Integrand size = 103, antiderivative size = 36 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=-1+x \left (-x+\frac {5-x+\frac {x}{e^6-x^2}}{x}\right )+\frac {x}{\log (x)} \]
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Time = 0.17 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.78, number of steps used = 9, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.058, Rules used = {28, 6820, 1828, 1600, 2334, 2335} \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=-x^2+\frac {x}{e^6-x^2}-x+\frac {x}{\log (x)} \]
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Rule 28
Rule 1600
Rule 1828
Rule 2334
Rule 2335
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (-e^6+x^2\right )^2 \log ^2(x)} \, dx \\ & = \int \left (\frac {x^2-x^4-2 x^5-e^{12} (1+2 x)+e^6 \left (1+2 x^2+4 x^3\right )}{\left (e^6-x^2\right )^2}-\frac {1}{\log ^2(x)}+\frac {1}{\log (x)}\right ) \, dx \\ & = \int \frac {x^2-x^4-2 x^5-e^{12} (1+2 x)+e^6 \left (1+2 x^2+4 x^3\right )}{\left (e^6-x^2\right )^2} \, dx-\int \frac {1}{\log ^2(x)} \, dx+\int \frac {1}{\log (x)} \, dx \\ & = \frac {x}{e^6-x^2}+\frac {x}{\log (x)}+\operatorname {LogIntegral}(x)-\frac {\int \frac {2 e^{12}+4 e^{12} x-2 e^6 x^2-4 e^6 x^3}{e^6-x^2} \, dx}{2 e^6}-\int \frac {1}{\log (x)} \, dx \\ & = \frac {x}{e^6-x^2}+\frac {x}{\log (x)}-\frac {\int \left (2 e^6+4 e^6 x\right ) \, dx}{2 e^6} \\ & = -x-x^2+\frac {x}{e^6-x^2}+\frac {x}{\log (x)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.81 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=-x-x^2-\frac {x}{-e^6+x^2}+\frac {x}{\log (x)} \]
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Time = 0.32 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.78
method | result | size |
default | \(\frac {x}{\ln \left (x \right )}-x -x^{2}+\frac {x}{{\mathrm e}^{6}-x^{2}}\) | \(28\) |
parts | \(\frac {x}{\ln \left (x \right )}-x -x^{2}+\frac {x}{{\mathrm e}^{6}-x^{2}}\) | \(28\) |
risch | \(-\frac {x \left (-x^{3}+x \,{\mathrm e}^{6}-x^{2}+{\mathrm e}^{6}-1\right )}{{\mathrm e}^{6}-x^{2}}+\frac {x}{\ln \left (x \right )}\) | \(39\) |
norman | \(\frac {x \,{\mathrm e}^{6}+x^{3} \ln \left (x \right )+x^{4} \ln \left (x \right )-\ln \left (x \right ) {\mathrm e}^{12}+\left (-{\mathrm e}^{6}+1\right ) x \ln \left (x \right )-x^{3}}{\left ({\mathrm e}^{6}-x^{2}\right ) \ln \left (x \right )}\) | \(56\) |
parallelrisch | \(\frac {x^{4} \ln \left (x \right )+x^{3} \ln \left (x \right )-\ln \left (x \right ) {\mathrm e}^{12}-x \,{\mathrm e}^{6} \ln \left (x \right )-x^{3}+x \,{\mathrm e}^{6}+x \ln \left (x \right )}{\ln \left (x \right ) \left ({\mathrm e}^{6}-x^{2}\right )}\) | \(57\) |
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Time = 0.27 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.25 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=\frac {x^{3} - x e^{6} - {\left (x^{4} + x^{3} - {\left (x^{2} + x\right )} e^{6} + x\right )} \log \left (x\right )}{{\left (x^{2} - e^{6}\right )} \log \left (x\right )} \]
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Time = 0.10 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.47 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=- x^{2} - x + \frac {x}{\log {\left (x \right )}} - \frac {x}{x^{2} - e^{6}} \]
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Time = 0.26 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.36 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=\frac {x^{3} - x e^{6} - {\left (x^{4} + x^{3} - x^{2} e^{6} - x {\left (e^{6} - 1\right )}\right )} \log \left (x\right )}{{\left (x^{2} - e^{6}\right )} \log \left (x\right )} \]
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Time = 0.29 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.67 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=-\frac {x^{4} \log \left (x\right ) + x^{3} \log \left (x\right ) - x^{2} e^{6} \log \left (x\right ) - x^{3} - x e^{6} \log \left (x\right ) + x e^{6} + 2 \, x \log \left (x\right )}{x^{2} \log \left (x\right ) - e^{6} \log \left (x\right )} \]
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Time = 13.97 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.75 \[ \int \frac {-e^{12}+2 e^6 x^2-x^4+\left (e^{12}-2 e^6 x^2+x^4\right ) \log (x)+\left (e^{12} (-1-2 x)+x^2-x^4-2 x^5+e^6 \left (1+2 x^2+4 x^3\right )\right ) \log ^2(x)}{\left (e^{12}-2 e^6 x^2+x^4\right ) \log ^2(x)} \, dx=\frac {x}{\ln \left (x\right )}-x+\frac {x}{{\mathrm {e}}^6-x^2}-x^2 \]
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