}\right ) \]
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\[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=\int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-24 e^6 x+\left (-2+14 e^3\right ) x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \\ & = \int \frac {\left (-2+14 e^3-24 e^6\right ) x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \\ & = \int \frac {\left (-2+14 e^3-24 e^6\right ) x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{\left (1-8 e^3\right ) x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \\ & = \int \frac {2 \left (1-3 e^3\right ) \left (-\left (\left (1-4 e^3\right ) x\right )-e^3 \log \left (5 e^x\right )\right )}{\left (1-8 e^3\right ) x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \\ & = \left (2 \left (1-3 e^3\right )\right ) \int \frac {-\left (\left (1-4 e^3\right ) x\right )-e^3 \log \left (5 e^x\right )}{\left (1-8 e^3\right ) x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx \\ & = \left (2 \left (1-3 e^3\right )\right ) \int \left (\frac {\left (1-4 e^3\right ) x}{3 e^6-\left (1+8 e^3 \left (-1+2 e^3\right )\right ) x^2-2 e^3 \left (1-4 e^3\right ) x \log \left (5 e^x\right )-e^6 \log ^2\left (5 e^x\right )}+\frac {e^3 \log \left (5 e^x\right )}{3 e^6-\left (1+8 e^3 \left (-1+2 e^3\right )\right ) x^2-2 e^3 \left (1-4 e^3\right ) x \log \left (5 e^x\right )-e^6 \log ^2\left (5 e^x\right )}\right ) \, dx \\ & = \left (2 e^3 \left (1-3 e^3\right )\right ) \int \frac {\log \left (5 e^x\right )}{3 e^6-\left (1+8 e^3 \left (-1+2 e^3\right )\right ) x^2-2 e^3 \left (1-4 e^3\right ) x \log \left (5 e^x\right )-e^6 \log ^2\left (5 e^x\right )} \, dx+\left (2 \left (1-4 e^3\right ) \left (1-3 e^3\right )\right ) \int \frac {x}{3 e^6-\left (1+8 e^3 \left (-1+2 e^3\right )\right ) x^2-2 e^3 \left (1-4 e^3\right ) x \log \left (5 e^x\right )-e^6 \log ^2\left (5 e^x\right )} \, dx \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(74\) vs. \(2(26)=52\).
Time = 0.51 (sec) , antiderivative size = 74, normalized size of antiderivative = 2.85 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=-\frac {2 \left (-1+3 e^3\right ) \log \left (x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )\right )}{-2+6 e^3} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(63\) vs. \(2(24)=48\).
Time = 0.43 (sec) , antiderivative size = 64, normalized size of antiderivative = 2.46
method | result | size |
norman | \(-\ln \left ({\mathrm e}^{6} \ln \left (5 \,{\mathrm e}^{x}\right )^{2}-8 \ln \left (5 \,{\mathrm e}^{x}\right ) x \,{\mathrm e}^{6}+16 x^{2} {\mathrm e}^{6}+2 \ln \left (5 \,{\mathrm e}^{x}\right ) x \,{\mathrm e}^{3}-8 x^{2} {\mathrm e}^{3}-3 \,{\mathrm e}^{6}+x^{2}\right )\) | \(64\) |
risch | \(-\ln \left (\ln \left (5\right )^{2}+2 \ln \left ({\mathrm e}^{x}\right ) \ln \left (5\right )+2 x \ln \left (5\right ) {\mathrm e}^{-3}-8 x \ln \left (5\right )-8 x \ln \left ({\mathrm e}^{x}\right )-8 \,{\mathrm e}^{-3} x^{2}+16 x^{2}+2 \ln \left ({\mathrm e}^{x}\right ) {\mathrm e}^{-3} x +{\mathrm e}^{-6} x^{2}+\ln \left ({\mathrm e}^{x}\right )^{2}-3\right )\) | \(66\) |
parallelrisch | \(-\ln \left (\frac {{\mathrm e}^{6} \ln \left (5 \,{\mathrm e}^{x}\right )^{2}-8 \ln \left (5 \,{\mathrm e}^{x}\right ) x \,{\mathrm e}^{6}+16 x^{2} {\mathrm e}^{6}+2 \ln \left (5 \,{\mathrm e}^{x}\right ) x \,{\mathrm e}^{3}-8 x^{2} {\mathrm e}^{3}-3 \,{\mathrm e}^{6}+x^{2}}{16 \,{\mathrm e}^{6}-8 \,{\mathrm e}^{3}+1}\right )\) | \(79\) |
default | \(-\frac {\left (-2+6 \,{\mathrm e}^{3}\right ) \ln \left (9 x^{2} {\mathrm e}^{6}-6 \,{\mathrm e}^{6} x \left (\ln \left (5 \,{\mathrm e}^{x}\right )-x \right )+{\mathrm e}^{6} {\left (\ln \left (5 \,{\mathrm e}^{x}\right )-x \right )}^{2}-6 x^{2} {\mathrm e}^{3}+2 \,{\mathrm e}^{3} x \left (\ln \left (5 \,{\mathrm e}^{x}\right )-x \right )-3 \,{\mathrm e}^{6}+x^{2}\right )}{2 \left (-1+3 \,{\mathrm e}^{3}\right )}\) | \(90\) |
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Leaf count of result is larger than twice the leaf count of optimal. 47 vs. \(2 (22) = 44\).
Time = 0.24 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.81 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=-\log \left (-6 \, x^{2} e^{3} + e^{6} \log \left (5\right )^{2} + x^{2} + 3 \, {\left (3 \, x^{2} - 1\right )} e^{6} - 2 \, {\left (3 \, x e^{6} - x e^{3}\right )} \log \left (5\right )\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 49 vs. \(2 (22) = 44\).
Time = 0.28 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.88 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=- \log {\left (x^{2} \left (- 6 e^{3} + 1 + 9 e^{6}\right ) + x \left (- 6 e^{6} \log {\left (5 \right )} + 2 e^{3} \log {\left (5 \right )}\right ) - 3 e^{6} + e^{6} \log {\left (5 \right )}^{2} \right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1021 vs. \(2 (22) = 44\).
Time = 0.34 (sec) , antiderivative size = 1021, normalized size of antiderivative = 39.27 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=\text {Too large to display} \]
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Leaf count of result is larger than twice the leaf count of optimal. 47 vs. \(2 (22) = 44\).
Time = 0.28 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.81 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=-\log \left ({\left | 9 \, x^{2} e^{6} - 6 \, x^{2} e^{3} - 6 \, x e^{6} \log \left (5\right ) + 2 \, x e^{3} \log \left (5\right ) + e^{6} \log \left (5\right )^{2} + x^{2} - 3 \, e^{6} \right |}\right ) \]
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Time = 18.21 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.85 \[ \int \frac {-2 x+14 e^3 x-24 e^6 x+\left (-2 e^3+6 e^6\right ) \log \left (5 e^x\right )}{x^2-8 e^3 x^2+e^6 \left (-3+16 x^2\right )+\left (2 e^3 x-8 e^6 x\right ) \log \left (5 e^x\right )+e^6 \log ^2\left (5 e^x\right )} \, dx=-\ln \left (3\,{\mathrm {e}}^6-{\mathrm {e}}^6\,{\ln \left (5\right )}^2+6\,x^2\,{\mathrm {e}}^3-9\,x^2\,{\mathrm {e}}^6-x^2+2\,x\,{\mathrm {e}}^3\,\ln \left (5\right )\,\left (3\,{\mathrm {e}}^3-1\right )\right ) \]
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