Integrand size = 68, antiderivative size = 27 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=e^{\frac {1}{2} \left (e^x-4 e^{2 x \left (\frac {2}{3}+x\right )}+e^5 x\right )} \]
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Time = 0.19 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.19, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.029, Rules used = {12, 6838} \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=\exp \left (\frac {1}{2} \left (-4 e^{\frac {2}{3} \left (3 x^2+2 x\right )}+e^5 x+e^x\right )\right ) \]
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Rule 12
Rule 6838
Rubi steps \begin{align*} \text {integral}& = \frac {1}{6} \int \exp \left (\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )\right ) \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx \\ & = \exp \left (\frac {1}{2} \left (e^x-4 e^{\frac {2}{3} \left (2 x+3 x^2\right )}+e^5 x\right )\right ) \\ \end{align*}
Time = 1.50 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.07 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=e^{\frac {1}{2} \left (e^x-4 e^{\frac {2}{3} x (2+3 x)}+e^5 x\right )} \]
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Time = 0.71 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.85
method | result | size |
risch | \({\mathrm e}^{-2 \,{\mathrm e}^{\frac {2 x \left (2+3 x \right )}{3}}+\frac {{\mathrm e}^{x}}{2}+\frac {x \,{\mathrm e}^{5}}{2}}\) | \(23\) |
norman | \({\mathrm e}^{-2 \,{\mathrm e}^{2 x^{2}+\frac {4}{3} x}+\frac {{\mathrm e}^{x}}{2}+\frac {x \,{\mathrm e}^{5}}{2}}\) | \(26\) |
parallelrisch | \({\mathrm e}^{-2 \,{\mathrm e}^{2 x^{2}+\frac {4}{3} x}+\frac {{\mathrm e}^{x}}{2}+\frac {x \,{\mathrm e}^{5}}{2}}\) | \(26\) |
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Time = 0.26 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.85 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=e^{\left (\frac {1}{2} \, x e^{5} - 2 \, e^{\left (2 \, x^{2} + \frac {4}{3} \, x\right )} + \frac {1}{2} \, e^{x}\right )} \]
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Time = 0.18 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=e^{\frac {x e^{5}}{2} + \frac {e^{x}}{2} - 2 e^{2 x^{2} + \frac {4 x}{3}}} \]
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\[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=\int { -\frac {1}{6} \, {\left (16 \, {\left (3 \, x + 1\right )} e^{\left (2 \, x^{2} + \frac {4}{3} \, x\right )} - 3 \, e^{5} - 3 \, e^{x}\right )} e^{\left (\frac {1}{2} \, x e^{5} - 2 \, e^{\left (2 \, x^{2} + \frac {4}{3} \, x\right )} + \frac {1}{2} \, e^{x}\right )} \,d x } \]
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Time = 0.31 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.85 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx=e^{\left (\frac {1}{2} \, x e^{5} - 2 \, e^{\left (2 \, x^{2} + \frac {4}{3} \, x\right )} + \frac {1}{2} \, e^{x}\right )} \]
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Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.93 \[ \int \frac {1}{6} e^{\frac {1}{2} \left (e^x-4 e^{\frac {1}{3} \left (4 x+6 x^2\right )}+e^5 x\right )} \left (3 e^5+3 e^x+e^{\frac {1}{3} \left (4 x+6 x^2\right )} (-16-48 x)\right ) \, dx={\mathrm {e}}^{-2\,{\mathrm {e}}^{\frac {4\,x}{3}}\,{\mathrm {e}}^{2\,x^2}}\,{\mathrm {e}}^{\frac {{\mathrm {e}}^x}{2}}\,{\mathrm {e}}^{\frac {x\,{\mathrm {e}}^5}{2}} \]
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